/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 33 Ten recently diagnosed diabetics... [FREE SOLUTION] | 91Ó°ÊÓ

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Ten recently diagnosed diabetics were tested to determine whether an educational program would be effective in increasing their knowledge of diabetes. They were given a test, before and after the educational program, concerning self-care aspects of diabetes. The scores on the test were as follows: $$\begin{array}{lcccccccccc}\text { Patient } & 1 & 2 & 3 & 4 & 5 & 6 & 7 & 8 & 9 & 10 \\ \hline \text { Before } & 75 & 62 & 67 & 70 & 55 & 59 & 60 & 64 & 72 & 59 \\\\\text { Afler } & 77 & 65 & 68 & 72 & 62 & 61 & 60 & 67 & 75 & 68 \\\\\hline\end{array}$$The following MINITAB output may be used to determine whether the scores improved as a result of the program. Verify the values shown on the output [mean difference(MEAN), standard deviation of the difference (STDEV), standard error of the difference (SE MEAN), \(t \star\) (T-Value), and \(p\) -value] by calculating the values yourself.

Short Answer

Expert verified
Given the calculated values, if the p-value is less than 0.05, then there is evidence to conclude that the educational program has a significant effect in increasing the patient's knowledge of diabetes.

Step by step solution

01

Calculate the differences

For each patient, subtract the score before the program from the score after the program. This will give ten differences.
02

Calculate mean difference

Add all the values from step 1 and divide by the number of patients (10), this will give the mean difference.
03

Calculate standard deviation of the difference

Subtract the mean difference from each individual difference, square the result, then add all these values and divide by the number of patients minus 1. The square root of this result is the standard deviation.
04

Calculate standard error of the mean difference

Divide the standard deviation by the square root of the number of patients. This is the standard error of the mean difference.
05

Calculate t-value

Divide the mean difference by the standard error.
06

Calculate degrees of freedom

Subtract 1 from the number of patients. This is the degrees of freedom.
07

Find p-value

Using a t-distribution table, find the probability that a t-statistic is greater than or equal to the absolute value of the t-value from step 5, with degrees of freedom from step 6. This is the p-value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pre-Post Test Comparison
When evaluating the effectiveness of an educational program, one common method used is the 'pre-post test comparison'. This approach involves administering a test before the program begins (the pre-test) and again after it concludes (the post-test). By comparing the scores from both tests, researchers can infer whether the program has had any impact on the participants' knowledge or skills.

In the context of the exercise, this comparison is applied to assess an educational program for diabetics. The score differences between the pre-test and post-test for ten patients provide the raw data needed to conduct statistical analysis. It's essential to ensure that any changes in test scores are specifically due to the program and not external factors. This might involve controlling variables or considering additional data to support the validity of the results.
Mean Difference Calculation
The 'mean difference' is a crucial statistic in research, representing the average change across all cases from the pre-test to the post-test. To calculate it, you simply subtract each individual's pre-test score from their post-test score and then take the average of these differences.

In the given exercise, the mean difference gives us an average indication of how much the diabetic patients' knowledge improved after the educational program. Calculating the mean difference is critical since it provides a single summary figure demonstrating the overall effect of the program, but it does not assess the variability of that effect across individuals, which is where other statistics, like standard deviation, come into play.
Standard Deviation in Educational Research
Understanding the 'standard deviation' is essential in educational research as it measures the amount of variability or dispersion in a set of values. In simpler terms, it tells us how spread out the differences between the pre-test and post-test scores are.

When analyzing the effectiveness of the educational program for diabetics, looking at the standard deviation of the difference helps us understand how consistently the program affected the participants. A low standard deviation suggests that most participants had a similar change in scores, while a high standard deviation indicates a wide range of outcomes. This statistic is integral to grasp the impact's uniformity and to pinpoint any outliers or anomalies in the data.
T-Value Analysis
Finally, 't-value analysis' is a statistical method used to determine if the observed mean difference is statistically significant. The t-value is calculated by dividing the mean difference by the standard error of the mean difference. It measures how many standard errors the mean difference is from zero. In educational research—like our diabetic education program—a high absolute t-value may suggest that the changes in test scores are unlikely to be due to random chance alone, implying the program’s effectiveness.

The p-value associated with the t-value helps us to decide whether to reject the null hypothesis, which typically states that the program had no effect. Generally, if the p-value is less than a chosen significance level (often 0.05), the null hypothesis is rejected, indicating that the educational program had a statistically significant positive effect on the participants' knowledge.

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Most popular questions from this chapter

Twenty laboratory mice were randomly divided into two groups of \(10 .\) Each group was fed according to a prescribed diet. At the end of 3 weeks, the weight gained by each animal was recorded. Do the data in the following table justify the conclusion that the mean weight gained on diet \(\mathrm{B}\) was greater than the mean weight gained on diet \(\mathrm{A}\), at the \(\alpha=0.05\) level of significance? Assume normality.$$\begin{array}{lllllllllll} \hline \text { Diet A } & 5 & 14 & 7 & 9 & 11 & 7 & 13 & 14 & 12 & 8 \\\\\text { Diet B } & 5 & 21 & 16 & 23 & 4 & 16 & 13 & 19 & 9 & 21 \\\\\hline\end{array}$$ a. Solve using the \(p\) -value approach. b. Solve using the classical approach.

Find the value of \(t \star\) for the difference between two means based on an assumption of normality and thic information about two samples: $$\begin{array}{cccc}\text { Sample } & \text { Number } & \text { Mean } & \text { Std. Dev. } \\\\\hline 1 & 18 & 38.2 & 14.2 \\\2 & 25 & 43.1 & 10.6 \\\\\hline\end{array}$$

Two different types of disc centrifuges are used to measure the particle size in latex paint. A gallon of paint is randomly selected, and 10 specimens are taken from it for testing on each of the centrifuges. There will be two sets of data, 10 data values each, as a result of the testing. Do the two sets of data represent dependent or independent samples? Explain.

One could reason that high school seniors would have more money issues than high school juniors. Seniors foresee expenses for college as well as their senior trip and prom. So does this mean that they work more than their junior classmates? Christine, a senior at HFL High School, randomly collected the following data (recorded in hours/week) from students that work: $$\begin{array}{llll}\hline \text { Seniors } & n_{s}=17 & \bar{x}_{s}=16.4 & s_{s}=10.48 \\\\\text { Juniors } & n_{i}=20 & \bar{x}_{i}=18.405 & s_{i}=9.69 \\\\\hline\end{array}$$ Assuming that work hours are normally distributed, do these data suggest that there is a significant difference between the average number of hours that HFL seniors and juniors work per week? Use \(\alpha=0.10\).

Are females as serious about golf as men are? If so, would the price of a driver for a man be the same as the price of a driver for a female? It was contended that women's drivers would be cheaper. Random samples of drivers were taken from the Golflink.com website. The prices were: $$\begin{array}{llllll} \text { Male } & & & & & \\\\\hline 149.99 & 299.99 & 49.99 & 499.99 & 167.97 & 299.99 \\\399.99 & 199.99 & 99.99 & 149.99 & & \\\\\hline \text { Female } & & & & & \\\\\hline 199.99 & 79.99 & 499.99 & 199.97 & 299.99 & 99.99\end{array}$$ At the 0.05 level of significance, is there sufficient evidence to support the contention that men's drivers are more expensive than women's drivers? Assume normality of golf driver prices.

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