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Refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable \(x\) represents the number of girls among 8 children. $$\begin{array}{|c|c|} \hline \begin{array}{c} \text { Number of } \\ \text { Girls } \boldsymbol{x} \end{array} & \boldsymbol{P}(\boldsymbol{x}) \\ \hline 0 & 0.004 \\ \hline 1 & 0.031 \\ \hline 2 & 0.109 \\ \hline 3 & 0.219 \\ \hline 4 & 0.273 \\ \hline 5 & 0.219 \\ \hline 6 & 0.109 \\ \hline 7 & 0.031 \\ \hline 8 & 0.004 \\ \hline \end{array}$$ Use the range rule of thumb to determine whether 6 girls in 8 births is a significantly high number of girls.

Short Answer

Expert verified
6 girls in 8 births is not significantly high.

Step by step solution

01

Determine the Mean

Calculate the mean of the distribution using the formula \(\text{mean} = \text{n} \times \text{p}\). Here, \(n = 8\) and \(p = 0.5\) (as the probability of having a girl is typically 0.5). Hence, \( \text{mean} = 8 \times 0.5 = 4 \).
02

Determine the Standard Deviation

Calculate the standard deviation using the formula \( \text{standard deviation} = \sqrt{ \text{n} \times \text{p} \times (1 - \text{p}) } \). Plugging in the values, we get \(\text{standard deviation} = \sqrt{8 \times 0.5 \times 0.5} = \sqrt{2} \approx 1.414 \).
03

Calculate Significantly High Value

Using the range rule of thumb, a value is significantly high if it is greater than \( \text{mean} + 2 \times \text{standard deviation} \). Calculate this as follows: \(\text{mean} + 2 \times \text{standard deviation} = 4 + 2 \times 1.414 = 4 + 2.828 = 6.828\).
04

Compare to Given Value

Compare the number of girls (6) to the significantly high value (6.828). Since 6 is less than 6.828, 6 girls in 8 births is not considered significantly high.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean
The mean, often referred to as the average, gives us an idea of the central value of a set of numbers. In statistics, the mean is calculated by adding all of the numbers in a dataset together and then dividing by the number of numbers in the set. Here, for the problem involving 8 births, we determined the mean using the formula \(\text{mean} = \text{n} \times \text{p}\). Since the probability \(\text{p}\) of having a girl is typically 0.5, and there are 8 children (\(\text{n} = 8\)), the mean number of girls among these children is calculated as follows: \[\text{mean} = 8 \times 0.5 = 4\ \]. This means, on average, we expect to have 4 girls in 8 births.
Standard Deviation
The standard deviation measures the amount of variation or dispersion in a dataset. In simple terms, it tells us how spread out the values in a dataset are around the mean. A low standard deviation means that the values are close to the mean, while a high standard deviation indicates that the values are spread out over a wider range. For our exercise, we calculate the standard deviation using the formula \( \text{standard deviation} = \sqrt{ \text{n} \times \text{p} \times (1 - \text{p})} \). Plugging in our values, we have \[\text{standard deviation} = \sqrt{8 \times 0.5 \times 0.5} = \sqrt{2} \approx 1.414 \]. This tells us that the number of girls in a subset of 8 births can vary by approximately 1.414 around the mean of 4.
Binomial Distribution
A binomial distribution is a discrete probability distribution that summarizes the likelihood that a value will take one of two independent states across a series of observations. This is applicable when there are two possible outcomes, such as success and failure. In our scenario, the two outcomes are having a girl or not having a girl (which we'll call having a boy), with the probability \(\text{p} = 0.5\) for each birth. The binomial distribution formula helps us determine the probability of achieving a fixed number of successes (girls in this case) in a specified number of trials (births). We can summarize the key properties of a binomial distribution as:
  • Fixed number of trials (n).
  • Two possible outcomes for each trial.
  • A constant probability of success (p) for each trial.
  • Independent trials where previous outcomes don't affect future ones.
In our problem, we use the provided probabilities from the table to analyze the outcomes in groups of 8 births.
Probability
Probability is a measure of how likely an event is to occur. It ranges from 0 (impossible event) to 1 (certain event). We use probability to assess the chance of various outcomes in statistical experiments. For example, the probability of having a girl in a single birth is \(\text{p} = 0.5\). Probability helps us make predictions about future events based on known data. In the context of our problem, the probability (\tabs{P}{x}}) for each possible number of girls (\(\text{x})\), such as 0, 1, 2,...,8, has been provided. Using these probabilities, we can assess how likely it is to have, for example, exactly 6 girls in 8 births. By comparing the probability of 6 girls with other values, we observed that while having 6 girls is unusual, it is not significantly high because it falls within the expected range defined by our calculation of mean and standard deviation.

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Most popular questions from this chapter

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