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Determine the critical values that would be used for the following hypothesis tests (using the classical approach) about the difference between two means with population variances unknown. a. \(\quad H_{a}: \mu_{1}-\mu_{2} \neq 0, n_{1}=26, n_{2}=16, \alpha=0.05\) b. \(\quad H_{a}: \mu_{1}-\mu_{2}<0, n_{1}=36, n_{2}=27, \alpha=0.01\) c. \(\quad H_{a}: \mu_{1}-\mu_{2}>0, n_{1}=8, n_{2}=11, \alpha=0.10\) d. \(\quad H_{a}: \mu_{1}-\mu_{2} \neq 10, n_{1}=14, n_{2}=15, \alpha=0.05\)

Short Answer

Expert verified
The critical values for the four cases are: a. ±2.021; b. -2.391; c. 1.337; d: ± 2.052.

Step by step solution

01

Find the degrees of freedom

Degrees of freedom are calculated as \(df = n_{1} + n_{2} - 2\). It's important to note, the value from the t table will depend on the degrees of freedom and the level of significance. For a:\(df_{a} = 26 + 16 - 2 = 40\)For b: \(df_{b} = 36 + 27 - 2 = 61\)For c: \(df_{c} = 8 + 11 - 2 = 17\)For d: \(df_{d} = 14 + 15 - 2 = 27\)
02

Identify the level of significance and type of test

The level of significance is given by \(\alpha\), here different for each case. Test type – one-tailed or two-tailed – depends on the alternative hypothesis \(H_{a}\). For 'less than' or 'greater than' it is one-tailed. For 'not equal to' it is two-tailed.
03

Find the critical t values from the t-table

Using a t-table, find the value corresponding to each of these degrees of freedom and significance levels, also noting the test type for each case. For a two-tailed test, use \(\alpha/2\) while for a one-tailed test use \(\alpha\). Critical t-values will be positive for \(>\) and \(\neq\) cases, and negative for \(<\) cases.
04

Express the results

Record the critical t value for each case. It’s needed to make decision about the null hypothesis.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Critical Values
Critical values are thresholds that define the boundaries for the region where the test statistic would lead to the rejection of the null hypothesis. In hypothesis testing, the idea is to determine whether there's enough evidence to reject a null hypothesis in favor of an alternative hypothesis. To find these critical values, which serve as cut-off points, one uses a statistical distribution, such as the t-distribution in the case of a t-test. The critical values are dependent on the desired level of significance and the test type (one-tailed or two-tailed).
For a two-tailed test, you would find two critical values (one positive and one negative) that represent both ends of the distribution, whereas for a one-tailed test, only one critical value is required. This is because a one-tailed test is concerned with an effect in one direction only. For instance, if you are testing whether one mean is greater than the other (a 'greater than' alternative hypothesis), then you would only look for the critical value where the test statistic would have to exceed to reject the null hypothesis.
Degrees of Freedom
Degrees of freedom (df) in statistics refer to the number of independent values in a calculation that can vary without violating any given constraints. In the context of the t-test, the degrees of freedom are calculated by subtracting 2 from the sum of the sample sizes of both groups. This formula, represented as \(df = n_{1} + n_{2} - 2\), accounts for the fact that the means of the two groups use up some of the freedom to vary.
In the context of hypothesis testing, degrees of freedom are important because they impact the shape of the t-distribution, which in turn affects the critical values. The t-distribution varies in shape based on the degrees of freedom; it is wider with heavier tails for smaller sample sizes and becomes more similar to the normal distribution as the degrees of freedom increase. Therefore, the degrees of freedom must be taken into account when looking up the critical t-value in a t-table to ensure the correctness of the hypothesis test.
T-Test
The t-test is a statistical analysis used to determine if there is a significant difference between the means of two groups which may be related in certain features. It is mostly used when the test statistic follows a normal distribution and the value of a scaling term in the test statistic (standard deviation) is unknown, prompting the use of the t-distribution instead of the normal distribution.
T-tests are divided into different types depending on the nature of the data and the hypothesis. For instance, an independent samples t-test looks at the differences in means between two unrelated groups, which is the case with the problem we are examining. The computation of the t-test involves the calculation of a t-value from the provided data, which is then compared against the critical t-value. If the calculated t-value is more extreme than the critical t-value (taking into account the type of test and degree of freedom), then the null hypothesis can be rejected, indicating a statistically significant difference between the group means.
Level of Significance
The level of significance, denoted as \(\alpha\), is a threshold chosen by the researcher that determines the probability of rejecting the null hypothesis when it is actually true, which is known as a Type I error. In simpler terms, it's the risk one is willing to take of making a mistake by saying there is an effect or a difference when there is none.
The level of significance is arbitrary, but common choices are 0.05, 0.01, and 0.10. This value directly influences the critical values: the smaller the \(\alpha\), the further away the critical value will be from zero, making it less likely to reject the null hypothesis. It reflects how stringent or lenient the researcher is about making errors. When you choose a smaller level of significance, you are saying that you require more evidence (a more extreme test statistic) to reject the null hypothesis, which could protect you from a Type I error but also makes it harder to detect a true effect (increasing the risk of a Type II error).

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Most popular questions from this chapter

The proportions of defective parts produced by two machines were compared, and the following data were collected: Machine \(1: n=150 ;\) number of defective parts \(=12\) Machine \(2: n=150:\) number of defective parts \(=6\) Determine a \(90 \%\) confidence interval for \(p_{1}-p_{2}\).

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