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In medicine and biological research, radioactive substances are often used for treatment and tests. In the laboratories of a large East Coast university and medical center, any waste containing radioactive material with a half-life under 65 days must be stored for 10 half-lives before it can be disposed of with the non-radioactive trash. a. By how much does this policy reduce the radioactivity of the waste? b. Fill out the accompanying chart and develop a general formula for the amount of radioactive pollution at any period, given an initial amount, \(A_{0}\).

Short Answer

Expert verified
The policy reduces the radioactivity to \(\frac{1}{1024}\) of its initial amount. The general formula is \(A = A_{0} \times (\frac{1}{2})^{n}\).

Step by step solution

01

- Understanding Half-Life

The half-life of a substance is the period it takes for half of the radioactive material to decay. Therefore, after 1 half-life, half of the initial amount remains.
02

- Calculating Reduction after 10 Half-Lives

After 10 half-lives, the amount of radioactive material left is determined using the formula \(A = A_{0} \times (\frac{1}{2})^{n}\), where \(n\) is the number of half-lives. For 10 half-lives, \(A = A_{0} \times (\frac{1}{2})^{10}\).
03

- Simplifying the Formula

Simplify \((\frac{1}{2})^{10}\), which equals \(\frac{1}{1024}\). Thus, \(A = A_{0} \times \frac{1}{1024}\). This means the radioactivity is reduced to \(\frac{1}{1024}\) of its initial amount.
04

- Developing the General Formula

The general formula for the amount of radioactive material remaining after \(n\) half-lives is \(A = A_{0} \times (\frac{1}{2})^{n}\).
05

- Filling the Chart

To fill in the chart, calculate the remaining amount of radioactive material after each half-life using the formula \(A = A_{0} \times (\frac{1}{2})^{n}\). For each half-life, substitute the values of \(A_{0}\) and \(n\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Half-Life Calculation
The half-life of a radioactive substance is a key concept in understanding radioactive decay. It represents the time it takes for half of the initial amount of the substance to decay into another form. For example, if you start with 100 grams of a radioactive material with a half-life of 5 days, after 5 days, only 50 grams will remain. The remaining 50 grams will continue to decay, with half of it disappearing every subsequent half-life period.
To calculate how much of a substance remains after multiple half-life periods, use the formula:
\[ A = A_0 \times \left( \frac{1}{2} \right)^n \]
Where:
  • \(A\) is the remaining amount of the substance.
  • \
  • \(A_0\) is the initial amount of the substance.
  • \
  • \(n\) is the number of half-lives that have passed.
Example: After 3 half-lives, the remaining substance is \(A = A_0 \times \left( \frac{1}{2} \right)^3\).
Radioactivity Reduction
In the context of radioactive waste, reducing radioactivity makes disposal safer. If lab waste has a half-life of less than 65 days, it must be stored for 10 half-lives before it can be discarded as non-radioactive trash. This policy drastically lowers the radioactivity. After each half-life, the remaining radioactive material is halved.
For example, starting with an initial amount \(A_0\), after 1 half-life, only \(\frac{A_0}{2}\) remains. After 2 half-lives, it’s \(\frac{A_0}{4}\). After 10 half-lives, the waste is reduced to:
\[ \frac{A_0}{2^{10}} = \frac{A_0}{1024} \]
That’s less than 0.1% of the original radioactivity, meaning the material is significantly safer. This sharp decrease exemplifies how effectively time and proper storage reduce radioactive risks.
Exponential Decay
Radioactive decay follows an exponential pattern, meaning it decreases rapidly at first and then more slowly over time. Exponential decay can be described with the formula:
\[ A = A_0 \times e^{-\beta t} \]
Where:
  • \(A\) is the amount remaining.
  • \
  • \(A_0\) is the initial amount.
  • \
  • \(e\) is the base of the natural logarithm (approximately 2.718).
  • \
  • \(\beta\) is the decay constant.
  • \
  • \(t\) is the time elapsed.
However, for half-life calculations, the simpler formula \(A = A_0 \times (\frac{1}{2})^n\) is usually used because it’s easier to apply. The principle behind both formulas is the same: the quantity decreases by a constant percentage over equal time periods. Over 10 half-lives, as calculated, the remaining amount is \(\frac{A_0}{1024}\), demonstrating how powerful exponential decay is at reducing radioactivity quickly at first and then more gradually.

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Most popular questions from this chapter

Tritium, the heaviest form of hydrogen, is a critical element in a hydrogen bomb. It decays exponentially with a half-life of about 12.3 years. Any nation wishing to maintain a viable hydrogen bomb has to replenish its tritium supply roughly every 3 years, so world tritium supplies are closely watched. Construct an exponential function that shows the remaining amount of tritium as a function of time as 100 grams of tritium decays (about the amount needed for an average size bomb). Be sure to identify the units for your variables.

MCI, a phone company that provides long-distance service, introduced a marketing strategy called "Friends and Family." Each person who signed up received a discounted calling rate to ten specified individuals. The catch was that the ten people also had to join the "Friends and Family" program. a. Assume that one individual agrees to join the "Friends and Family" program and that this individual recruits ten new members, who in turn each recruit ten new members, and so on. Write a function to describe the number of new people who have signed up for "Friends and Family" at the \(n\) th round of recruiting. b. Now write a function that would describe the total number of people (including the originator) signed up after \(n\) rounds of recruiting. c. How many "Friends and Family" members. stemming from this one person, will there be after five rounds of recruiting? After ten rounds? d. Write a 60 -second summary of the pros and cons of this recruiting strategy. Why will this strategy eventually collapse?

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