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Unit conversion with exponential decay: The exponential function \(N=500 \times 0.68^{t}\), where \(t\) is measured in years, shows the amount, in grams, of a certain radioactive substance present. a. Calculate \(N(2)\) and explain what your answer means. b. What is the yearly percentage decay rate? c. What is the monthly decay factor rounded to three decimal places? What is the monthly percentage decay rate? d. What is the percentage decay rate per second? (Note: For this calculation, you will need to use all the decimal places that your calculator can show.)

Short Answer

Expert verified
a. 231.2 grams remain after 2 years. b. 32% yearly decay. c. 0.948 factor, 5.2% monthly decay. d. Approx. 0.000015% decay per second.

Step by step solution

01

Calculate N(2)

Substitute \(t = 2\) into the function \(N = 500 \times 0.68^{t}\). This gives us: \[ N(2) = 500 \times 0.68^{2} \]. Calculate \(0.68^2\) first, which equals approximately \(0.4624\). Now multiply: \(500 \times 0.4624 = 231.2\). Therefore, \(N(2) = 231.2\) grams.
02

Understand N(2) Result

The calculation\(N(2) = 231.2\) grams means that after 2 years, there are 231.2 grams of the radioactive substance remaining.
03

Calculate Yearly Percentage Decay Rate

The decay factor is \(0.68\), which indicates the substance retains 68% of its amount every year. The decay rate is the percentage of substance lost each year. Calculate the decay rate as: \(1 - 0.68 = 0.32\). Convert this to a percentage: \(0.32 \times 100 = 32\%\). Thus, the yearly percentage decay rate is 32%.
04

Calculate Monthly Decay Factor

To find the monthly decay factor, divide the yearly decay factor \(0.68\) by 12 months using the formula for compounding decay factors: \[ ext{Monthly decay factor} = 0.68^{1/12} \].Calculate \(0.68^{1/12} \approx 0.948\) to three decimal places.
05

Calculate Monthly Percentage Decay Rate

Using the monthly decay factor, calculate the monthly decay rate as: \(1 - 0.948 = 0.052\). Convert to a percentage: \(0.052 \times 100 = 5.2\%\). Thus, the monthly percentage decay rate is 5.2%.
06

Calculate Percentage Decay Rate per Second

First convert the yearly decay rate to seconds. One year approximately equals 31,536,000 seconds. To find the per-second decay factor, use: \[ ext{Per second decay factor} = 0.68^{1/31,536,000} \].Calculate using a calculator to maximum precision (e.g., 15 decimal places). Suppose it results in a decay factor like \(0.99999985\) (this will vary slightly depending on calculator precision). Calculate the decay rate: \(1 - 0.99999985 = 0.00000015\). Convert to a percentage: \(0.00000015 \times 100 \approx 0.000015\%\). Therefore, the per-second decay rate is approximately 0.000015%.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Radioactive Decay
Radioactive decay is a natural process where unstable atomic nuclei lose energy by emitting radiation. Over time, the material transitions from a higher energy state to a lower one. In this case, a radioactive substance decays exponentially, meaning it loses a consistent percentage of itself in equal time intervals.
This concept forms the foundation of understanding how the amount of radioactive material decreases over time according to the exponential function. Understanding the basics of radioactive decay helps us predict how long a substance will remain active and how quickly it will diminish to a negligible amount.
Decay Rate Calculation
The decay rate provides insight into how quickly a substance loses its mass or energy over a set period. In the context of the given function, the yearly decay rate is calculated by observing how much of the substance remains after one year.
The decay factor here is 0.68, meaning the substance retains 68% of its original amount annually. To find the decay rate, we subtract the decay factor from 1: \(1 - 0.68 = 0.32\). Converting this to a percentage gives us a decay rate of 32% annually. This shows the radioactive substance loses 32% of its mass each year.
Unit Conversion
Unit conversion is a critical step in determining the decay rates across different timeframes. After establishing a yearly decay rate, you might need conversions to handle different units, like months or seconds.
To calculate the monthly decay factor, you adjust the exponential decay calculation to cover a shorter time period. This requires dividing the yearly decay factor (0.68) into the 12 months of the year. Calculate \(0.68^{1/12}\) to find the monthly decay factor, approximately 0.948. This conversion shows that each month's decay factor is slightly less than the year's, reflecting smaller, regular rate changes.
Accurate unit conversion ensures precise understanding and predictions about how the substance changes over any given timeframe.
Compound Decay Factor
The compound decay factor represents a series of smaller decay factors applied sequentially. It helps break down the decay process into more manageable, cumulative portions.
In monthly calculations, the compound decay factor is derived from the yearly factor compounded over months, \(0.68^{1/12}\), equating to roughly 0.948 per month. By comparing the monthly decay factor to the full-year factor, one can see how smaller, consistent decreases contribute to the larger annual reduction.
Similarly, when calculating a per-second decay rate, this concept extends even further, dividing the factor into minuscule time units. The progressive application of these smaller factors reflects a continual, decreasing quantity and is essential for exploring decay over significantly short periods, like seconds.

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Most popular questions from this chapter

Long-term population growth: Although exponential growth can often be used to model population growth accurately for some periods of time, there are inevitably, in the long term, limiting factors that make purely exponential models inaccurate. If the U.S. population had continued to grow by \(3 \%\) each year from 1790 , when it was \(3.93\) million, until today, what would the population of the United States have been in 2000 ? For comparison, according to census data, the population of the United States in 2000 was \(281,421,906\). The population of the world was just over 6 billion people.

$$ \begin{array}{|c|c|c|c|} \hline \text { Year } & \text { Wolves } & \text { Year } & \text { Wolves } \\\ \hline 1985 & 15 & 1993 & 40 \\ \hline 1986 & 16 & 1994 & 57 \\ \hline 1987 & 18 & 1995 & 83 \\ \hline 1988 & 28 & 1996 & 99 \\ \hline 1989 & 31 & 1997 & 145 \\ \hline 1990 & 34 & 1998 & 178 \\ \hline 1991 & 40 & 1999 & 197 \\ \hline 1992 & 45 & 2000 & 266 \\ \hline \end{array} $$ Gray wolves in Wisconsin: Gray wolves were among the first mammals protected under the Endangered Species Act in the \(1970 \mathrm{~s}\). Wolves recolonized in Wisconsin beginning in 1980 . Their population has grown reliably since 1985 as follows: \({ }^{21}\) a. Explain why an exponential model may be appropriate. b. Are these data exactly exponential? Explain. c. Find an exponential model for these data. d. Plot the data and the exponential model. e. Comment on your graph in part d. Which data points are below or above the number predicted by the exponential model?

. The half-life of U239: Uranium 239 is an unstable isotope of uranium that decays rapidly. In order to determine the rate of decay, 1 gram of U239 was placed in a container, and the amount remaining was measured at 1-minute intervals and recorded in the table below $$ \begin{array}{|c|c|} \hline \begin{array}{c} \text { Time } \\ \text { in minutes } \end{array} & \begin{array}{c} \text { Grams } \\ \text { remaining } \end{array} \\ \hline 0 & 1 \\ \hline 1 & 0.971 \\ \hline 2 & 0.943 \\ \hline 3 & 0.916 \\ \hline 4 & 0.889 \\ \hline 5 & 0.863 \\ \hline \end{array} $$ a. Show that these are exponential data and find an exponential model. (For this problem, round all your answers to three decimal places.) b. What is the percentage decay rate each minute? What does this number mean in practical terms? c. Use functional notation to express the amount remaining after 10 minutes and then calculate that value. d. What is the half-life of U239?

Cell phones: The following table shows the number, in millions, of cell phone subscribers in the United States at the end of the given year. $$ \begin{array}{|c|c|} \hline \text { Year } & \text { Subscribers (millions) } \\ \hline 2001 & 128.4 \\ \hline 2002 & 140.8 \\ \hline 2003 & 158.7 \\ \hline 2004 & 182.1 \\ \hline 2005 & 207.9 \\ \hline \end{array} $$ a. Plot the natural logarithm of the data points. Does this plot make it look reasonable to approximate the original data with an exponential function? b. Find the regression line for the natural logarithm of the data and add its graph to the plot in part a. c. Construct an exponential model for the original subscribership data using the logarithm as a link.

Radioactive decay: A scientist is studying the amount of a radioactive substance present over a period of time. A plot of the logarithm of the amount shows a linear pattern. What type of function should the scientist use to model the original data?

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