/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 14 Estimate the doubling time using... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Estimate the doubling time using the rule of 70 when: a. \(P=2.1(1.0475)^{t}\), where \(t\) is in years b. \(Q=2.1(1.00475)^{T}\), where \(T\) is in years

Short Answer

Expert verified
Doubling time for (a) is 14.74 years and for (b) is 147.37 years.

Step by step solution

01

Understanding the Rule of 70

The rule of 70 is a way to estimate the doubling time of an investment or population growing at a fixed annual rate. The formula is: \[ \text{Doubling Time} = \frac{70}{\text{Growth Rate (\text{in \text{\text{%}}})}} \]
02

for Part (a) - Identify the Growth Rate

For the equation given: \( P = 2.1(1.0475)^t \), the annual growth rate is 4.75%. This is because the base of the exponential term is 1.0475, which means a growth rate of 4.75%.
03

for Part (a) - Apply the Rule of 70

Using the rule of 70, the doubling time can be calculated as: \[ \text{Doubling Time} = \frac{70}{4.75} \ \text{Doubling Time} \, \text{(in years)} = 14.74 \]
04

for Part (b) - Identify the Growth Rate

For the equation given: \( Q = 2.1(1.00475)^T \), the annual growth rate is 0.475%. This is because the base of the exponential term is 1.00475, which means a growth rate of 0.475%.
05

for Part (b) - Apply the Rule of 70

Using the rule of 70, the doubling time can be calculated as: \[ \text{Doubling Time} = \frac{70}{0.475} \ \text{Doubling Time} \, \text{(in years)} = 147.37 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

rule of 70
The Rule of 70 is a simple method to estimate how long it will take for a quantity to double, given a consistent annual growth rate. This rule is particularly useful for understanding population growth, investments, or any scenario involving exponential growth. The formula is straightforward: divide 70 by the annual growth rate (expressed as a percentage).
For example, if a population grows at an annual rate of 5%, the doubling time is approximately:
\[ \text{Doubling Time} = \frac{70}{5} = 14\text{ years} \]
Always remember to check the growth rate format. If it’s 4.75%, use 4.75 directly, not as a decimal (0.0475). This rule serves as a quick estimate, not an exact calculation, but it is remarkably useful for making quick comparisons and forecasts.
exponential growth
Exponential growth describes a process where the quantity increases by a constant percentage each period. This is commonly seen in populations, finance, and even certain types of data increase. The general formula for exponential growth is:
\[ P(t) = P_0 \times (1 + r)^t \] where:
  • \( P(t) \) is the amount at time \( t \)
  • \( P_0 \) is the initial amount
  • \( r \) is the growth rate per period
  • \( t \) is the number of periods

Every period, such as every year, the quantity multiplies by \(1 + r\), making the growth ‘exponential.’ This kind of growth can lead to large numbers very quickly because you’re always adding a percentage of an ever-growing amount. For instance, a population of 1,000 growing at 5% per year becomes 1,050 after one year, 1,102.5 after two years, and so on. Understanding exponential growth is crucial for grasping concepts like doubling time and rates of increase.
annual growth rate
The annual growth rate is the percentage increase in a population or investment over the span of a year. It is a key variable in many financial, environmental, and demographic studies. To find the annual growth rate within equations like these:
\( P = 2.1(1.0475)^t \)
Look at the base of the exponential term. Here, 1.0475 means the annual growth rate is 4.75%. If this base were 1.00475, the growth rate would be 0.475%. Always convert the term immediately to a percentage by moving the decimal point two places to the right.
The annual growth rate helps in predicting how quickly something like a population or investment will grow over time and is an integral part of exponential growth calculations.

Key points to remember:
  • Identify the base of the exponential term
  • Convert the decimal to a percentage (e.g., 1.0475 becomes 4.75%)
population growth estimation
Estimating population growth can be essential for planning in areas like urban development, resource management, and public health. One common method to estimate this growth is through the exponential growth model, which assumes a constant rate of growth. Doubling time can also assist in these estimations. Using the rule of 70, you can estimate how long it will take for a population to double in size.
For instance, if you have an annual growth rate of 4.75%, the doubling time is calculated as:
\[ \text{Doubling Time} = \frac{70}{4.75} \text{ years} = 14.74 \text{ years} \]
Such estimates help policymakers and researchers make crucial decisions. Knowing that a population will double in about 14.74 years tells you when more resources, infrastructure, or services will be needed.
Key aspects include:
  • Understanding the growth rate
  • Using the rule of 70 for quick calculations
  • Predicting the timeline for future resource needs

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

(Graphing program recommended.) Make a table of values and plot each pair of functions on the same coordinate system. a. \(y=2^{x}\) and \(y=2 x\) for \(-3 \leq x \leq 3\) b. \(y=(0.5)^{x}\) and \(y=0.5 x\) for \(-3 \leq x \leq 3\) c. Which of the four functions that you drew in parts (a) and (b) represent growth? d. How many times did the graphs that you drew for part (a) intersect? Find the coordinates of any points of intersection. e. How many times did the graphs that you drew for part (b) intersect? Find the coordinates of any points of intersection.

(Graphing program recommended.) Cosmic ray bombardment of the atmosphere produces neutrons, which in turn react with nitrogen to produce radioactive carbon-14. Radioactive carbon-14 enters all living tissue through carbon dioxide (via plants). As long as a plant or animal is alive, carbon-14 is maintained in the organism at a constant level. Once the organism dies, however, carbon-14 decays exponentially into carbon-12. By comparing the amount of carbon- 14 to the amount of carbon-12, one can determine approximately how long ago the organism died. Willard Libby won a Nobel Prize for developing this technique for use in dating archaeological specimens. The half-life of carbon-14 is about 5730 years. In answering the following questions, assume that the initial quantity of carbon- 14 is 500 milligrams. a. Construct an exponential function that describes the relationship between \(A,\) the amount of carbon- 14 in milligrams, and \(t,\) the number of 5730 -year time periods. b. Generate a table of values and plot the function. Choose a reasonable set of values for the domain. Remember that the objects we are dating may be up to 50,000 years old. c. From your graph or table, estimate how many milligrams are left after 15,000 years and after 45,000 years. d. Now construct an exponential function that describes the relationship between \(A\) and \(T,\) where \(T\) is measured in years. What is the annual decay factor? The annual decay rate? e. Use your function in part (d) to calculate the number of milligrams that would be left after 15,000 years and after 45,000 years.

In medicine and biological research, radioactive substances are often used for treatment and tests. In the laboratories of a large East Coast university and medical center, any waste containing radioactive material with a half-life under 65 days must be stored for 10 half-lives before it can be disposed of with the non-radioactive trash. a. By how much does this policy reduce the radioactivity of the waste? b. Fill out the accompanying chart and develop a general formula for the amount of radioactive pollution at any period, given an initial amount, \(A_{0}\).

Which of the following exponential functions represent growth and which decay? a. \(N=50 \cdot 2.5^{T}\) b. \(y=264(5 / 2)^{x}\) c. \(R=745(1.001)^{t}\) d. \(g(z)=\left(3 \cdot 10^{5}\right) \cdot(0.8)^{z}\) e. \(f(T)=\left(1.5 \cdot 10^{11}\right) \cdot(0.35)^{T}\) f. \(h(x)=2000\left(\frac{2}{3}\right)^{x}\)

(Graphing program recommended.) If you have a heart attack and your heart stops beating, the amount of time it takes paramedics to restart your heart with a defibrillator is critical. According to a medical report on the evening news, each minute that passes decreases your chance of survival by \(10 \%\). From this wording it is not clear whether the decrease is linear or exponential. Assume that the survival rate is \(100 \%\) if the defibrillator is used immediately. a. Construct and graph a linear function that describes your chances of survival. After how many minutes would your chance of survival be \(50 \%\) or less? b. Construct and graph an exponential function that describes your chances of survival. Now after how many minutes would your chance of survival be \(50 \%\) or less?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.