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Nearly linear or exponential data: One of the two tables below shows data that are better approximated with a linear function, and the other shows data that are better approximated with an exponential function. Make plots to identify which is which, and then use the appropriate regression to find models for both. $$ \begin{aligned} &\begin{array}{|c|c|} \hline t & f(t) \\ \hline 1 & 3.62 \\ \hline 2 & 23.01 \\ \hline 3 & 44.26 \\ \hline 4 & 62.17 \\ \hline 5 & 83.25 \\ \hline \end{array}\\\ &\begin{array}{|c|c|} \hline t & g(t) \\ \hline 1 & 3.62 \\ \hline 2 & 5.63 \\ \hline 3 & 8.83 \\ \hline 4 & 13.62 \\ \hline 5 & 21.22 \\ \hline \end{array} \end{aligned} $$

Short Answer

Expert verified
\(g(t)\) is linear; \(f(t)\) is exponential with models: \(g(t) \approx 4.41t - 0.86\) and \(f(t) \approx 2.4 \cdot 1.8^t\).

Step by step solution

01

Plot the Data

Start by plotting both sets of data. For the table containing \(f(t)\), plot the points (1, 3.62), (2, 23.01), (3, 44.26), (4, 62.17), and (5, 83.25). For \(g(t)\), plot the points (1, 3.62), (2, 5.63), (3, 8.83), (4, 13.62), and (5, 21.22). Look for patterns: a straight-line pattern suggests linear data, while a curved, upward-sloping pattern suggests exponential growth.
02

Identify Linear Data

After plotting, examine the graph. If the points of a dataset lie approximately in a straight line, that dataset is better approximated with a linear function. In this case, the data of \(g(t)\) appear linear.
03

Fit a Linear Model for Linear Data

Apply linear regression to the data set \(g(t)\). The linear regression model is of the form \( g(t) = at + b \). By calculating or using a calculator/computer, find the values of \(a\) and \(b\). For the dataset \(g(t)\), \(g(t) \approx 4.41t - 0.86\).
04

Identify Exponential Data

Examine the plot again and notice the pattern of \(f(t)\); it follows a curved upward pattern, indicating exponential growth.
05

Fit an Exponential Model for Exponential Data

An exponential function is of the form \( f(t) = a \cdot b^t \). By using exponential regression tools, calculate the parameters \(a\) and \(b\). For \(f(t)\), we find \(f(t) \approx 2.4 \cdot 1.8^t\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Linear Function
A linear function is a mathematical expression in which the output grows proportionally to the input. It means that you can represent such a function using the equation \( y = mx + b \), where:
  • \( m \) is the slope (the change in \( y \) for a unit change in \( x \)).
  • \( b \) is the y-intercept (the point where the line crosses the y-axis).
In the context of data modeling, when data points lie approximately on a straight line, they are well-represented by a linear function. By plotting the points and fitting a linear function using linear regression, we can determine the best-fit line, as done with the dataset \( g(t) \). Here, the equation was found to be \( g(t) = 4.41t - 0.86 \), suggesting a direct and proportional growth over time with an established beginning point.
Exponential Function
Exponential functions, represented by the equation \( y = a \, b^x \), describe situations where the rate of change of the dependent variable accelerates over time or space. Key elements include:
  • \( a \): the initial amount when \( x = 0 \).
  • \( b \): the growth factor. If \( b > 1 \), the function indicates growth; if \( b < 1 \), it indicates decay.
In practical terms, exponential functions model phenomena where change occurs rapidly, such as population growth or compound interest.
In this exercise, plotting the dataset \( f(t) \) showed an upward curved pattern, hinting at its exponential nature. By applying exponential regression, the relationship was approximated as \( f(t) = 2.4 \, 1.8^t \). This demonstrates how each subsequent point grows by a factor of approximately 1.8, underscoring the power of exponential functions in capturing dramatic growth.
Data Modeling
Data modeling is the process of creating a mathematical representation of a set of data. It allows for predictions and insights by finding relationships and trends within the data. When modeling data:
  • Start by plotting the data points to visually assess their pattern.
  • Determine whether the data set follows a linear pattern or an exponential one.
  • Choose the appropriate model (either linear or exponential) to apply based on observed patterns.
  • Use regression techniques to quantify the relationship with the best fit parameters for the chosen model.
This exercise required distinguishing between linear and exponential data through plotting and identification, leading to the selection of the appropriate regression models. Regression analysis then provided the means to extract meaningful relationships from the data, demonstrating how effective data modeling can be in uncovering these patterns and trends.

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Most popular questions from this chapter

Headway on four-lane highways: When traffic is flowing on a highway, the headway is the average time between vehicles. On four-lane highways, the probability \(P\) that the headway is at least \(t\) seconds is given to a good degree of accuracy \({ }^{6}\) by $$ P=e^{-q t}, $$ a. On a four-lane highway carrying an average of 500 vehicles per hour in one direction, what is the probability that the headway is at least 15 seconds? (Note: 500 vehicles per hour is \(\frac{500}{3600}=0.14\) vehicle per second.) b. On a four-lane highway carrying an average of 500 vehicles per hour, what is the decay factor for the probability that headways are at least \(t\) seconds? Reminder: An important law of exponents tells us that \(a^{b c}=\left(a^{b}\right)^{c}\). where \(q\) is the average number of vehicles per second traveling one way on the highway.

Long-term population growth: Although exponential growth can often be used to model population growth accurately for some periods of time, there are inevitably, in the long term, limiting factors that make purely exponential models inaccurate. If the U.S. population had continued to grow by \(3 \%\) each year from 1790 , when it was \(3.93\) million, until today, what would the population of the United States have been in 2000 ? For comparison, according to census data, the population of the United States in 2000 was \(281,421,906\). The population of the world was just over 6 billion people.

. The half-life of U239: Uranium 239 is an unstable isotope of uranium that decays rapidly. In order to determine the rate of decay, 1 gram of U239 was placed in a container, and the amount remaining was measured at 1-minute intervals and recorded in the table below $$ \begin{array}{|c|c|} \hline \begin{array}{c} \text { Time } \\ \text { in minutes } \end{array} & \begin{array}{c} \text { Grams } \\ \text { remaining } \end{array} \\ \hline 0 & 1 \\ \hline 1 & 0.971 \\ \hline 2 & 0.943 \\ \hline 3 & 0.916 \\ \hline 4 & 0.889 \\ \hline 5 & 0.863 \\ \hline \end{array} $$ a. Show that these are exponential data and find an exponential model. (For this problem, round all your answers to three decimal places.) b. What is the percentage decay rate each minute? What does this number mean in practical terms? c. Use functional notation to express the amount remaining after 10 minutes and then calculate that value. d. What is the half-life of U239?

Atmospheric pressure: The table below gives a measurement of atmospheric pressure, in grams per square centimeter, at the given altitude, in kilometers.17 $$ \begin{array}{|c|c|} \hline \text { Altitude } & \text { Atmospheric pressure } \\ \hline 5 & 569 \\ \hline 10 & 313 \\ \hline 15 & 172 \\ \hline 20 & 95 \\ \hline 25 & 52 \\ \hline \end{array} $$ (For comparison, 1 kilometer is about 0.6 mile, and 1 gram per square centimeter is about 2 pounds per square foot.) a. Plot the data on atmospheric pressure. b. Make an exponential model for the data on atmospheric pressure. c. What is the atmospheric pressure at an altitude of 30 kilometers? d. Find the atmospheric pressure on Earth’s surface. This is termed standard atmospheric pressure. e. At what altitude is the atmospheric pressure equal to 25% of standard atmospheric pressure?

Cell phones: The following table shows the number, in millions, of cell phone subscribers in the United States at the end of the given year. $$ \begin{array}{|c|c|} \hline \text { Year } & \text { Subscribers (millions) } \\ \hline 2001 & 128.4 \\ \hline 2002 & 140.8 \\ \hline 2003 & 158.7 \\ \hline 2004 & 182.1 \\ \hline 2005 & 207.9 \\ \hline \end{array} $$ a. Plot the natural logarithm of the data points. Does this plot make it look reasonable to approximate the original data with an exponential function? b. Find the regression line for the natural logarithm of the data and add its graph to the plot in part a. c. Construct an exponential model for the original subscribership data using the logarithm as a link.

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