/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q2.3-7E Question: In Problems 7-16, obta... [FREE SOLUTION] | 91影视

91影视

Question: In Problems 7-16, obtain the general solution to the equation.

dydx-y-e3x=0

Short Answer

Expert verified

The general solution to the given equation is y=e3x2+Cex.

Step by step solution

01

Method for solving linear equations

  • Write the equation in the standard form dydx+P(x)y=Q(x).
  • Calculate the integrating factorlocalid="1664262698741" role="math" (x)by the formula (x)=exp[Pxdx].
  • Multiply the equation in standard form by (x)and, recalling that the left-hand side is just ddx[(x)y], obtain

(x)dydx+P(x)y=(x)Q(x)ddx[(x)y]=(x)Q(x)

  • Integrate the last equation and solve for y by dividing by(x)to obtainy(x)=1(x)[(x)Q(x)+c]. Here C is an arbitrary constant.
02

Solving the given equation

Given that,
dydx-y-e3x=0.......1

Write the equation (1) into standard form of linear equation.

dydx-y-e3x=0dydx-y=e3x.........2

Calculate the integrating factor of x.

WhereP(x)=-1

Then,

x=ePxdx=e-1dx=e-x

03

Simplification method

Multiply xin equation (2)

e-xdydx-e-xy=e2xddxe-xy=e2x

Integrating both sides.

ddxe-xydx=e2xdxe-xy=e2x2+Cy=e3x2+Cex

So, the solution is y=e3x2+Cex.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.