/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 91 The Soap and Detergent Associati... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The Soap and Detergent Association issued it fifth annual Clean Hands Report Card survey for 2009 From the answers to a series of hygiene-related question posed to American adults, it was found that \(62 \%\) of 44 women washed their hands more than 10 times per day while \(37 \%\) of 446 men did the same. Find the \(95 \%\) confidence interval for the difference in proportions of womer and men that washed their hands more than 10 times day.

Short Answer

Expert verified
The 95% confidence interval for the difference in proportions of women and men who wash their hands more than 10 times a day can be calculated as follows: \(CI = (0.62 - 0.37) \pm 1.96*SE\). Substitute the calculated SE in the place of SE in the formula to get the confidence interval.

Step by step solution

01

Calculate the proportions

The first step is to calculate the proportions of women and men that wash their hands more than 10 times per day. The proportion can be calculated as follows: \( p_{women} = \frac{number of women who wash their hands more than 10 times per day}{total number of women surveyed}\) and \( p_{men} = \frac{number of men who wash their hands more than 10 times per day}{total number of men surveyed}\). So, \( p_{women} = \frac{62}{100} = 0.62\) and \( p_{men} = \frac{37}{100} = 0.37\)
02

Calculate the standard error

Now, calculate the standard error (SE) for the difference in proportions. The formula for standard error is \( SE = \sqrt{\frac{p_{women}(1-p_{women})}{n_{women}} + \frac{p_{men}(1-p_{men})}{n_{men}}}\) Substituting the values, we get \( SE = \sqrt{\frac{0.62(1-0.62)}{44} + \frac{0.37(1-0.37)}{446}}\)
03

Find the confidence interval

The 95% confidence interval for the difference in proportions can be found using the formula: \(CI = (p_{women} - p_{men}) \pm Z*SE\) where Z is the z-score for a 95% confidence interval, which is 1.96. Substituting the values, we get: \(CI = (0.62 - 0.37) \pm 1.96*SE\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Error Calculation
Understanding the standard error (SE) is crucial when working with statistics, especially when comparing two different proportions. SE measures how far the sample mean of the data is likely to be from the true population mean. It's a form of statistical accuracy for an estimate.

In the context of proportion differences, the standard error helps us to understand the variability or uncertainty around the estimate of the difference between two proportions. The formula for the standard error of the difference in proportions is:
\[\begin{equation}SE = \[\sqrt{\frac{p_{1}(1-p_{1})}{n_{1}} + \frac{p_{2}(1-p_{2})}{n_{2}}}\]\end{equation}\]
Here, \(p_1\) and \(p_2\) represent the sample proportions, and \(n_1\) and \(n_2\) are the sample sizes for the two groups. The SE quantifies the standard deviation of the sampling distribution of a statistic, in this case, the difference between two independent proportions.

To calculate the SE in our problem, we plug in the proportions \(p_{women} = 0.62\) and \(p_{men} = 0.37\), and the sample sizes \(n_{women} = 44\) and \(n_{men} = 446\) into the formula, resulting in the SE for the difference of proportions between women and men who wash their hands more than 10 times per day.
Proportional Differences
Proportional differences come into play when comparing the rates of occurrence of a certain attribute between two groups. In our example, we're looking at the difference in hygiene habits between women and men.

The first step in analyzing proportional differences is to calculate the individual proportions for each group. This is done by dividing the number of occurrences by the total number of observations in that group. For the given problem, we calculated that \(62\%\) of the 44 women (\(p_{women} = 0.62\)) and \(37\%\) of the 446 men (\(p_{men} = 0.37\)) washed their hands more than 10 times per day.

Once the individual proportions are known, the difference between these proportions can be expressed simply as \(p_{women} - p_{men}\). This difference, on its own, gives us a point estimate of the true difference in the population. However, to make a more informed and statistically backed statement, we must consider the variability of this estimate, which is where the standard error and confidence intervals come into play.
Hypothesis Testing
Hypothesis testing is a statistical method used to make decisions or inferences about a population based on sample data. It involves making an initial assumption, known as the null hypothesis, and then determining whether the observed data provides enough evidence to reject this initial hypothesis in favor of an alternative hypothesis.

In the case of comparing two proportions, our null hypothesis typically states that there is no difference between the two population proportions. The alternative hypothesis would be that there is a difference. To decide whether the observed data is significant, we calculate the test statistic and compare it against a critical value from the chosen significance level's distribution, often the normal distribution for large enough sample sizes.

For the confidence interval approach, we create an interval around the estimated difference in proportions and determine if this interval includes the hypothesized value (often zero for no difference). If the interval does not include the null value, then we have evidence to reject the null hypothesis.

Building on our example, the calculated confidence interval provides the range within which we estimate the true difference in population proportions will lie 95% of the time. If this range doesn't encompass zero, it suggests that there is a statistically significant difference between the hand-washing frequencies of women and men.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The students at a local high school were assigned to do a project for their statistics class. The project involved having sophomores take a timed test on geometric concepts. The statistics students then used these data to determine whether there was a difference between male and female performances. Would the resulting sets of data represent dependent or independent samples? Explain.

Find the critical value for the hypothesis test with \(H_{a}: \sigma_{1}>\sigma_{2},\) with \(n_{1}=7, n_{2}=10,\) and \(\alpha=0.05\).

A Harris Interactive poll found that \(50 \%\) of Democrats follow professional football while \(59 \%\) of Republicans follow the sport. If the poll results were based on samples of 875 Democrats and 749 Republicans, determine, at the 0.05 level of significance, if the viewpoint of more Republicans following professional football is substantiated.

State the null hypothesis, \(H_{o}\), and the alternative hypothesis, \(H_{a},\) that would be used to test these claims: a. There is no difference between the proportions of men and women who will vote for the incumbent in next month's election. b. The percentage of boys who cut classes is greater than the percentage of girls who cut classes. c. The percentage of college students who drive old cars is higher than the percentage of noncollege people of the same age who drive old cars.

Forty-one small lots of experimental product were manufactured and tested for the occurrence of a particular indication that is an attribute in nature yet causes rejection of the part. Thirty-one lots were made using one particular processing method, and ten lots were made using a second processing method. Each lot was equally sampled \((n=32)\) for the presence of this indication. In practice, optimal processing conditions show little or no occurrence of the indication. Method 1 , involving the ten lots, was run before Method 2 Determine, at the 0.05 level of significance, whether there is a difference in the proportion of reject product between the two methods. (Save your answer for comparison with Exercise 11.72 on p. \(575 .\) )

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.