/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 41 If a procedure meets all the con... [FREE SOLUTION] | 91Ó°ÊÓ

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If a procedure meets all the conditions of a binomial distribution except that the number of trials is not fixed, then the geometric distribution can be used. The probability of getting the first success on the \(x\) th trial is given by \(P(x)=p(1-p)^{x-1},\) where \(p\) is the probability of success on any one trial. Subjects are randomly selected for the National Health and Nutrition Examination Survey conducted by the National Center for Health Statistics, Centers for Disease Control and Prevention. The probability that someone is a universal donor (with group \(\mathrm{O}\) and type Rh negative blood) is \(0.06 .\) Find the probability that the first subject to be a universal blood donor is the fifth person selected.

Short Answer

Expert verified
The probability is approximately 0.0468.

Step by step solution

01

Identify the known values

Identify the probability of success, which is the probability that a person is a universal donor. Given: \( p = 0.06 \). Also identify \( x \), the number of trials needed for the first success. Given: \( x = 5 \).
02

Write down the formula for the geometric distribution

The probability of getting the first success on the \( x \)th trial for a geometric distribution is given by: \[ P(x) = p (1 - p)^{x-1} \].
03

Substitute the known values into the formula

Substitute \( p = 0.06 \) and \( x = 5 \) into the formula: \[ P(5) = 0.06 (1 - 0.06)^{5-1} \].
04

Simplify the expression

First, calculate \( 1 - 0.06 \): \( 1 - 0.06 = 0.94 \). Then calculate \( 0.94^{4} \): \[ 0.94^{4} \approx 0.78 \]. Now multiply by 0.06: \[ P(5) = 0.06 \times 0.78 \approx 0.0468 \].
05

State the final probability

The probability that the first subject to be a universal blood donor is the fifth person selected is approximately 0.0468.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

probability of success
In statistics, the probability of success (denoted as \( p \)) is the chance of a particular event happening in one trial. For instance, if you're rolling a die, the probability of rolling a number greater than 3 (4, 5, or 6) is 0.5. In our exercise, we're interested in finding a universal donor. This is someone with group O and Rh-negative blood, a rare type with a probability of 0.06. The formula for a geometric distribution, which is used when identifying the first successful event in a series of otherwise independent trials, relies heavily on this probability of success. The formula is given by \( P(x) = p(1 - p)^{x-1} \), where \( x \) is the trial occurrence.
binomial distribution
The binomial distribution is used when you deal with a fixed number of trials, each with the same probability of success. Imagine flipping a coin 10 times and recording heads (H) and tails (T). Here, each flip is a trial, and the probability of success (getting heads) is 0.5 in each trial. However, if you do not fix the number of trials but look for the first success, the geometric distribution steps in. While both distributions involve repeated trials and a probability of success, they differ in the end goal. The binomial distribution counts successes in a set number of trials, and the geometric distribution seeks the first success in a possibly infinite series of trials.
National Health and Nutrition Examination Survey
The National Health and Nutrition Examination Survey (NHANES) collects various health-related data in the United States. Conducted by the National Center for Health Statistics (NCHS) and managed by the Centers for Disease Control and Prevention (CDC), NHANES helps monitor the health and nutritional statuses of the U.S. population. Participants are chosen randomly, ensuring that the data adequately represent the entire population. In our example, survey subjects are tested to identify universal donors. This population diversity makes NHANES a reliable source for understanding health and nutritional parameters across different demographics.
universal blood donor
A universal blood donor is someone with blood group O and Rh-negative type. This rare type is critical in emergencies since O negative (O-) blood can be received by any individual, regardless of their blood type. The probability of a person being a universal donor is low, typically around 0.06 or 6%. Finding the first universal donor in a sequential selection of subjects can be mathematically modeled using a geometric distribution. Each new person selected is an independent trial with a constant probability of 0.06, aiming to spot the first successful match—our universal donor.

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Most popular questions from this chapter

For 100 births, \(P\) (exactly 56 girls) \(=0.0390\) and \(P(56 \text { or more girls) }=0.136\) Is 56 girls in 100 births a significantly high number of girls? Which probability is relevant to answering that question?

Involve finding binomial probabilities, finding parameters, and determining whether values are significantly high or low by using the range rule of thumb and probabilities. Data Set 27 "M\&M Weights" in Appendix B includes data from 100 M\&M candies, and 19 of them are green. Mars, Inc. claims that \(16 \%\) of its plain M\&M candies are green. For the following, assume that the claim of \(16 \%\) is true, and assume that a sample consists of \(100 \mathrm{M} \& \mathrm{Ms}\). a. Use the range rule of thumb to identify the limits separating values that are significantly low and those that are significantly high. Based on the results, is the result of 19 green \(\mathrm{M} \& \mathrm{Ms}\) significantly high? b. Find the probability of exactly 19 green M\&Ms. c. Find the probability of 19 or more green M\&Ms. d. Which probability is relevant for determining whether the result of 19 green \(\mathrm{M} \& \mathrm{Ms}\) is significantly high: the probability from part (b) or part (c)? Based on the relevant probability, is the result of 19 green M\&Ms significantly high? e. What do the results suggest about the \(16 \%\) claim by Mars, Inc.?

Find the probabilities and answer the questions. A survey sponsored by the Vision Council showed that \(79 \%\) of adults need correction (eyeglasses, contacts, surgery, etc.) for their eyesight. If 20 adults are randomly selected, find the probability that at least 19 of them need correction for their eyesight. Is 19 a significantly high number of adults requiring eyesight correction?

Involve finding binomial probabilities, finding parameters, and determining whether values are significantly high or low by using the range rule of thumb and probabilities. One of Mendel's famous experiments with peas resulted in 580 offspring, and 152 of them were yellow peas. Mendel claimed that under the same conditions, \(25 \%\) of offspring peas would be yellow. Assume that Mendel's claim of \(25 \%\) is true, and assume that a sample consists of 580 offspring peas. a. Use the range rule of thumb to identify the limits separating values that are significantly low and those that are significantly high. Based on the results, is the result of 152 yellow peas either significantly low or significantly high? b. Find the probability of exactly 152 yellow peas. c. Find the probability of 152 or more yellow peas. d. Which probability is relevant for determining whether 152 peas is significantly high: the probability from part (b) or part (c)? Based on the relevant probability, is the result of 152 yellow peas significantly high? e. What do the results suggest about Mendel's claim of \(25 \% ?\)

Refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable \(x\) represents the number of girls among 8 children. $$\begin{array}{|c|c|} \hline \begin{array}{c} \text { Number of } \\ \text { Girls } \boldsymbol{x} \end{array} & \boldsymbol{P}(\boldsymbol{x}) \\ \hline 0 & 0.004 \\ \hline 1 & 0.031 \\ \hline 2 & 0.109 \\ \hline 3 & 0.219 \\ \hline 4 & 0.273 \\ \hline 5 & 0.219 \\ \hline 6 & 0.109 \\ \hline 7 & 0.031 \\ \hline 8 & 0.004 \\ \hline \end{array}$$ Use the range rule of thumb to determine whether 6 girls in 8 births is a significantly high number of girls.

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