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In Problems , identify the equation as separable, linear, exact, or having an integrating factor that is a function of either x alone or y alone.

x2sinx+4ydx+xdy=0

Short Answer

Expert verified

The given equation is linear and has an integrating factor that is a function of x alone.

Step by step solution

01

General form of separable, linear, exact or integrating factors

  • Separable equation: If the right-hand side of the equation dydx=fx,y can be expressed as a function g(x) that depends only on x times a function p(y) that depends only on y, then the differential equation is called separable.
  • Linear equation:Standard form of linear equation is dydx+Pxy=Qx.
  • Exact differential form:The differential form Mx,ydx+Nx,ydy is said to be exact in a rectangle R if there is a function such that

∂F∂xx,y=Mx,y     and    ∂F∂yx,y=Nx,y

  • Special integrating factors: If∂M∂y-∂N∂xN is continuous and depends only on x. If∂N∂x-∂M∂yM is continuous and depends only on y.
02

Evaluate the given equation

Given: x2sinx+4ydx+xdy=0

Evaluate:

x2sinx+4ydx+xdy=0dydx=-x2sinx+4yxdy=-xsinx-4yxdydx+4yx=-xsinx

Compare the equation with general form of separable and linear equation.

So, the given equation is not separable but it is linear.

03

Testing for exactness

Given: x2sinx+4ydx+xdy=0

Let: M=x2sinx+4y,N=x

Then:

∂M∂y=4∂N∂x=1

So ∂M∂y≠∂N∂x.

Therefore, the given equation is not exact.

04

Computing integrating factor

If ∂M∂y-∂N∂xN then the given function is x alone.

If∂N∂x-∂M∂yM then the given function is y alone.

Then, substitute the values to prove it.

∂M∂y-∂N∂xN=4-1x=3x

So, we obtain an integrating factor that is a function of x alone. And the given equation is linear.

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