/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q2.3-8E Question: In Problems 7-16, obta... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Question: In Problems 7-16, obtain the general solution to the equation.

dydx=yx+2x+1

Short Answer

Expert verified

The general solution to the given equation is y=2x2+xlnx+Cx.

Step by step solution

01

Method for solving linear equations

  • Write the equation in the standard form dydx+P(x)y=Q(x).
  • Calculate the integrating factor by μ(x)the formula .
  • Multiply the equation in standard form by μ(x)and, recalling that the left-hand side is just ddx[μ(x)y], obtain

μ(x)dydx+Pμ(x)y=μ(x)Q(x)ddx[μ(x)y]=μ(x)Q(x)

  • Integrate the last equation and solve for y by dividing by μ(x)to obtainy(x)=1Ï€(x)[∫π(x)Q(x)+c] . Here C is an arbitrary constant.
02

Solve the given equation

Given that,

dydx=yx+2x+1.........1

Write the equation (1) into standard form of linear equation.

dydx=yx+2x+1dydx-yx=2x+1........2

Calculate the integrating factor of μx.

Where Px=-1x.

Then,

μx=e∫Pxdx=e∫-1xdx=e-lnx=1x

03

Simplification method

Multiply μxin equation (2)

1xdydx-1xyx=1x2x+11xdydx-yx2=2+1xddx1xy=2+1x

Integrating both sides.

∫ddx1xy=∫2+1xdxyx=2x+lnx+C

So, the solution is yx=2x+ln|x|+C.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.