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91Ó°ÊÓ

At a large university, a mathematics placement exam is administered to all students. Samples of 36 male and 30 female students are randomly selected from this year's student body and the following scores recorded: $$\begin{array}{lllllllllll}\hline \text { Male } & 72 & 68 & 75 & 82 & 81 & 60 & 75 & 85 & 80 & 70 \\\& 71 & 84 & 68 & 85 & 82 & 80 & 54 & 81 & 86 & 79 \\\& 99 & 90 & 68 & 82 & 60 & 63 & 67 & 72 & 77 & 51 \\\& 61 & 71 & 81 & 74 & 79 & 76 & & & & \\\\\hline \text { Female } & 81 & 76 & 94 & 89 & 83 & 78 & 85 & 91 & 83 & 83 \\\& 84 & 80 & 84 & 88 & 77 & 74 & 63 & 69 & 80 & 82 \\\& 89 & 69 & 74 & 97 & 73 & 79 & 55 & 76 & 78 & 81 \\ \hline\end{array}$$ a. Describe each set of data with a histogram (use the same class intervals on both histograms), the mean, and the standard deviation. b. Construct \(95 \%\) confidence interval for the mean score for all male students. Do the same for all female students. c. Do the results found in part b show that the mean scores for males and females could be the same? Justify your answer. Be careful! d. Construct the \(95 \%\) confidence interval for the difference between the mean scores for male and female students. e. Do the results found in part d show that the mean scores for male and female students could be the same? Explain. f. Explain why the results in part b cannot be used to draw conclusions about the difference between the two means.

Short Answer

Expert verified
Descriptive statistics, including histograms, mean, and standard deviation, give some initial insight into the score distributions. Confidence intervals for individual means could seem to indicate a difference between the means, but the proper way to make inferences about the difference is to construct a confidence interval directly for the difference of the means. If this interval includes zero, then it could indicate no significant difference between the two means; otherwise, a significant difference may be inferred.

Step by step solution

01

Descriptive Statistics

Calculate the mean and standard deviation for each gender's scores. Using a software or a scientific calculator, determine the class intervals and construct histograms for the data. The mean is the sum of the scores divided by the quantity of scores. The standard deviation shows how spread out the scores are from the mean.
02

Confidence Intervals for Mean Score

To build a 95% confidence interval for the mean, use the formula \(\bar{x}\pm z\times\frac{s}{\sqrt{n}}\), where \(\bar{x}\) is the estimated mean, \(z\) is the critical value for a two-tailed test at the 5% level (which is 1.96), \(s\) is the standard deviation, and \(n\) is sample size.
03

Interpretation of Confidence Intervals for Mean

If the confidence intervals for the two means overlap, it may suggest that the means are not significantly different. However, this visual interpretation has some statistical limitations, that's why the analysis has to continue to the next steps.
04

Confidence Interval for Difference Between Means

Construction of a 95% confidence interval for the difference in means uses the formula \(\bar{x}_1-\bar{x}_2 \pm z\times\sqrt{\frac{s^2_1}{n_1}+\frac{s^2_2}{n_2}}\), where \(\bar{x}_1\), \(\bar{x}_2\), \(s_1^2\), \(s_2^2\), \(n_1\) and \(n_2\) are the sample means, sample variances, and sample sizes of the two groups respectively.
05

Interpretation of Confidence Interval for Difference in Means

If the confidence interval for the difference of means includes the value zero, it suggests that there is no statistically significant difference between the two means. If it does not include the value zero, the means are statistically different.
06

Explanation of Inadequacy of Separate Confidence Intervals

The reason why separate confidence intervals for each population cannot be used to draw conclusions about the difference between the two means is because they don't take into account the variation in both distributions; they only consider the variation within each group separately.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Descriptive Statistics
Descriptive statistics play a crucial role in summarizing a large set of data points in an understandable way. In the context of the mathematics placement exam, calculating the mean, which is the average score, provides a quick snapshot of the central tendency of the student scores. It is often the first step to understand the general performance level.

Similarly, the standard deviation is a measure that tells us how spread out the scores are in relation to the mean. A lower standard deviation indicates that the scores are clustered closely around the mean, whereas a higher standard deviation signals that scores are more dispersed. The standard deviation provides a sense of the variability or consistency amongst the scores of the students.

Constructing histograms for male and female students’ scores using class intervals can visually represent the distribution and frequency of scores across a range. It is an intuitive way to see patterns, such as clustering of scores or the presence of outliers, which are scores that stand out from the rest.
Confidence Interval
A confidence interval gives a range in which we can expect the true mean score to lie within, based on our sample data. For the mathematics placement exam, calculating a 95% confidence interval implies that there is a 95% chance that the interval constructed from the sample includes the true mean for all male or female students.

Using the formula \(\bar{x}\pm z\times\frac{s}{\sqrt{n}}\), where \(\bar{x}\) is the sample mean, \(z\) is the z-score corresponding to a 95% confidence level (which is approximately 1.96), \(s\) is the standard deviation of the sample, and \(n\) is the number of observations in the sample, we can determine this interval for each gender. This calculation helps to estimate the mean score for the entire student body while acknowledging that we have only examined a sample.
Standard Deviation
The standard deviation is a statistic that quantifies the degree to which scores in a set of data deviate from the mean. In the mathematics exam data for male and female students, the standard deviation offers insight into the diversity of mathematical abilities within each group.

In the calculation of a confidence interval, the standard deviation plays a key role as it affects the width of the interval. A larger standard deviation will produce a wider confidence interval, indicating a greater uncertainty in the estimation of the population mean, while a smaller standard deviation leads to a narrower interval, reflecting a more precise estimate. Understanding standard deviation is fundamental not only in creating the confidence intervals but also in interpreting the reliability and precision of our estimated means.
Mean Score Analysis
Analyzing the mean scores of the math placement exams for male and female students informs us about the average performance of each group. It is a preliminary step before delving into inferential statistics where comparisons between groups are made. However, mean score analysis alone cannot provide a complete picture without considering variation and sampling error.

In the exercise, when we calculate a confidence interval for the difference between the mean scores of male and female students, we are looking for evidence of any significant differences in performance between the two groups. If this interval includes zero, it indicates that we cannot say with confidence that there is a difference between the groups. However, if the interval does not include zero, this suggests a statistically significant difference in mean scores. It’s important to remember that mean score analysis is only one dimension, and it should be considered alongside other statistical measures for a comprehensive understanding of the data.

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Most popular questions from this chapter

State the null hypothesis, \(H_{o}\), and the alternative hypothesis, \(H_{a},\) that would be used to test these claims: a. There is no difference between the proportions of men and women who will vote for the incumbent in next month's election. b. The percentage of boys who cut classes is greater than the percentage of girls who cut classes. c. The percentage of college students who drive old cars is higher than the percentage of noncollege people of the same age who drive old cars.

When a hypothesis test is two-tailed and Excel is used to calculate the \(p\) -value, what additional step must be taken?

Use a computer to demonstrate the truth of the theory presented in this section. a. The underlying assumptions are "the populations are normally distributed," and while conducting a hypothesis test for the equality of two standard deviations, it is assumed that the standard deviations are equal. Generate very large samples of two theoretical populations: \(N(100,20)\) and \(N(120,20)\) Find graphic and numerical evidence that the populations satisfy the assumptions. b. Randomly select 100 samples, each of size \(8,\) from both populations and find the standard deviation of each sample. c. Using the first sample drawn from each population as a pair, calculate the \(F\) t-statistic. Repeat for all samples. Describe the sampling distribution of the \(100 F \star\) -values using both graphic and numerical statistics. d. Generate the probability distribution for \(F(7,7),\) and compare it with the observed distribution of \(F \star .\) Do the two graphs agree? Explain.

State the null hypothesis, \(H_{o},\) and the alternative hypothesis, \(H_{a},\) that would be used to test these claims: a. The mean of the differences between the post-test and the pre-test scores is greater than \(15 .\) b. The mean weight gain, after the change in diet for the laboratory animals, is at least 10 oz. c. The mean weight loss experienced by people on a new diet plan was no less than 12 lb. d. The mean difference in the home reassessments from the two town assessors was no more than \(\$ 200\)

Immediate-release medications quickly deliver their drug content, with the maximum concentration reached in a short time; sustained-release medications, on the other hand, take longer to reach maximum concentration. As part of a study, immediaterelease codeine (irc) was compared with sustainedrelease codeine (src) using 13 healthy patients. The patients were randomly assigned to one of the two types of codeine and treated for 2.5 days; after a 7 -day washout period, each patient was given the other type of codeine. Thus, each patient received both types. The total amount \((\mathrm{A})\) of drug available over the life of the treatment in (ng \(\cdot \mathrm{mL}\) )/hr follows: a. Explain why this is a paired-difference design. b. What adjustment is needed since there is no Asrc for patient \(6 ?\) Is there a significant difference in the total amount of drug available over the life of the treatment? c. Check the test assumptions and describe your findings. d. Test the claim using \(\alpha=0.05\)

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