/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 21 Assume that when adults with sma... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Assume that when adults with smartphones are randomly selected, \(54 \%\) use them in meetings or classes (based on data from an LG Smartphone survey). If 8 adult smartphone users are randomly selected, find the probability that exactly 6 of them use their smartphones in meetings or classes.

Short Answer

Expert verified
The probability is approximately 0.275.

Step by step solution

01

Identify the type of probability distribution

This problem involves a fixed number of independent trials (8 adults) and a constant probability of success (54%). Therefore, it follows a binomial distribution.
02

Define the binomial distribution parameters

The number of trials (n) is 8 and the probability of success (p) is 0.54. We want to find the probability of exactly 6 successes (k=6).
03

Use the binomial probability formula

The binomial probability formula is given by \[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \( \binom{n}{k} \) is the combination of n items taken k at a time.
04

Calculate the combination \( \binom{8}{6} \)

\[ \binom{8}{6} = \frac{8!}{6!(8-6)!} = \frac{8!}{6!2!} = \frac{8 \times 7}{2 \times 1} = 28 \]
05

Calculate the probability

Substitute the values into the binomial probability formula: \[ P(X = 6) = 28 \times (0.54)^6 \times (0.46)^2 \]Compute the terms:\[ (0.54)^6 \approx 0.046656 \]\[ (0.46)^2 = 0.2116 \]Now multiply these terms:\[ P(X = 6) \approx 28 \times 0.046656 \times 0.2116 \approx 0.275 \]

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Probability
To understand binomial probability, consider a scenario where you perform several independent experiments and want to know the likelihood of a certain number of successes. A **binomial experiment** must satisfy the following conditions:
- Fixed number of trials
- Each trial has just two possible outcomes (success and failure)
- Probability of success is the same on every trial
- Trials are independent
In our example, we look at whether an adult with a smartphone uses it in meetings or classes.
We want to find out the probability of exactly 6 out of 8 adults using their smartphones in such settings.
Binomial Distribution
A **binomial distribution** describes the number of successes in a fixed number of independent trials of a binary experiment. It is characterized by two parameters:
- The number of trials ()
- The probability of success in each trial (p)
In our problem, we have 8 trials (adults) and a 0.54 probability of success.
We are to find the probability that exactly 6 out of these 8 adults use their smartphones in meetings or classes.
Probability Calculation
For calculating the probability of exactly 6 successes out of 8 trials, we employ the **binomial probability formula**:
\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \] where \( \binom{n}{k} \) represents combinations. In our case:
- \( n = 8 \) (adults)
- \( k = 6 \) (using smartphones in meetings or classes)
- \( p = 0.54 \) (probability of using smartphones)
To compute the combination \( \binom{8}{6} = 28 \) and then substitute into the formula:
\[ P(X = 6) = 28 \times (0.54)^6 \times (0.46)^2 \]
Plugging these values: \( p^6 \approx 0.046656 \) and \( (0.46)^2 = 0.2116 \)
Consequently:
\[ P(X = 6) \approx 0.275 \]
Statistics in Education
Learning about probabilities and distributions, like the binomial distribution, is essential in the field of statistics. It provides insights that are valuable in various disciplines, including education.
Statistics help educators and researchers make informed decisions by understanding data patterns.
Knowing these basic probability concepts empowers students to apply them in practical situations, such as predicting test outcomes or analyzing survey data.
For instance, in our current example, understanding the **binomial distribution** and using the formula, we are able to assess the likelihood that a specific number of people will exhibit a behavior, given our fixed parameters and conditions.
Such skills are vital for conducting educational research and improving teaching methodologies.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

If a procedure meets all the conditions of a binomial distribution except that the number of trials is not fixed, then the geometric distribution can be used. The probability of getting the first success on the \(x\) th trial is given by \(P(x)=p(1-p)^{x-1},\) where \(p\) is the probability of success on any one trial. Subjects are randomly selected for the National Health and Nutrition Examination Survey conducted by the National Center for Health Statistics, Centers for Disease Control and Prevention. The probability that someone is a universal donor (with group \(\mathrm{O}\) and type Rh negative blood) is \(0.06 .\) Find the probability that the first subject to be a universal blood donor is the fifth person selected.

Determine whether the given procedure results in a binomial distribution (or a distribution that can be treated as binomial. For those that are not binomial, identify at least one requirement that is not satisfied. In a survey sponsored by TGI Friday's, 1000 different adult respondents were randomly selected without replacement, and each was asked if they investigate dates on social media before meeting them. Responses consist of "yes" or "no."

The binomial distribution applies only to cases involving two types of outcomes, whereas the multinomial distribution involves more than two categories. Suppose we have three types of mutually exclusive outcomes denoted by A, B, and C. Let \(P(\mathrm{A})=p_{1}, P(\mathrm{B})=p_{2},\) and \(P(\mathrm{C})=p_{3} .\) In \(n\) independent trials, the probability of \(x_{1}\) outcomes of type \(A, x_{2}\) outcomes of type \(B\), and \(x_{3}\) outcomes of type \(C\) is given by $$\frac{n !}{\left(x_{1}\right) !\left(x_{2}\right) !\left(x_{3}\right) !} \cdot p_{1}^{x_{1}} \cdot p_{2}^{x_{2}} \cdot p_{3}^{x_{3}}$$ A roulette wheel in the Venetian casino in Las Vegas has 18 red slots, 18 black slots, and 2 green slots. If roulette is played 15 times, find the probability of getting 7 red outcomes, 6 black outcomes, and 2 green outcomes.

Assume that when adults with smartphones are randomly selected, \(54 \%\) use them in meetings or classes (based on data from an LG Smartphone survey). If 12 adult smartphone users are randomly selected, find the probability that fewer than 3 of them use their smartphones in meetings or classes.

Refer to the accompanying table, which describes the numbers of adults in groups of five who reported sleepwalking (based on data from "Prevalence and Comorbidity of Nocturnal Wandering In the U.S. Adult General Population," by Ohayon et al., Neurology, Vol. 78, No. 20). $$\begin{array}{|c|c|} \hline x & P(x) \\ \hline 0 & 0.172 \\ \hline 1 & 0.363 \\ \hline 2 & 0.306 \\ \hline 3 & 0.129 \\ \hline 4 & 0.027 \\ \hline 5 & 0.002 \\ \hline \end{array}$$ Find the mean and standard deviation for the numbers of sleepwalkers in groups of five.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.