/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Data that are not exponential: S... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Data that are not exponential: Show that the following data are not exponential. $$ \begin{array}{|c|c|c|c|} \hline t & h(t) & t & h(t) \\ \hline 0 & 4.9 & 3 & 200.2 \\ \hline 1 & 26.6 & 4 & 352.1 \\ \hline 2 & 91.7 & 5 & 547.4 \\ \hline \end{array} $$

Short Answer

Expert verified
The calculated ratios are not constant; hence, the data is not exponential.

Step by step solution

01

Understand Exponential Functions

An exponential function follows the form \( h(t) = a imes b^t \), where \( a \) is the initial amount and \( b \) is the base or growth factor, a constant ratio between consecutive terms.
02

Calculate Ratios of Consecutive Terms

To determine if the data is exponential, calculate the ratios between consecutive values of \( h(t) \). Compute \( \frac{h(t+1)}{h(t)} \) for each consecutive pair: - \( \frac{h(1)}{h(0)} = \frac{26.6}{4.9} \approx 5.43 \)- \( \frac{h(2)}{h(1)} = \frac{91.7}{26.6} \approx 3.45 \)- \( \frac{h(3)}{h(2)} = \frac{200.2}{91.7} \approx 2.18 \)- \( \frac{h(4)}{h(3)} = \frac{352.1}{200.2} \approx 1.76 \)- \( \frac{h(5)}{h(4)} = \frac{547.4}{352.1} \approx 1.55 \)
03

Analyze the Ratios

If the data were exponential, the ratios should be constant. However, the calculated ratios (5.43, 3.45, 2.18, 1.76, 1.55) are not constant, indicating that the data does not follow an exponential form.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Data Analysis
Data analysis is a way to interpret and understand information. Imagine you have a list of numbers, just like how we have different values of \( h(t) \) at various times \( t \). By examining these numbers, we can find patterns or trends. This helps in predicting future outcomes or understanding past behavior.

For data that follows an exponential trend, the pattern says that as \( t \) changes, \( h(t) \) should change by a constant factor. In our example, analyzing data helps us discover that the pattern isn't exponential because the growth is not consistent.

By comparing how much \( h(t) \) changes from one point to the next, we can conclude if there’s a steady pattern or not. If the changes differ like in our example, it's not exponential but rather suggests a varying trend.
Exploring the Growth Factor
The growth factor is a special number in exponential relations. If you have an exponential function \( h(t) = a \times b^t \), the growth factor is \( b \). It tells us how much \( h(t) \) grows between each period \( t \).

For example, if \( b = 2 \), it means each step doubles the previous value. This property is key in exponential functions.

But in the data set here, if you look, every step grows by a different amount: 5.43, 3.45, 2.18, 1.76, 1.55. These values should be the same if the data followed an exponential model. They aren't constant, meaning the data doesn't have a fixed growth factor.
Introduction to Mathematical Modeling
Mathematical modeling involves creating a mathematical representation of a real-world situation. It helps us simplify and analyze complex systems using equations and functions.

In our case, we initially considered modeling the data with an exponential function, hoping \( h(t) = a \times b^t \) matches the data given.

By calculating ratios, we tested our model. However, since the model doesn't align with a single growth factor, it tells us that a different type of model might better explain the data. This is a core process in mathematical modeling: propose, test, and refine your model.
Decoding Consecutive Ratios
Consecutive ratios are calculated by dividing subsequent values in a sequence. For data that is thought to be exponential, these ratios should all be identical. They represent the growth factor over time: \( \frac{h(t+1)}{h(t)} \).

By computing these ratios for the data set
  • \( \frac{26.6}{4.9} \approx 5.43 \)
  • \( \frac{91.7}{26.6} \approx 3.45 \)
  • \( \frac{200.2}{91.7} \approx 2.18 \)
  • \( \frac{352.1}{200.2} \approx 1.76 \)
  • \( \frac{547.4}{352.1} \approx 1.55 \)
we found they are not the same. Non-uniform ratios reveal that data doesn't grow by a consistent factor, proving it’s not exponential. This analysis helps us select the right model for predicting or understanding data behavior better.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The pH scale: Acidity of a solution is determined by the concentration \(H\) of hydrogen ions in the solution (measured in moles per liter of solution). Chemists use the negative of the logarithm of the concentration of hydrogen ions to define the \(\mathrm{pH}\) scale: $$ \mathrm{pH}=-\log H . $$ Lower pH values indicate a more acidic solution. a. Normal rain has a pH value of 5.6. Rain in the eastern United States often has a pH level of \(3.8\). How much more acidic is this than normal rain? b. If the \(\mathrm{pH}\) of water in a lake falls below a value of 5 , fish often fail to reproduce. How much more acidic is this than normal water with a \(\mathrm{pH}\) of \(5.6 ?\)

Growth of bacteria: The organism \(E\). coli is a common bacterium. Under certain conditions it undergoes cell division approximately each \(20 \mathrm{~min}-\) utes. During cell division, each cell divides into two cells. a. Explain why the number of \(E\). coli cells present is an exponential function of time. b. What is the hourly growth factor for E. coli? c. Express the population N of E. coli as an exponential function of time t measured in hours. (Use N0 to denote the initial population.) d. How long will it take a population of E. coli to triple in size?

Magnitude and distance: Astronomers measure brightness of stars using both the absolute magnitude, a measure of the true brightness of the star, and the apparent magnitude, a measure of the brightness of a star as it appears from Earth.42 The difference between apparent and absolute magnitude should yield information about the distance to the star. The table on the following page gives magnitude difference m and distance d, measured in light-years, for several stars. a. Plot ln d against m and determine whether it is reasonable to model distance as an exponential function of magnitude difference. b. Give an exponential model for the data using the logarithm as a link.$$ \begin{array}{|l|c|c|} \hline \text { Star } & \begin{array}{c} \text { Magnitude } \\ \text { difference } m \end{array} & \text { Distance } d \\ \hline \text { Algol } & 2.56 & 105 \\ \hline \text { Aldebaran } & 1.56 & 68 \\ \hline \text { Capella } & 0.66 & 45 \\ \hline \text { Canopus } & 2.38 & 98 \\ \hline \text { Pollux } & 0.13 & 35 \\ \hline \text { Regulus } & 2.05 & 84 \\ \hline \end{array} $$ c. If one star shows a magnitude difference 1 greater than the magnitude difference that a second star shows, how do their distances from Earth compare? d. Alphecca shows a magnitude difference of 1.83. How far is Alphecca from Earth? e. Alderamin is 52 light-years from Earth and has an apparent magnitude of 2.47. Find the absolute magnitude of Alderamin.

Nearly linear or exponential data: One of the two tables below shows data that are better approximated with a linear function, and the other shows data that are better approximated with an exponential function. Make plots to identify which is which, and then use the appropriate regression to find models for both. $$ \begin{aligned} &\begin{array}{|c|c|} \hline t & f(t) \\ \hline 1 & 3.62 \\ \hline 2 & 23.01 \\ \hline 3 & 44.26 \\ \hline 4 & 62.17 \\ \hline 5 & 83.25 \\ \hline \end{array}\\\ &\begin{array}{|c|c|} \hline t & g(t) \\ \hline 1 & 3.62 \\ \hline 2 & 5.63 \\ \hline 3 & 8.83 \\ \hline 4 & 13.62 \\ \hline 5 & 21.22 \\ \hline \end{array} \end{aligned} $$

Radioactive decay: A physicist has found the following linear model for the natural logarithm of the amount of a radioactive substance present over time: $$ \ln A=-0.073 t+2.336 . $$ Here \(t\) is time in minutes and \(A\) is the amount in grams. Find an exponential model for the amount.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.