/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 56 Find the value of \(t \star\) fo... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find the value of \(t \star\) for the difference between two means based on an assumption of normality and thic information about two samples: $$\begin{array}{cccc}\text { Sample } & \text { Number } & \text { Mean } & \text { Std. Dev. } \\\\\hline 1 & 18 & 38.2 & 14.2 \\\2 & 25 & 43.1 & 10.6 \\\\\hline\end{array}$$

Short Answer

Expert verified
The t-value for the provided data is given by \(t = \Delta / S_E \), where \(\Delta\) represents the difference in means, and \(S_E\) is the standard error of the groups.

Step by step solution

01

Find the difference between the means

The difference between the mean of Sample 1 and Sample 2 can be calculated by subtracting the mean of Sample 1 from Sample 2. Thus, \(\Delta = 43.1 - 38.2 = 4.9\)
02

Find the standard deviation of each group

The standard deviation of each group is given as 14.2 and 10.6 for Sample 1 and Sample 2 respectively.
03

Compute the pooled standard deviation

The pooled standard deviation \(S_p\) is the average spread of all data points. It can be calculated as the square root of the sum of the variances divided by the number of groups minus 1. In this case, the variances are the squares of the standard deviations (14.2^2 and 10.6^2), and the groups are the sample sizes (18 and 25). Thus, \(S_p = sqrt[ ((18-1)*14.2^2 + (25-1)*10.6^2) / (18 + 25 -2) ] \)
04

Compute the standard error

The standard error is calculated by dividing the pooled standard deviation by the square root of the sum of the reciprocals of the sample sizes. In this case, the standard error is \(S_E = S_p * sqrt(1/18 + 1/25) \).
05

Compute the t-value

Finally, the t-value is calculated by dividing the difference in means by the standard error. Thus \(t = \Delta / S_E \).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Pooled Standard Deviation
When comparing two groups and looking at the variability within their scores, it's not enough to just consider the standard deviation of each group.

Instead, we use the concept of pooled standard deviation, which combines the variability from both groups to get a more accurate estimate of the overall variation. It takes into account the spread of both datasets and adjusts for the sample size of each, which is crucial when dealing with different numbers of observations.

To calculate the pooled standard deviation, we first square the standard deviations (to get the variances), multiply each by their respective sample size minus one, add them up, and then divide by the total number of observations from both samples minus two. Finally, we take the square root of that value. Mathematically, it can be expressed as follows:\[\begin{equation}S_p = \sqrt{\frac{(n_1-1)s_1^2 + (n_2-1)s_2^2}{n_1 + n_2 - 2}}\end{equation}\]where:
  • S_p is the pooled standard deviation,
  • s_1 and s_2 are the standard deviations for the two samples,
  • n_1 and n_2 are the sizes of the two samples.
This is crucial for conducting accurate hypothesis testing when comparing two different means and ensures the t-test will have valid results.
Standard Error
Once we have our pooled standard deviation, we can then move forward to another important concept called the standard error of the mean. This measure represents the variability or spread within a sample mean if we were to sample the population multiple times.

The standard error is an essential statistic because it tells us how far the sample mean is expected to be from the population mean. This is particularly important when we're conducting a t-test, as it plays a pivotal role in calculating the t-value.

To calculate the standard error for two independent samples, use the pooled standard deviation along with the sample sizes as follows:\[\begin{equation}S_E = S_p \sqrt{\frac{1}{n_1} + \frac{1}{n_2}}\end{equation}\]Within the context of hypothesis testing, a smaller standard error implies that our sample means are tightly clustered around the true population mean. Practically, this translates to more confidence in our sample results and predictions about the population.
t-test for Independent Samples
The t-test for independent samples is a statistical method used to determine whether there is a significant difference between the means of two unrelated groups. This comes into play when trying to understand if two samples could have come from the same population or if their means are indeed different.

For our example, the final step after calculating the pooled standard deviation and the standard error is to find the t-value. This is the number that we will compare against a critical value from the t-distribution table to decide whether our finding is statistically significant or not. The formula for the t-value is given by:\[\begin{equation}t = \frac{\Delta}{S_E}\end{equation}\] where
  • \Delta is the difference between the sample means, and
  • S_E is the standard error of the mean difference.
This calculated t-value can then be used to make inferences about the population means. If the t-value exceeds the critical value, we reject the null hypothesis that there is no difference between the population means. Understanding the use of pooled standard deviation, standard error, and interpreting the results of a t-test provides a solid foundation for making inferences about population parameters based on sample data.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A Harris Interactive poll found that \(50 \%\) of Democrats follow professional football while \(59 \%\) of Republicans follow the sport. If the poll results were based on samples of 875 Democrats and 749 Republicans, determine, at the 0.05 level of significance, if the viewpoint of more Republicans following professional football is substantiated.

A manufacturer designed an experiment to compare the differences between men and women with respect to the times they require to assemble a product. A total of 15 men and 15 women were tested to determine the time they required, on average, to assemble the product. The time required by the men had a standard deviation of 4.5 minutes, and the time required by the women had a standard deviation of 2.8 minutes. Do these data show that the amount of time needed by men is more variable than the amount of time needed by women? Use \(\alpha=0.05\) and assume the times are approximately normally distributed. a. Solve using the \(p\) -value approach. b. Solve using the classical approach.

State the null hypothesis, \(H_{o},\) and the alternative hypothesis, \(H_{a},\) that would be used to test these claims: a. The mean of the differences between the post-test and the pre-test scores is greater than \(15 .\) b. The mean weight gain, after the change in diet for the laboratory animals, is at least 10 oz. c. The mean weight loss experienced by people on a new diet plan was no less than 12 lb. d. The mean difference in the home reassessments from the two town assessors was no more than \(\$ 200\)

An insurance company is concerned that garage A charges more for repair work than garage B charges. It plans to send 25 cars to each garage and obtain separate estimates for the repairs needed for each car. a. How can the company do this and obtain independent samples? Explain in detail. b. How can the company do this and obtain dependent samples? Explain in detail.

In a survey of families in which both parents work, one of the questions asked was, "Have you refused a job, promotion, or transfer because it would mean less time with your family?" A total of 200 men and 200 women were asked this question. "Yes" was the response given by \(29 \%\) of the men and \(24 \%\) of the women. Based on this survey, can we conclude that there is a difference in the proportion of men and women responding "Yes" at the 0.05 level of significance?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.