/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 17 Sound pressure: Sound exerts pre... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Sound pressure: Sound exerts pressure on the human ear. Increasing loudness corresponds to greater pressure. The table below shows the pressure P , in dynes per square centimeter, exerted on the ear by sound with loudness D, measured in decibels. $$ \begin{array}{|c|c|} \hline \text { Loudness } D & \text { Pressure } P \\ \hline 65 & 0.36 \\ \hline 85 & 3.6 \\ \hline 90 & 6.4 \\ \hline 105 & 30 \\ \hline 110 & 50 \\ \hline \end{array} $$ a. Plot the natural logarithm of the data. Does it appear reasonable to model pressure as an exponential function of loudness? b. Find an exponential model of P as a function of D using the logarithm as a link. c. How is pressure on the ear affected when loudness is increased by 1 decibel?

Short Answer

Expert verified
The pressure increases by about 9.1% for each 1 dB increase in loudness.

Step by step solution

01

Calculate the Natural Logarithm of Pressure

We will calculate the natural logarithm of pressure, \( P \), for each loudness, \( D \), value given in the table.\[ \begin{align*}D = 65 \, & : \, \ln(0.36) \approx -1.0217 \D = 85 \, & : \, \ln(3.6) \approx 1.2809 \D = 90 \, & : \, \ln(6.4) \approx 1.8563 \D = 105 \, & : \, \ln(30) \approx 3.4012 \D = 110 \, & : \, \ln(50) \approx 3.9120 \end{align*}\\] This will allow us to analyze if an exponential model is suitable.
02

Plot the Natural Logarithm Data

Plot the calculated natural logarithm values against loudness \( D \). The \( x \)-axis represents loudness \( D \), and the \( y \)-axis represents \( \ln(P) \). If the plot appears approximately linear, it indicates that pressure can be modeled exponentially as a function of loudness.
03

Develop the Exponential Model

An exponential model has the form \( P = ab^D \). Taking the natural log gives \( \ln(P) = \ln(a) + D \ln(b) \). Using linear regression on the \( (D, \ln(P)) \) data points, determine the slope \( \ln(b) \) and intercept \( \ln(a) \). Applying linear regression, we find approximately: - Slope \( \ln(b) \approx 0.0871 \) - Intercept \( \ln(a) \approx -6.5253 \)Thus, \( a \approx e^{-6.5253}, b \approx e^{0.0871} \). This gives the model: \( P = 0.001468 e^{0.0871D} \).
04

Analyze the Effect of Increasing Loudness by 1 Decibel

Given the model \( P = 0.001468 e^{0.0871D} \), increasing the loudness by 1 dB changes \( D \) to \( D+1 \). The ratio of new pressure to old pressure is \( \frac{e^{0.0871(D+1)}}{e^{0.0871D}} = e^{0.0871} \approx 1.091 \). Therefore, the pressure increases by approximately 9.1% for each 1 dB increase in loudness.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sound Pressure
Sound pressure is the force exerted by sound waves as they interact with surfaces, like our ears. Imagine sound waves as ripples that you see in water.
When these waves hit something, they apply force over a particular area. In acoustics, this is measured as sound pressure.
- Sound pressure is measured in units like dynes per square centimeter, which indicates the pressure the sound waves exert on a surface.
- Human ears detect different levels of sound pressure, which our brain interprets as varying loudness. Greater pressure implies louder sound.
Understanding sound pressure helps us figure out how certain sounds, like music or noise, affect us. For example, high sound pressure levels can be uncomfortable or even harmful after prolonged exposure. By studying sound pressure and how it changes with loudness, we can make environments like concert halls and workplaces safer and more enjoyable.
Logarithm Transformation
Logarithm transformation is a nifty mathematical tool that helps simplify complex relationships. In our sound pressure scenario, this transformation is particularly useful.
- A logarithm answers the question: "To what exponent must we raise a base number, such as 10 or Euler's number (\(e\)), to get another number?"
- When we take the natural logarithm (\(\ln\)) of a value, we're using a base of \(e\), which is approximately 2.718.
Transforming sound pressure data into logarithms aids in modeling. When pressure and loudness relate exponentially, plotting the logarithm of pressure against loudness often yields a straight line.
This linearity allows us to apply linear regression techniques to develop an accurate model. Instead of dealing with exponential complexity, logarithms offer a more straightforward linear approach.
Linear Regression
Linear regression is a method that helps uncover the relationship between two variables. In our case, it's used to model the relationship between loudness and the logarithm of sound pressure.
- Think of it as drawing the best-fitting straight line through data points on a graph. The line minimizes the total difference between itself and the points.
- The linear equation derived can help predict one variable's value if you have the other. Here, it helps predict sound pressure from loudness.
The process works by finding two key components: the slope and the intercept, from the ideal line through the data points.
In our context, the slope suggests how much \(\ln(P)\) changes with every increment in loudness \(D\), and the intercept indicates where the line crosses the \(y\)-axis.
Understanding these lets us transform the problem back into an exponential form that models sound pressure accurately.
Decibels
Decibels (dB) are the units used to express sound intensity or loudness. It's a logarithmic scale that quantifies sound pressure level relative to a reference point.
- A decibel represents a relative difference between two quantities of power or pressure.
- This scale is logarithmic because it covers an extensive range of sound pressures humans can perceive, from the faintest rustling leaves to an airplane engine.
On this scale, a 10 dB increase generally means sound intensity is ten times greater. However, our perception of this change isn't linear, which is why the logarithmic nature of the decibel scale is so fitting.
For instance, increasing loudness by 1 dB in our modeled relationship results in a noticeable 9.1% increase in sound pressure.
By using decibels, we can manage sound levels effectively and ensure environments are suitable for human occupancy, between comfort and safety.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Spectroscopic parallax: Stars have an apparent magnitude \(m\), which is the brightness of light reaching Earth. They also have an absolute magnitude \(M\), which is the intrinsic brightness and does not depend on the distance from Earth. The difference \(S=m-M\) is the spectroscopic parallax. Spectroscopic parallax is related to the distance \(D\) from Earth, in parsecs, 35 by $$ S=5 \log D-5 $$ a. The distance to the star Kaus Astralis is \(38.04\) parsecs. What is its spectroscopic parallax? b. The spectroscopic parallax for the star Rasalhague is 1.27. How far away is Rasalhague? c. How is spectroscopic parallax affected when distance is multiplied by 10 ? d. The star Shaula is \(3.78\) times as far away as the star Atria. How does the spectroscopic parallax of Shaula compare to that of Atria?

$$ \begin{array}{|c|c|c|c|} \hline \text { Year } & \text { Wolves } & \text { Year } & \text { Wolves } \\\ \hline 1985 & 15 & 1993 & 40 \\ \hline 1986 & 16 & 1994 & 57 \\ \hline 1987 & 18 & 1995 & 83 \\ \hline 1988 & 28 & 1996 & 99 \\ \hline 1989 & 31 & 1997 & 145 \\ \hline 1990 & 34 & 1998 & 178 \\ \hline 1991 & 40 & 1999 & 197 \\ \hline 1992 & 45 & 2000 & 266 \\ \hline \end{array} $$ Gray wolves in Wisconsin: Gray wolves were among the first mammals protected under the Endangered Species Act in the \(1970 \mathrm{~s}\). Wolves recolonized in Wisconsin beginning in 1980 . Their population has grown reliably since 1985 as follows: \({ }^{21}\) a. Explain why an exponential model may be appropriate. b. Are these data exactly exponential? Explain. c. Find an exponential model for these data. d. Plot the data and the exponential model. e. Comment on your graph in part d. Which data points are below or above the number predicted by the exponential model?

Stand density: Forest managers are interested in measures of how crowded a given forest stand is. \({ }^{33}\) One measurement used is the stand-density index, or \(S D I\). It can be related to the number \(N\) of trees per acre and the diameter \(D\), in inches, of a tree of average size (in terms of cross- sectional area at breast height) for the stand. The relation is $$ \log S D I=\log N+1.605 \log D-1.605 . $$ b. What is the effect on the stand-density index of increasing the number of trees per acre by a factor of 10 , assuming that the average size of a tree remains the same? c. What is the relationship between the stand-density index and the number of trees per acre if the diameter of a tree of average size is 10 inches? a. A stand has 500 trees per acre, and the diameter of a tree of average size is 7 inches. What is the stand-density index? (Round your answer to the nearest whole number.) b. What is the effect on the stand-density index of increasing the number of trees per acre by a factor of 10, assuming that the average size of a tree remains the same? c. What is the relationship between the stand-density index and the number of trees per acre if the diameter of a tree of average size is 10 inches?

Household income: The following table shows the median income, in thousands of dollars, of American families. $$ \begin{array}{|c|c|} \hline \text { Year } & \begin{array}{c} \text { Income } \\ \text { (thousands of dollars) } \end{array} \\ \hline 2000 & 50.73 \\ \hline 2001 & 51.41 \\ \hline 2002 & 51.68 \\ \hline 2003 & 52.68 \\ \hline 2004 & 54.06 \\ \hline 2005 & 56.19 \\ \hline \end{array} $$ a. Plot the natural logarithm of the data. Does it appear reasonable to model family income using an exponential function? b. Find the equation of the regression line for the natural logarithm of the data. c. Construct an exponential model for the original income data using the logarithm as a link.

Population: A biologist has found the following linear model for the natural logarithm of an animal population as a function of time: $$ \ln N=0.039 t-0.693 . $$ Here \(t\) is time in years and \(N\) is the population in thousands. Find an exponential model for the population.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.