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In Problems 1 and 2, use the definition of the Laplace transform to determine L{f}.

f(t)={e-t,0≤t≤5-1,5<t

Short Answer

Expert verified

L{f(t)}(s)=1s+1(1-e-5(s+1))-1se-5s

Step by step solution

01

Step 1:Given Information

The given function is f(t)={e-t,0≤t≤5-1,5<t.

02

Determining the

Using the Laplace transform definition, we get

L{f(t)}(s)=∫0∞e-stf(t)dt=∫05e−ste−tdt+∫5∞(−1)e−stdt=∫05e−t(s+1)dt−limN→∞∫5Ne−stdt

Simplify further as:

L{f(t)}=[−e−t(s+1)s+1]05−limN→∞[−e−sts]5N=1s+1(1−e−5(s+1))−limN→∞(1s(e−5s−e−Ns))=1s+1(1−e−5(s+1))−1se−5s

03

Determining the Result

Thus, the required Laplace transform isL{f(t)}(s)=1s+1(1-e-5(s+1))-1se-5s

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