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In Problems 15-24, solve for Y(s), the Laplace transform of the solution y(t) to the given initial value problem.

17.y''+y'-y=t3;y(0)=1,y'(0)=0

Short Answer

Expert verified

The Initial value fory''+y'-y=t3isY=s5+s4+6s4s2+s-1

Step by step solution

01

Determine the Laplace Transform

  • The Laplace transform is a strong integral transform used in mathematics to convert a function from the time domain to the s-domain.
  • In some circumstances, the Laplace transform can be utilized to solve linear differential equations with given beginning conditions.
  • Fs=∫0∞f(t)e-stt'
02

Determine the Laplace transform

Define Lys=Ys

Using the properties listed below, take the Laplace transform of the equation.

Ly's=sLys-y0Ly''s=s2Lys-sy0-y'0Ctns=n!sn+1Ly''+Ly'-Ly=Lt3

Substitute the properties into the equation.

s2Y-sy(0)-y'(0)+[sY-y(0)]-Y=3!s4

Substitute the initial conditions

y0=1andy'0=0s2Y-s+sY-1-Y=6s4

Isolate the Y variable and solve:

s2Y+sY-Y=6s4+s+1Ys2+s-1=s5+s4+6s4Y=s5+s4+6s4s2+s-1

Therefore, the initial value fory''+y'-y=t3isY=s5+s4+6s4s2+s-1

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