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Question: In Problems 1-30, solve the equation.

dydx+3yx=x2-4x+3

Short Answer

Expert verified

The solution of the given equation is y=x36-4x25+3x4+Cx-3.

Step by step solution

01

Given information and simplification

Given that, dydx+3yx=x2-4x+31

Let Px=3x.

Find the value of x.

x=ePxdx=e3xdx=e3lnx=x3

Multiply x3 in equation (1) on both sides.

x3dydx+x33yx=x3x2-4x+3x3dydx+3x2y=x5-4x4+3x3ddxx3y=x5-4x4+3x3

02

Integration

Now integrate the equation on both sides.

ddxx3ydx=x5-4x4+3x3dxx3y=x66-4x55+3x44+Cy=x-3x66-4x-3x55+3x-3x44+Cx-3y=x36-4x25+3x4+Cx-3

So, the solution is y=x36-4x25+3x4+Cx-3

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