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Refer to the accompanying table, which describes results from groups of 8 births from 8 different sets of parents. The random variable \(x\) represents the number of girls among 8 children. $$\begin{array}{|c|c|} \hline \begin{array}{c} \text { Number of } \\ \text { Girls } \boldsymbol{x} \end{array} & \boldsymbol{P}(\boldsymbol{x}) \\ \hline 0 & 0.004 \\ \hline 1 & 0.031 \\ \hline 2 & 0.109 \\ \hline 3 & 0.219 \\ \hline 4 & 0.273 \\ \hline 5 & 0.219 \\ \hline 6 & 0.109 \\ \hline 7 & 0.031 \\ \hline 8 & 0.004 \\ \hline \end{array}$$ a. Find the probability of getting exactly 1 girl in 8 births. b. Find the probability of getting 1 or fewer girls in 8 births. c. Which probability is relevant for determining whether 1 is a significantly low number of girls in 8 births: the result from part (a) or part (b)? d. Is 1 a significantly low number of girls in 8 births? Why or why not?

Short Answer

Expert verified
a. 0.031, b. 0.035, c. Part (b), d. Yes, because 0.035 < 0.05.

Step by step solution

01

Finding probability of exactly 1 girl

From the table, find the probability corresponding to exactly 1 girl. The probability is directly given as \(P(1) = 0.031\).
02

Finding probability of 1 or fewer girls

Add the probabilities of getting 0 and 1 girls from the table: \(P(0) + P(1) = 0.004 + 0.031 = 0.035\).
03

Identifying relevant probability for significance

To determine if 1 girl is a significantly low number, use the cumulative probability of getting 1 or fewer girls (from part b) as it shows the likelihood of that outcome or more extreme ones.
04

Determining if 1 girl is significantly low

Compare the cumulative probability (from part b) with a significance threshold, often 0.05. Since \(0.035 < 0.05\), 1 girl is considered a significantly low number of girls in 8 births.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Distribution
In the exercise, we deal with a binomial probability distribution. Here, the random variable \(x\) represents the number of girls among 8 births. A probability distribution lists all possible outcomes of a random variable and the corresponding probabilities for each outcome.
For instance, our table shows various outcomes, from having 0 girls to having 8 girls. Each outcome has an associated probability. The probabilities are crucial as they sum up to 1. This property ensures that one of the outcomes will definitely occur.
Understanding a probability distribution helps us answer specific questions. For example, to find the probability of getting exactly 1 girl, we simply look up \(P(1)\) in the table, which is 0.031. This means there’s a 3.1% chance of having exactly 1 girl out of 8 births.
Cumulative Probability
Cumulative probability helps us determine the probability of a random variable falling within a certain range. It’s the sum of the probabilities of outcomes up to and including a specific value.
In our exercise, calculating the cumulative probability is essential for part (b). To find the probability of getting 1 or fewer girls, we add the probabilities of getting exactly 0 girls and exactly 1 girl. From the table: \(P(0) + P(1) = 0.004 + 0.031 = 0.035\).
This result tells us that there’s a 3.5% chance of having 1 or fewer girls among 8 births. This cumulative probability is valuable especially when assessing the likelihood of multiple events.
Significance Testing
Significance testing helps determine if an observed result is unusual or noteworthy in context. We use it to decide if an outcome is significantly different from what we would expect under normal circumstances.
In part (c) of the exercise, we need to examine whether 1 girl out of 8 births is statistically significant. The relevant probability here is the cumulative probability from part (b), which is 0.035.
We compare this cumulative probability to a threshold value, often set at 0.05. If the probability is below this threshold, the result is considered statistically significant. In our case, since 0.035 < 0.05, having 1 girl is seen as a significantly low number among 8 births.
Random Variables
Random variables represent outcomes of a random process. In the exercise, our random variable \(x\) denotes the number of girls among 8 births. It can take on any integer value from 0 to 8.
Random variables can be discrete or continuous. Here, \(x\) is discrete because it takes on specific values (whole numbers). Understanding random variables helps us assign probabilities and analyze outcomes.
For example, knowing \(x\) can range from 0 to 8, each with a corresponding probability, allows us to answer various questions about the births. Whether we're calculating the likelihood of having a certain number of girls or if an observed result is significant, the concept of random variables is deeply integrated into these analyses.

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Most popular questions from this chapter

If we sample from a small finite population without replacement, the binomial distribution should not be used because the events are not independent. If sampling is done without replacement and the outcomes belong to one of two types, we can use the hypergeometric distribution. If a population has \(A\) objects of one type (such as lottery numbers you selected), while the remaining \(B\) objects are of the other type (such as lottery numbers you didn't select), and if \(n\) objects are sampled without replacement (such as six drawn lottery numbers), then the probability of getting \(x\) objects of type \(A\) and \(n-x\) objects of type \(B\) is $$P(x)=\frac{A !}{(A-x) ! x !} \cdot \frac{B !}{(B-n+x) !(n-x) !} \div \frac{(A+B) !}{(A+B-n) ! n !}$$ In New Jersey's Pick 6 lottery game, a bettor selects six numbers from 1 to 49 (without repetition), and a winning six-number combination is later randomly selected. Find the probabilities of getting exactly two winning numbers with one ticket. (Hint: Use \(A=6, B=43, n=6\) and \(x=2 .\))

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviation. If a probability distribution is not given, identify the requirements that are not satisfied. Groups of adults are randomly selected and arranged in groups of three. The random variable \(x\) is the number in the group who say that they would feel comfortable in a selfdriving vehicle (based on a TE Connectivity survey). $$\begin{array}{|c|c|} \hline x & P(x) \\ \hline 0 & 0.358 \\ \hline 1 & 0.439 \\ \hline 2 & 0.179 \\ \hline 3 & 0.024 \\ \hline \end{array}$$

Assume that when adults with smartphones are randomly selected, \(54 \%\) use them in meetings or classes (based on data from an LG Smartphone survey). If 12 adult smartphone users are randomly selected, find the probability that fewer than 3 of them use their smartphones in meetings or classes.

Involve finding binomial probabilities, finding parameters, and determining whether values are significantly high or low by using the range rule of thumb and probabilities. In a presidential election, 611 randomly selected voters were surveyed, and 308 of them said that they voted for the winning candidate (based on data from ICR Survey Research Group). The actual percentage of votes for the winning candidate was \(43 \%\). Assume that \(43 \%\) of voters actually did vote for the winning candidate, and assume that 611 voters are randomly selected. a. Use the range rule of thumb to identify the limits separating values that are significantly low and those that are significantly high. Based on the results, is the 308 voters who said that they voted for the winner significantly high? b. Find the probability of exactly 308 voters who actually voted for the winner. c. Find the probability of 308 or more voters who actually voted for the winner. d. Which probability is relevant for determining whether the value of 308 voters is significantly high: the probability from part (b) or part (c)? Based on the relevant probability, is the result of 308 voters who said that they voted for the winner significantly high? e. What is an important observation about the survey results?

Refer to the accompanying table, which describes the numbers of adults in groups of five who reported sleepwalking (based on data from "Prevalence and Comorbidity of Nocturnal Wandering In the U.S. Adult General Population," by Ohayon et al., Neurology, Vol. 78, No. 20). $$\begin{array}{|c|c|} \hline x & P(x) \\ \hline 0 & 0.172 \\ \hline 1 & 0.363 \\ \hline 2 & 0.306 \\ \hline 3 & 0.129 \\ \hline 4 & 0.027 \\ \hline 5 & 0.002 \\ \hline \end{array}$$ Find the mean and standard deviation for the numbers of sleepwalkers in groups of five.

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