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The frequencies of subjects who have Hepatitis C and who do not are tabulated.

The frequencies are further divided into positive test results and negative test results.

The conditional probability of an event describes the likelihood of the event with reference to some prior condition.

The following is the expression to compute the conditional probability of B given A.

$P\left(B|A\right)=\frac{P\left(AandB\right)}{P\left(A\right)}$

Let A be the event of selecting a subject who has Hepatitis C.

Let B be the event of selecting a subject who does not have Hepatitis C.

Let C be the event of selecting a subject who has a positive test result.

Let D be the event of selecting a subject who has a negative test result.

The following table consists of the total frequency under each category:

The total number of subjects is equal to 1500.

The number of subjects who have Hepatitis C is 345.

The probability of selecting a subject who has Hepatitis C is given by:

$P\left(A\right)=\frac{345}{1500}$

The number of subjects who have Hepatitis C and tested negative is equal to 10.

The probability of selecting a subject who tested negative and has Hepatitis C is given by:

$P\left(AandD\right)=\frac{10}{1500}$

The probability of selecting a subject who tested negative, given that he/she has Hepatitis C, is calculated as follows:

$$\begin{gathered} P\left(D|A\right)=\frac{P\left(AandD\right)}{P\left(A\right)} \\ =\frac{\frac{10}{1500}}{\frac{345}{1500}} \\ =\frac{10}{345} \\ =0.0290 \end{gathered}$$

Therefore, the probability of selecting a subject who tested negative, given that he/she has Hepatitis C, is equal to 0.0290.

The event of testing negative, given that the subject has Hepatitis C, will delay the onset of the treatment of the disease and can worsen the health of the subject.