/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 3 Based on a Pitney Bowes survey, ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Based on a Pitney Bowes survey, when 1009 consumers were asked if they are comfortable with drones delivering their purchases, \(42 \%\) said yes. Consider the probability that among 30 different consumers randomly selected from the 1009 who were surveyed, there are at least 10 who are comfortable with the drones. Given that the subjects surveyed were selected without replacement, are the 30 selections independent? Can they be treated as being independent? Can the probability be found by using the binomial probability formula? Explain.

Short Answer

Expert verified
Yes, the selections can be treated as independent, and the binomial probability formula can be used.

Step by step solution

01

Analyze the Problem

First, identify what we are asked to determine. We need to check if the selections are independent and if the probability can be found using the binomial probability formula.
02

Understand Independence

For selections to be independent, the outcome of one selection must not affect another. In this case, the 30 consumers are chosen without replacement from 1009 consumers, which implies some dependency.
03

Apply the 5% Rule

When sampling without replacement, selections can be considered independent if the sample size is less than 5% of the population. Calculate if 30 is less than 5% of 1009. \[0.05 \times 1009 = 50.45 \] Since 30 is less than 50.45, the selections can be treated as independent.
04

Binomial Probability Formula Criteria

The binomial probability formula can be used if the trials are independent, and each trial results in a success or failure. Since we've established that the selections can be treated as independent, and each consumer's response (comfortable or not) fits the success/failure criterion, we can now check the binomial formula applicability.
05

Confirm the Use of Binomial Formula

Given the success probability (comfortable with drones) is 42%, or 0.42, and we can treat the trials as independent, the conditions for using the binomial probability formula are met. Thus, the probability can be found using the binomial probability formula.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Independence in Probability
In probability, two events are considered independent if the occurrence of one does not affect the occurrence of the other. In other words, the outcome of one trial does not influence the outcome of another trial. When you select 30 consumers from a group of 1009, you might initially think that since they are chosen without replacement, the trials are not independent. However, in many practical scenarios, we can apply a simplification rule that helps us treat the selections as independent. This brings us to the 5% rule in sampling.

Remember, ensuring independence simplifies calculations and models significantly, making our statistical analysis more straightforward. That’s why determining independence is crucial before proceeding further.
5% Rule in Sampling
The 5% rule in sampling states that when you are dealing with large populations, a sample can be considered independent if it is less than 5% of the total population, even when sampling without replacement. This is because the changes in probabilities are minimal and can be ignored for practical purposes.

Here's how this works for our problem:

  • First, we calculate 5% of the population (1009 consumers).Using the formula \[0.05 \times 1009 = 50.45\].
  • Then, we compare this result to our sample size (30 consumers). Since 30 is less than 50.45, we can treat these selections as independent.


With the 5% rule, even though we initially selected without replacement, the negligible effect on probabilities allows the simplification of treating selections as independent.
Binomial Probability Formula
The binomial probability formula is a key tool in statistics for calculating the probability of a given number of successes in a fixed number of independent trials. It is given by:

\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]

where:
  • \( P(X = k) \) is the probability of getting exactly \( k \) successes in \( n \) trials.
  • \( n \) is the number of trials.
  • \( k \) is the number of successes desired.
  • \( p \) is the probability of success on a single trial.


For our problem, we need to check whether this formula applies:
  • Are the trials independent? Using the 5% rule, we treated them as independent.
  • Are there only two possible outcomes (success or failure)? Yes, a consumer is either comfortable with drones (success) or not (failure).


Thus, by confirming these conditions, we can use the binomial probability formula to calculate the probability that at least 10 out of the 30 consumers are comfortable with drones from the given survey sample.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Use the Poisson distribution to find the indicated probabilities. Kicks A classical example of the Poisson distribution involves the number of deaths caused by horse kicks to men in the Prussian Army between 1875 and 1894 Data for 14 corps were combined for the 20 -year period, and the 280 corps- years included a total of 196 deaths. After finding the mean number of deaths per corps-year, find the probability that a randomly selected corps-year has the following numbers of deaths: (a) \(0,\) (b) \(1,\) (c) 2 , (d) \(3,(\mathrm{e})\) 4. The actual results consisted of these frequencies: 0 deaths (in 144 corps-years); 1 death (in 91 corps-years); 2 deaths (in 32 corps-ycars); 3 deaths (in 11 corps- years); 4 deaths (in 2 corps-years). Compare the actual results to those expected by using the Poisson probabilities. Does the Poisson distribution serve as a good tool for predicting the actual results?

Involve the method of composite sampling, whereby a medical testing laboratory saves time and money by combining blood samples for tests so that only one test is conducted for several people. A combined sample tests positive if at least one person has the disease. If a combined sample tests positive, then individual blood tests are used to identify the individual with the disease or disorder. Based on data from Bloodjournal.org, 10\% of women 65 years of age and older have anemia, which is a deficiency of red blood cells. In tests for anemia, blood samples from 8 women 65 and older are combined. What is the probability that the combined sample tests positive for anemia? Is it likely for such a combined sample to test positive?

For 100 births, \(P\) (exactly 56 girls) \(=0.0390\) and \(P(56 \text { or more girls) }=0.136\) Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question?

Refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable \(x\) represents the number of girls among 8 children. $$\begin{array}{|c|c|} \hline \begin{array}{c} \text { Number of } \\ \text { Girls } \boldsymbol{x} \end{array} & \boldsymbol{P}(\boldsymbol{x}) \\ \hline 0 & 0.004 \\ \hline 1 & 0.031 \\ \hline 2 & 0.109 \\ \hline 3 & 0.219 \\ \hline 4 & 0.273 \\ \hline 5 & 0.219 \\ \hline 6 & 0.109 \\ \hline 7 & 0.031 \\ \hline 8 & 0.004 \\ \hline \end{array}$$ a. Find the probability of getting exactly 1 girl in 8 births. b. Find the probability of getting 1 or fewer girls in 8 births. c. Which probability is relevant for determining whether 1 is a significantly low number of girls in 8 births: the result from part (a) or part (b)? d. Is 1 a significantly low number of girls in 8 births? Why or why not?

If a procedure meets all the conditions of a binomial distribution except that the number of trials is not fixed, then the geometric distribution can be used. The probability of getting the first success on the \(x\) th trial is given by \(P(x)=p(1-p)^{x-1},\) where \(p\) is the probability of success on any one trial. Subjects are randomly selected for the National Health and Nutrition Examination Survey conducted by the National Center for Health Statistics, Centers for Disease Control and Prevention. The probability that someone is a universal donor (with group \(\mathrm{O}\) and type Rh negative blood) is \(0.06 .\) Find the probability that the first subject to be a universal blood donor is the fifth person selected.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.