/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Relative abundance of species: A... [FREE SOLUTION] | 91Ó°ÊÓ

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Relative abundance of species: A collection of animals may contain a number of species. Some rare species may be represented by only 1 individual in the collection. Others may be represented by more. In 1943 Fisher, Corbert, and Williams \({ }^{37}\) proposed a model for finding the number of species in certain types of collections represented by a fixed number of individuals. They associate with an animal collection two constants, \(\alpha\) and \(x\), with the following property: The number of species in the sample represented by a single individual is \(\alpha x\); the number in the sample represented by 2 individuals is \(\alpha\left(x^{2} / 2\right)\); and, in general, the number of species represented by \(n\) individuals is \(\alpha\left(x^{n} / n\right)\). If we add all these numbers up, we get the total number \(S\) of species in the collection. It is an important fact from advanced mathematics that this sum also yields a natural logarithm: $$ S=\alpha x+\alpha \frac{x^{2}}{2}+\alpha \frac{x^{3}}{3}+\cdots=-\alpha \ln (1-x) $$ If \(N\) is the total number of individuals in the sample, then it turns out that we can find \(x\) by solving the equation $$ \frac{x-1}{x} \ln (1-x)=\frac{S}{N} . $$ We can then find the value of \(\alpha\) using $$ \alpha=\frac{N(1-x)}{x} \text {. } $$ In 1935 at the Rothamsted Experimental Station in England, 6814 moths representing 197 species were collected and catalogued. a. What is the value of \(S / N\) for this collection? (Keep four digits beyond the decimal point.) b. Draw a graph of the function $$ \frac{x-1}{x} \ln (1-x) $$ using a horizontal span of 0 to 1 . c. Use your answer to part a and your graph in part b to determine the value of \(x\) for this collection. (Keep four digits beyond the decimal point.) d. What is the value of \(\alpha\) for this collection? (Keep two digits beyond the decimal point.) e. How many species of moths in the collection were represented by 5 individuals? f. For this collection, plot the graph of the number of species represented by \(n\) individuals against \(n\). Include values of \(n\) up to 20 .

Short Answer

Expert verified
a. 0.0289, c. x ≈ 0.9711, d. α ≈ 199.06, e. ≈ 35 species.

Step by step solution

01

Calculate S/N

To find the ratio \( S/N \), where \( S \) is the total number of species and \( N \) is the total number of individuals in the sample, use the provided numbers from Rothamsted Experimental Station: \( S = 197 \) species and \( N = 6814 \) moths. Compute it as follows:\[\frac{S}{N} = \frac{197}{6814} \approx 0.02891.\]
02

Graph the Function

To graph the function \( \frac{x-1}{x} \ln(1-x) \), you will plot it for values of \( x \) ranging from 0 to 1. This function is undefined for \( x = 0 \) and \( x = 1 \), so focus specifically on the interval (0, 1). You can use a graphing tool or software such as Desmos or a graphing calculator to accurately plot this curve.
03

Determine the Value of x

With the graph from Step 2, find the \( x \) value that corresponds to \( \frac{S}{N} = 0.02891 \). This requires finding where the graph intersects the line \( y = 0.02891 \). By exploring or zooming in around the intersection, determine that \( x \approx 0.9711 \).
04

Find the Value of Alpha

Using the formula \( \alpha = \frac{N(1-x)}{x} \), plug in the values for \( N = 6814 \) and the previously calculated \( x = 0.9711 \):\[\alpha = \frac{6814(1-0.9711)}{0.9711} \approx 199.06.\]
05

Calculate Number of Species with 5 Individuals

Using the formula for the number of species represented by \( n \) individuals, substitute \( n = 5 \):\[\text{Number of species} = \alpha \frac{x^5}{5} = 199.06 \times \frac{0.9711^5}{5} \approx 35.43.\] Rounding gives approximately 35 species.
06

Plot Species vs. Number of Individuals

To plot the graph, calculate the number of species for each \( n \) from 1 to 20 using the formula \( \alpha \frac{x^n}{n} \). For each value of \( n \), calculate \( 199.06 \times \frac{0.9711^n}{n} \). Use these values to plot the number of species (y-axis) against the number of individuals (n, x-axis). This will show the decline in species count as the number of individuals representing them increases.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Fisher-Corbert-Williams model
The Fisher-Corbert-Williams model is a pivotal concept in species abundance modeling designed to understand biodiversity in ecological samples. This model was introduced in 1943 to estimate the number of species in a collection or ecosystem. The model uses two constants: \( \alpha \) and \( x \) to describe how many different species are present based on the number of individuals for each species. These constants are crucial in predicting species distribution and abundance.
The calculation involves a series where the number of species represented by just one individual is \( \alpha x \), two individuals is \( \alpha \left(\frac{x^2}{2}\right) \), and so on. The total number of species \( S \) is the sum:
  • \( S = \alpha x + \alpha \frac{x^2}{2} + \alpha \frac{x^3}{3} + \ldots \)
  • Mathematically equivalent to: \( S = -\alpha \ln(1-x) \)
This model is valuable because it combines finite sample data to continuously estimate species richness, offering powerful insights into ecological diversity and aiding in conservation efforts.
mathematical modeling
Mathematical modeling in ecology involves developing mathematical formulas and representations to explain and predict natural phenomena. With models like that of Fisher-Corbert-Williams, researchers can simulate ecological patterns and understand complex systems. Here, mathematical equations describe species diversity based on parameters like \( \alpha \) and \( x \). These constants facilitate predictions about species count and distribution without exhaustive sampling.
Models can be:
  • Deterministic: providing precise outcomes based on input conditions without inherent randomness.
  • Stochastic: incorporating random variability to account for uncertainty in natural processes.
In this context, solving for \( x \) and \( \alpha \) enables determining relative abundance and requires interpreting functions such as \( \frac{x-1}{x} \ln(1-x) \). These calculations are essential for converting observed sample data (e.g., moths' examples) to meaningful ecological metrics.
natural logarithms
Natural logarithms are fundamental in many fields, including ecology, to simplify complex calculations. They use the constant \( e \) (approximately 2.718) as the base for logarithmic expressions. In species abundance models like Fisher-Corbert-Williams, natural logarithms transform multiplicative relationships into additive ones, simplifying computation.
In our context, the total number of species given by the sum \( S = -\alpha \ln(1-x) \) leverages properties of natural logarithms. This equation relates the series of distributions \( \alpha \frac{x^n}{n} \) to a continuous function of logarithmic properties.
  • Facilitates solving otherwise complicated expressions.
  • Translates into more straightforward computational steps when dealing with large numbers in ecology.
The use of natural logarithms thus reduces complexity, providing clear pathways to solve for critical variables, which is vital for interpreting ecological data.
data analysis in ecology
Data analysis in ecology involves collecting, organizing, and evaluating biological data to understand relationships and patterns within ecosystems. The objective is to use statistical and mathematical tools to make informed decisions about biodiversity and conservation.
  • Incorporates quantitative methods to infer trends and relations from sample data.
  • Helpful in monitoring changes over time and evaluating ecological health.
Using the Fisher-Corbert-Williams model, ecologists convert raw data (like the number of moth species caught in an experiment) into informative statistics on species abundance. By analyzing the function \( \frac{x-1}{x} \ln(1-x) \) and finding \( x \), one can determine the species richness and equitability in a sample. This analysis allows for predictions and informed conclusions about ecological diversity. The application of data analysis in ecology ensures that habitats are better understood and managed sustainably.

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Most popular questions from this chapter

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