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Radioactive decay: A physicist has found the following linear model for the natural logarithm of the amount of a radioactive substance present over time: $$ \ln A=-0.073 t+2.336 . $$ Here \(t\) is time in minutes and \(A\) is the amount in grams. Find an exponential model for the amount.

Short Answer

Expert verified
The exponential model is \( A = 10.34 \cdot e^{-0.073t} \).

Step by step solution

01

Transforming the Linear to Exponential Model

Given the linear model: \[ \ln A = -0.073t + 2.336. \] The equation is of the form \( y = mx + b \), with \( y = \ln A \), \( m = -0.073 \), \( x = t \), and \( b = 2.336 \). To convert this into an exponential model, we must rewrite the formula as an exponential function by expressing \( A \) directly in terms of \( t \).
02

Exponentiating Both Sides

To find \( A \), exponentiate both sides of the equation to eliminate the natural logarithm:\[ A = e^{(-0.073t + 2.336)}.\] This equation represents \( A \) as an exponential function in terms of \( t \).
03

Simplifying the Exponential Expression

Using the properties of exponents, \( e^{a+b} = e^a \cdot e^b \), separate the exponential terms:\[ A = e^{-0.073t} \cdot e^{2.336}. \] This further simplifies to:\[ A = \left(e^{2.336}\right) \cdot \left(e^{-0.073t}\right). \] Here, \( e^{2.336} \) is a constant multiplier, and \( e^{-0.073t} \) shows the decay over time.
04

Calculating the Constant

Calculate the constant \( e^{2.336} \) using a calculator:\[ C = e^{2.336} \approx 10.34.\] Thus, the model becomes:\[ A = 10.34 \cdot e^{-0.073t}, \]where \( C \approx 10.34 \) is the initial amount when \( t = 0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Exponential Model
In mathematics and physics, an exponential model is a type of mathematical model used to describe situations where a quantity grows or decays at a rate proportional to its current value. This typically results in an exponential function, such as in the case of radioactive decay. When dealing with radioactive substances, the amount of substance decreases over time in a way that can be described by an exponential decay model. This model often takes the form \(A = A_0 e^{-kt}\), where:
  • \(A\) is the amount of the substance at time \(t\).
  • \(A_0\) is the initial amount of the substance when \(t = 0\).
  • \(k\) is the decay constant, a positive number specific to the substance.
The exponential model is particularly useful because it provides a straightforward way to predict future amounts of a substance based on current or known past values.
Natural Logarithm
The natural logarithm, denoted \(\ln(x)\), is the logarithm to the base \(e\), where \(e\) is a constant approximately equal to 2.71828. Natural logarithms are commonly used in mathematics due to their unique properties and connections to exponential functions. In particular, \(\ln(e) = 1\), and \(\ln(1) = 0\). These properties make natural logarithms extremely powerful in converting multiplicative processes into additive ones, thereby simplifying calculations involving growth or decay.In the context of radioactive decay, the natural logarithm is used to express the linear relationship between the amount of substance and time, as seen in the given linear model. By exponentiating this logarithmic form, we can transform the relationship back into an exponential function, which can then be used to model the decay accurately.
Linear to Exponential Transformation
Transforming a linear equation into an exponential form involves exponentiating both sides of an equation where a natural logarithm is present. This process is essential when dealing with logarithmic expressions that need to be interpreted or presented in their more useful exponential form. For example, given the equation \(\ln A = -0.073t + 2.336\), to solve for \(A\), we exponentiate both sides to get:\[ A = e^{(-0.073t + 2.336)}. \]Utilizing the property of exponents, \(e^{a+b} = e^a \cdot e^b\), we can further simplify this into:\[ A = e^{2.336} \cdot e^{-0.073t}. \]This shows our transition from a linear representation of decay to an exponential one, making it easier to work with in practical scenarios and solve problems involving decay rates.
Radioactive Substance
A radioactive substance contains unstable atomic nuclei that lose energy by emitting radiation. This process is known as radioactive decay, and it results in the transformation of the nuclei into different elements or isotopes over time. Radioactive decay follows a predictable pattern, often represented by an exponential decay model due to the fact that the decay process is proportional to the current quantity of the substance. This is why the amount of radioactive material decreases exponentially over time. In practical terms:
  • Each moment, the likelihood of a given nucleus decaying remains constant, which leads to the exponential nature of the model.
  • Important applications include dating archaeological findings, understanding nuclear reactions, and medical imaging.
The use of an exponential model allows physicists and other scientists to predict how long a radioactive substance will remain active, how quickly it will decay, and to calculate its half-life, which is the time taken for half of the radioactive nuclei to decay.

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Most popular questions from this chapter

Growth in length: In the fishery sciences it is important to determine the length of a fish as a function of its age. One common approach, the von Bertalanffy model, uses a decreasing exponential function of age to describe the growth in length yet to be attained; in other words, the difference between the maximum length and the current length is supposed to decay exponentially with age. The following table shows the length \(L\), in inches, at age \(t\), in years, of the North Sea sole. \({ }^{40}\) $$ \begin{array}{|c|c|c|c|} \hline t=\text { age } & L \text { = length } & t=\text { age } & L=\text { length } \\ \hline 1 & 3.7 & 5 & 12.7 \\ \hline 2 & 7.5 & 6 & 13.5 \\ \hline 3 & 10.0 & 7 & 14.0 \\ \hline 4 & 11.5 & 8 & 14.4 \\ \hline \end{array} $$ The maximum length attained by the sole is \(14.8\) inches. a. Make a table showing, for each age, the difference \(D\) between the maximum length and the actual length \(L\) of the sole. b. Find the exponential function that approximates \(D\) using the logarithm as a link. c. Find a formula expressing the length \(L\) of a sole as a function of its age \(t\). d. Draw a graph of \(L\) against \(t\).

Wages: A worker is reviewing his pay increases over the past several years. The table below shows the hourly wage W, in dollars, that he earned as a function of time t, measured in years since the beginning of 1990. $$ \begin{array}{|c|c|} \hline \text { Time } t & \text { Wage } W \\ \hline 1 & 15.30 \\ \hline 2 & 15.60 \\ \hline 3 & 15.90 \\ \hline 4 & 16.25 \\ \hline \end{array} $$ a. By calculating ratios, show that the data in this table are exponential. (Round the quotients to two decimal places.) b. What is the yearly growth factor for the data? c. The worker can't remember what hourly wage he earned at the beginning of 1990 . Assuming that \(W\) is indeed an exponential function, determine what that hourly wage was. d. Find a formula giving an exponential model for \(W\) as a function of \(t\). e. What percentage raise did the worker receive each year?f. Given that prices increased by 34% over the decade of the 1990s, use your model to determine whether the worker’s wage increases kept pace with inflation.

Population: A scientist who is studying population data makes a plot of the logarithm of the population values as a function of time. If the population is growing exponentially, what should the plot look like?

Grains of wheat on a chess board: A children's fairy tale tells of a clever elf who extracted from a king the promise to give him one grain of wheat on a chess board square today, two grains on an adjacent square tomorrow, four grains on an adjacent square the next day, and so on, doubling the number of grains each day until all 64 squares of the chess board were used. How many grains of wheat did the hapless king contract to place on the 64th square? There are about \(1.1\) million grains of wheat in a bushel. Assume that a bushel of wheat sells for \(\$ 4.25\). What was the value of the wheat on the 64th square?

State quakes: The largest recorded earthquake centered in Idaho measured \(7.2\) on the Richter scale. a. The largest recorded earthquake centered in Montana was \(3.16\) times as powerful as the Idaho earthquake. What was the Richter scale reading for the Montana earthquake? b. The largest recorded earthquake centered in Arizona measured \(5.6\) on the Richter scale. How did the power of the Idaho quake compare with that of the Arizona quake?

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