/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 5 Construct both a linear and an e... [FREE SOLUTION] | 91Ó°ÊÓ

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Construct both a linear and an exponential function that go through the points (0,6) and (1,9) .

Short Answer

Expert verified
Linear function: \( y = 3x + 6 \). Exponential function: \( y = 6(1.5)^x \).

Step by step solution

01

Identify the Form of the Linear Function

The linear function will be in the form of \( y = mx + b \). Here, \( m \) is the slope of the line and \( b \) is the y-intercept.
02

Calculate the Slope

Use the formula for the slope \( m = \frac{y_2 - y_1}{x_2 - x_1} \). Using points \((0, 6)\) and \((1, 9)\), \( m = \frac{9 - 6}{1 - 0} = 3 \).
03

Determine the Y-Intercept

Substitute one of the points into the linear equation to find the y-intercept \( b \). Using the point \((0, 6)\), which is the y-intercept itself, we find \( b = 6 \).
04

Form the Linear Equation

Using \( m = 3 \) and \( b = 6 \), the linear function is \( y = 3x + 6 \).
05

Identify the Form of the Exponential Function

The exponential function will be in the form of \( y = ab^x \). Here, \( a \) and \( b \) are constants.
06

Determine the Value of \( a \)

Using the point \((0, 6)\), substitute \( x = 0 \) into the exponential function. Since \( y = 6 \), this gives \( 6 = ab^0 = a \). Therefore, \( a = 6 \).
07

Determine the Value of \( b \)

Using the point \((1, 9)\), substitute \( x = 1 \) into the exponential function. With \( y = 9 \), this gives \( 9 = 6b \). Solving for \( b \) yields \( b = \frac{9}{6} = 1.5 \).
08

Form the Exponential Equation

Using \( a = 6 \) and \( b = 1.5 \), the exponential function is \( y = 6(1.5)^x \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Slope
A key concept in understanding linear functions is the slope, denoted by the letter \(m\). The slope represents the rate of change between two variables. To put it simply, it tells us how much the \(y\)-value changes for every one unit increase in the \(x\)-value.
In the given exercise, we use the points \((0, 6)\) and \((1, 9)\) to find the slope. The formula for the slope is \(m = \frac{y_2 - y_1}{x_2 - x_1}\). Plugging in our points, we get \(m = \frac{9 - 6}{1 - 0} = 3\).
So, the slope \(m\) equals 3, meaning for every one unit increase in \(x\), the \(y\)-value increases by 3 units.
Knowing the slope helps us form the linear equation, integrating the change rate directly into our function.
Y-Intercept
Next, let's focus on the y-intercept, denoted by the letter \(b\). The y-intercept is the point where the line crosses the \(y\)-axis. This occurs when \(x = 0\).
In our exercise, one of the given points is \((0, 6)\). This automatically gives us the y-intercept value \(b = 6\).
To form the linear equation, we combine the slope and the y-intercept. With the slope \(m = 3\) and the y-intercept \(b = 6\), we get the linear equation as \(y = 3x + 6\).
The y-intercept helps us quickly determine the starting point of the function on the \(y\)-axis. This makes it easier to graph and understand the behavior of the linear function from its origin.
Exponential Function
Understanding exponential functions is crucial as well. An exponential function has the general form \(y = ab^x\), where \(a\) and \(b\) are constants. The \(a\) value is the initial amount or the y-intercept for \(x = 0\), and \(b\) is the base of the exponential, representing the growth factor.
To find \(a\), we use the point \((0, 6)\). Given \(y = 6\) when \(x = 0\), substituting these values gives us \(6 = ab^0 \). Since \(b^0 = 1\), we have \(a = 6\).
Next, to find \(b\), we use the point \((1, 9)\). Substituting into the exponential form, \(9 = 6b^1\). Solving for \(b\) gives us \(b = \frac{9}{6} = 1.5\).
Therefore, the exponential function is \( y = 6(1.5)^x \).
Exponential functions are powerful in modeling growth patterns, such as population growth, where values increase by a consistent percentage rather than a fixed amount.

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Most popular questions from this chapter

Two cities each have a population of 1.2 million people. City A is growing by a factor of 1.15 every 10 years, while city \(\mathbf{B}\) is decaying by a factor of 0.85 every 10 years. a. Write an exponential function for each city's population \(P_{A}(t)\) and \(P_{B}(t)\) after \(t\) years. b. For each city's population function generate a table of values for \(x=0\) to \(x=50,\) using 10 -year intervals, then sketch a graph of each town's population on the same grid.

On November \(25,2003,\) National Public Radio did a report on Under Armour, a sports clothing company, stating that their "profits have increased by \(1200 \%\) in the last 5 years." a. Let \(P(t)\) represent the profit of the company during every 5-year period, with \(A_{0}\) the initial amount. Write the exponential model for the company's profit. b. Assuming an initial profit of \(\$ 100,000,\) what would be the profit in year 5 ? Year \(10 ?\) c. Determine the \(a n n u a l\) growth rate for Under Armour.

In a chain letter one person writes a letter to a number of other people, \(N,\) who are each requested to send the letter to \(N\) other people, and so on. In a simple case with \(N=2\), let's assume person Al starts the process. Al sends to \(\mathrm{B} 1\) and \(\mathrm{B} 2 ; \mathrm{B} 1\) sends to \(\mathrm{C} 1\) and \(\mathrm{C} 2 ; \mathrm{B} 2\) sends to \(\mathrm{C} 3\) and \(\mathrm{C} 4\); and so on. A typical letter has listed in order the chain of senders who sent the letters. So \(\mathrm{D} 7\) receives a letter that has \(\mathrm{A} 1, \mathrm{~B} 2\), and \(\mathrm{C} 4\) listed. If these letters request money, they are illegal. A typical request looks like this: \(\cdot\) When you receive this letter, send \(\$ 10\) to the person on the top of the list. \(\cdot\) Copy this letter, but add your name to the bottom of the list and leave off the name at the top of the list. \(\cdot\) Send a copy to two friends within 3 days. For this problem, assume that all of the above conditions hold. a. Construct a mathematical model for the number of new people receiving letters at each level \(L,\) assuming \(N=2\) as shown in the above tree. b. If the chain is not broken, how much money should an individual receive? c. Suppose A 1 sent out letters with two additional phony names on the list (say Ala and Alb) with P.O. box addresses she owns. So both \(\mathrm{B} 1\) and \(\mathrm{B} 2\) would receive a letter with the list \(\mathrm{A} 1, \mathrm{~A} 1 \mathrm{a},\) Alb. If the chain isn't broken, how much money would Al receive? d. If the chain continued as described in part (a), how many new people would receive letters at level \(25 ?\) e. Internet search: Chain letters are an example of a "pyramid growth" scheme. A similar business strategy is multilevel marketing. This marketing method uses the customers to sell the product by giving them a financial incentive to promote the product to potential customers or potential salespeople for the product. (See Exercise \(31 .)\) Sometimes the distinction between multilevel marketing and chain letters gets blurred. Search the U.S. Postal Service website (www.usps.gov) for "pyramid schemes" to find information about what is legal and what is not. Report what you find.

Suppose you are given a table of values of the form \((x, y)\) where \(\Delta x,\) the distance between two consecutive \(x\) values, is constant. Why is calculating \(y_{2}-y_{1},\) the distance between two consecutive \(y\) values, equivalent to calculating the average rate of change between consecutive points?

The future value \(V\) of a savings plan, where regular payments \(P\) are made \(n\) times to an account in which the interest rate, \(i,\) is compounded each payment period, can be calculated using the formula $$ V=P \cdot \frac{(1+i)^{n}-1}{i} $$ The total number of payments, \(n,\) equals the number of payments per year, \(m,\) times the number of years, \(t,\) so $$ n=m \cdot t $$ The interest rate per compounding period, \(i\), equals the annual interest rate, \(r,\) divided by the number of compounding periods a year, \(m,\) so $$ i=r / m $$ a. Substitute \(n=m \cdot t\) and \(i=r / m\) in the formula for \(V\), getting an expression for \(V\) in terms of \(m, t,\) and \(r\). b. If a parent plans to build a college fund by putting \(\$ 50\) a month into an account compounded monthly with a \(4 \%\) annual interest rate, what will be the value of the account in 17 years? c. Solve the original formula for \(P\) as a function of \(V, i,\) and \(n\). d. Now you are able to find how much must be paid in every month to meet a particular final goal. If you estimate the child will need \(\$ 100,000\) for college, what monthly payment must the parent make if the interest rate is the same as in part (b)?

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