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91Ó°ÊÓ

Many cheeses are produced in the shape of a wheel, and due to manufacturing inconsistencies, the amount of cheese, measured by weight, varies from wheel to wheel. Heidi Cembert wishes to determine if there is a significant difference, at the \(10 \%\) level, between the weight per wheel of Gouda and Brie cheese. She randomly samples 16 wheels of Gouda and finds the mean to be 1.2 pounds with a standard deviation of 0.32 pound and then samples 14 wheels of Brie and finds the mean to be 1.05 pounds with a standard deviation of 0.25 pound. At the 0.05 level of significance, is there sufficient evidence to support Heidi's contention that there is a difference in the mean weights of the two types of cheese?

Short Answer

Expert verified
Yes, based on the statistical analysis, there is a significant difference in the mean weights of Gouda cheese and Brie cheese at the 10% significance level.

Step by step solution

01

Formulate the Hypotheses

The null hypothesis (H_0) is: The mean weight of the two types of cheese are the same. The alternative hypothesis (H_A) is: The mean weight of the two types of cheese are not the same.
02

Calculate the Test Statistic

The formula for the test statistic when comparing two means is given by: \[t = \frac{{(\bar{X}_1 - \bar{X}_2) - \delta}}{{\sqrt{s_1^2/n_1 + s_2^2/n_2}}}\]where \(\bar{X}_1, \bar{X}_2\) are the sample means, \(s_1, s_2\) are the sample standard deviations, \(n_1, n_2\) are the sample sizes, and \(\delta\) is the difference in population means under the null hypothesis. In this case, \(\delta = 0\), so we have:\[t = \frac{{(1.2 - 1.05)}}{{\sqrt{0.32^2/16 + 0.25^2/14}}} = 1.783\]
03

Find the Critical Value in the t-Distribution Table

The degree of freedom for two-sample t-tests is calculated as \(df = n_1 + n_2 - 2 = 16 + 14 - 2 = 28\) which is the closest value found in the t-distribution table. For a 0.1 significance level and df of 28, the critical value is 1.701.
04

Draw the Conclusion from the Test

We compare the calculated t-test statistic with the critical value. Because our Calculated value (1.783) is greater than the Critical value (1.701), we reject the null hypothesis. Hence, we have enough statistical evidence to support Heidi's assumption that there's a difference in the mean weights of the two types of cheese.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Two-Sample T-Test
The two-sample t-test is a statistical method used to determine whether there is a significant difference between the means of two independent groups. In the context of our example, Heidi is using this test to compare the weights of wheels of Gouda cheese to those of Brie cheese.

When conducting a two-sample t-test, we calculate a t-statistic that measures the difference between the two sample means relative to the variation within the samples. This statistic takes into account the sample sizes, means, and standard deviations of the two groups. If the t-statistic falls beyond a certain critical value determined by the desired significance level and the degrees of freedom, we can conclude that there is a significant difference between the two groups.

For Heidi's cheese weights, we saw this calculation in action: the mean weight of the Gouda and Brie samples were compared using their respective standard deviations and sample sizes to calculate a t-value. The final step involves comparing this value to a critical value from the t-distribution to make a decision regarding the significant difference in mean weights.
Null Hypothesis
The null hypothesis, often denoted as \(H_0\), is a fundamental concept in hypothesis testing. It is a statement that there is no effect or no difference, and it serves as a starting point for statistical analysis. In Heidi's case, the null hypothesis posits that the mean weight per wheel of both Gouda and Brie cheese are the same.

In statistical tests, the null hypothesis is what we assume to be true until we have enough evidence to support an alternative view. It is framed in such a way that it can be directly tested statistically and, if found lacking evidence, be rejected in favor of the alternative hypothesis. However, failure to reject the null hypothesis does not necessarily confirm it as true; it merely suggests that the sample data are not sufficiently convincing to rule it out.
Alternative Hypothesis
The alternative hypothesis, denoted as \(H_A\) or \(H_1\), reflects a research hypothesis – it's what the researcher aims to support. It is proposed as a direct contradiction to the null hypothesis and represents a specific claim about a population parameter. In the cheese weight example, the alternative hypothesis is that the mean weights of Gouda and Brie cheese wheels are not the same.

When performing a two-sample t-test like Heidi's, we are essentially testing the likelihood that the alternative hypothesis is true given the data. Should our test statistic indicate a value that is sufficiently extreme according to the t-distribution, we would reject the null hypothesis in favor of the alternative hypothesis, thus suggesting that there is a statistically significant difference in the groups being compared.
Statistical Significance
Statistical significance is a determination of whether the results of a statistical test reflect a true effect, or if they are likely due to chance. It is usually denoted by a p-value, which is the probability of obtaining test results at least as extreme as the ones observed during the test, assuming that the null hypothesis is true.

In hypothesis testing, we often set a significance level before conducting the test, which is denoted by \( \alpha \). Common \( \alpha \)-levels include 0.05, 0.01, or 0.10, with lower values indicating a stricter criterion for claiming a significant effect. If the p-value is less than \( \alpha \), we reject the null hypothesis, indicating that our observed effect is statistically significant. For Heidi’s cheese experiment, a level of 0.05 was set, and since her calculated test statistic exceeded the critical value at this level, she found enough evidence to conclude that there is a significant difference in the mean weights of Gouda and Brie wheels at the 10% level of statistical significance.

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Most popular questions from this chapter

Consumer Reports conducted a survey of 1000 adults concerning wearing bicycle helmets. One of the questions presented to 25 - to 54 -year olds was whether they wear a helmet most of the time while biking or cycling. This was further broken down to whether or not they had a child at home. Eighty-seven percent of the age group that had a child at home reported that they wear a helmet most of the time, while \(74 \%\) of those without a child at home reported they wear a helmet most of the time. If the sample size is 340 for both age groups, is the proportion of helmet use significantly greater when there is a child in the home, at the 0.01 level of significance?

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