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Estimate the doubling time using the rule of 70 when: a. \(P=2.1(1.0475)^{t}\), where \(t\) is in years b. \(Q=2.1(1.00475)^{T}\), where \(T\) is in years

Short Answer

Expert verified
Doubling time for (a) is 14.74 years and for (b) is 147.37 years.

Step by step solution

01

Understanding the Rule of 70

The rule of 70 is a way to estimate the doubling time of an investment or population growing at a fixed annual rate. The formula is: \[ \text{Doubling Time} = \frac{70}{\text{Growth Rate (\text{in \text{\text{%}}})}} \]
02

for Part (a) - Identify the Growth Rate

For the equation given: \( P = 2.1(1.0475)^t \), the annual growth rate is 4.75%. This is because the base of the exponential term is 1.0475, which means a growth rate of 4.75%.
03

for Part (a) - Apply the Rule of 70

Using the rule of 70, the doubling time can be calculated as: \[ \text{Doubling Time} = \frac{70}{4.75} \ \text{Doubling Time} \, \text{(in years)} = 14.74 \]
04

for Part (b) - Identify the Growth Rate

For the equation given: \( Q = 2.1(1.00475)^T \), the annual growth rate is 0.475%. This is because the base of the exponential term is 1.00475, which means a growth rate of 0.475%.
05

for Part (b) - Apply the Rule of 70

Using the rule of 70, the doubling time can be calculated as: \[ \text{Doubling Time} = \frac{70}{0.475} \ \text{Doubling Time} \, \text{(in years)} = 147.37 \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

rule of 70
The Rule of 70 is a simple method to estimate how long it will take for a quantity to double, given a consistent annual growth rate. This rule is particularly useful for understanding population growth, investments, or any scenario involving exponential growth. The formula is straightforward: divide 70 by the annual growth rate (expressed as a percentage).
For example, if a population grows at an annual rate of 5%, the doubling time is approximately:
\[ \text{Doubling Time} = \frac{70}{5} = 14\text{ years} \]
Always remember to check the growth rate format. If it’s 4.75%, use 4.75 directly, not as a decimal (0.0475). This rule serves as a quick estimate, not an exact calculation, but it is remarkably useful for making quick comparisons and forecasts.
exponential growth
Exponential growth describes a process where the quantity increases by a constant percentage each period. This is commonly seen in populations, finance, and even certain types of data increase. The general formula for exponential growth is:
\[ P(t) = P_0 \times (1 + r)^t \] where:
  • \( P(t) \) is the amount at time \( t \)
  • \( P_0 \) is the initial amount
  • \( r \) is the growth rate per period
  • \( t \) is the number of periods

Every period, such as every year, the quantity multiplies by \(1 + r\), making the growth ‘exponential.’ This kind of growth can lead to large numbers very quickly because you’re always adding a percentage of an ever-growing amount. For instance, a population of 1,000 growing at 5% per year becomes 1,050 after one year, 1,102.5 after two years, and so on. Understanding exponential growth is crucial for grasping concepts like doubling time and rates of increase.
annual growth rate
The annual growth rate is the percentage increase in a population or investment over the span of a year. It is a key variable in many financial, environmental, and demographic studies. To find the annual growth rate within equations like these:
\( P = 2.1(1.0475)^t \)
Look at the base of the exponential term. Here, 1.0475 means the annual growth rate is 4.75%. If this base were 1.00475, the growth rate would be 0.475%. Always convert the term immediately to a percentage by moving the decimal point two places to the right.
The annual growth rate helps in predicting how quickly something like a population or investment will grow over time and is an integral part of exponential growth calculations.

Key points to remember:
  • Identify the base of the exponential term
  • Convert the decimal to a percentage (e.g., 1.0475 becomes 4.75%)
population growth estimation
Estimating population growth can be essential for planning in areas like urban development, resource management, and public health. One common method to estimate this growth is through the exponential growth model, which assumes a constant rate of growth. Doubling time can also assist in these estimations. Using the rule of 70, you can estimate how long it will take for a population to double in size.
For instance, if you have an annual growth rate of 4.75%, the doubling time is calculated as:
\[ \text{Doubling Time} = \frac{70}{4.75} \text{ years} = 14.74 \text{ years} \]
Such estimates help policymakers and researchers make crucial decisions. Knowing that a population will double in about 14.74 years tells you when more resources, infrastructure, or services will be needed.
Key aspects include:
  • Understanding the growth rate
  • Using the rule of 70 for quick calculations
  • Predicting the timeline for future resource needs

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Most popular questions from this chapter

Lead- 206 is not radioactive, so it does not spontaneously decay into lighter elements. Radioactive elements heavier than lead undergo a series of decays, each time changing from a heavier element into a lighter or more stable one. Eventually, the element decays into lead- 206 and the process stops. So, over billions of years, the amount of lead in the universe has increased because of the decay of numerous radioactive elements produced by supernova explosions. Radioactive uranium- 238 decays sequentially into thirteen other lighter elements until it stabilizes at lead-206. The half-lives of the fifteen different elements in this decay chain vary from 0.000164 seconds (from polonium- 214 to lead- 210 ) all the way up to 4.47 billion years (from uranium- 238 to thorium- 234 ). a. Find the decay rate per billion years for uranium- 238 to decay into thorium- 234 . b. Find the decay rate per second for polonium-214 to decay into lead-2.10.

(Graphing program recommended.) Cosmic ray bombardment of the atmosphere produces neutrons, which in turn react with nitrogen to produce radioactive carbon-14. Radioactive carbon-14 enters all living tissue through carbon dioxide (via plants). As long as a plant or animal is alive, carbon-14 is maintained in the organism at a constant level. Once the organism dies, however, carbon-14 decays exponentially into carbon-12. By comparing the amount of carbon- 14 to the amount of carbon-12, one can determine approximately how long ago the organism died. Willard Libby won a Nobel Prize for developing this technique for use in dating archaeological specimens. The half-life of carbon-14 is about 5730 years. In answering the following questions, assume that the initial quantity of carbon- 14 is 500 milligrams. a. Construct an exponential function that describes the relationship between \(A,\) the amount of carbon- 14 in milligrams, and \(t,\) the number of 5730 -year time periods. b. Generate a table of values and plot the function. Choose a reasonable set of values for the domain. Remember that the objects we are dating may be up to 50,000 years old. c. From your graph or table, estimate how many milligrams are left after 15,000 years and after 45,000 years. d. Now construct an exponential function that describes the relationship between \(A\) and \(T,\) where \(T\) is measured in years. What is the annual decay factor? The annual decay rate? e. Use your function in part (d) to calculate the number of milligrams that would be left after 15,000 years and after 45,000 years.

Find \(C\) and \(a\) such that the function \(f(x)=C a^{x}\) satisfies the given conditions. a. \(f(0)=6\) and for each unit increase in \(x,\) the output is multiplied by 1.2 . b. \(f(0)=10\) and for each unit increase in \(x,\) the output is multiplied by 2.5

(Graphing program recommended.) On the same graph, sketch \(f(x)=3(1.5)^{x}, g(x)=-3(1.5)^{x},\) and \(h(x)=3(1.5)^{-x}\) a. Which graphs are mirror images of each other across the \(y\) -axis? b. Which graphs are mirror images of each other across the \(x\) -axis? c. Which graphs are mirror images of each other about the origin (i.e., you could translate one into the other by reflecting first about the \(y\) -axis, then about the \(x\) -axis)? d. What can you conclude about the graphs of the two functions \(f(x)=C a^{x}\) and \(g(x)=-C a^{x} ?\) e. What can you conclude about the graphs of the two functions \(f(x)=C a^{x}\) and \(g(x)=C a^{-x} ?\)

Two cities each have a population of 1.2 million people. City A is growing by a factor of 1.15 every 10 years, while city \(\mathbf{B}\) is decaying by a factor of 0.85 every 10 years. a. Write an exponential function for each city's population \(P_{A}(t)\) and \(P_{B}(t)\) after \(t\) years. b. For each city's population function generate a table of values for \(x=0\) to \(x=50,\) using 10 -year intervals, then sketch a graph of each town's population on the same grid.

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