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Question: In Problems 31-40, solve the initial value problem.

dydx-2yx=x2cosx,鈥夆赌夆赌夆赌y=2

Short Answer

Expert verified

The solution of the given equation is y=x2sinx+2x22.

Step by step solution

01

Given information and simplification

Given that, dydx-2yx=x2cosx,鈥夆赌夆赌夆赌y=21

Let Px=-2x.

Find the value ofx.

x=ePxdx=e-2xdx=e-2lnx=1x2

Multiply1x2 in equation (1) on both sides.

1x2dydx-2yx3=cosxdydx1x2y=cosx

02

integration method

Now integrate the equation on both sides.

dydx1x2ydx=cosxdx1x2y=sinx+C1y=x2sinx+x2C2

So, the solution is found.

03

Find the initial value

Given that, y=2.

Then,x= and y = 2.

Substitute the value in equation (2) to get the value of C.

y=x2sinx+x2C2=2sin+2C22=C

Substitute the value of C in equation (2).

y=x2sinx+2x22

So, the solution is y=x2sinx+2x22

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