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Suppose \(x\) has a beta distribution with parameters \(\alpha=2.5\) and \(\beta=1\). Determine the following: (a) \(P(X<0.25)\) (b) \(P(0.25

Short Answer

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(a) 0.15625, (b) 0.6875, (c) Mean: 0.7143, Variance: 0.051.

Step by step solution

01

Understanding the Beta Distribution

The beta distribution is defined on the interval [0, 1] and is determined by two shape parameters, \( \alpha \) and \( \beta \). For our problem, these parameters are given as \( \alpha = 2.5 \) and \( \beta = 1 \). The probability density function (pdf) for a beta distribution is given by: \[ f(x) = \frac{x^{\alpha-1} (1-x)^{\beta-1}}{B(\alpha, \beta)} \] where \( B(\alpha, \beta) \) is the beta function.
02

Calculating P(X < 0.25)

To find \( P(X < 0.25) \), we need to evaluate the cumulative distribution function (CDF) of the beta distribution at \( x = 0.25 \). This is given by the incomplete beta function \( I_x(\alpha, \beta) \). For our parameters \( \alpha = 2.5 \), \( \beta = 1 \), and \( x = 0.25 \), we have: \( P(X < 0.25) = I_{0.25}(2.5, 1) \). Using tables or computational tools, we find \( P(X < 0.25) \approx 0.15625 \).
03

Calculating P(0.25 < X < 0.75)

\( P(0.25 < X < 0.75) \) is found by calculating \( P(X < 0.75) - P(X < 0.25) \). First, find \( P(X < 0.75) = I_{0.75}(2.5, 1) \approx 0.84375 \). Then calculate the difference: \( P(0.25 < X < 0.75) = 0.84375 - 0.15625 = 0.6875 \).
04

Calculating Mean and Variance

The mean of a beta distribution is given by \( \frac{\alpha}{\alpha + \beta} \). With \( \alpha = 2.5 \) and \( \beta = 1 \), the mean is \( \frac{2.5}{3.5} = 0.7143 \). The variance is \( \frac{\alpha\beta}{(\alpha + \beta)^2(\alpha + \beta + 1)} \), leading to \( \frac{2.5 \times 1}{3.5^2 \times 4.5} = 0.051 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Density Function
The Probability Density Function (PDF) of a beta distribution plays a crucial role in describing how probabilities are distributed over the interval [0, 1]. In a beta distribution, the PDF is determined by two shape parameters, \(\alpha\) and \(\beta\). The function is defined as follows:
  • \[ f(x) = \frac{x^{\alpha-1} (1-x)^{\beta-1}}{B(\alpha, \beta)} \]
In this formula, \(x\) represents a value within the range of 0 to 1, and the term \(B(\alpha, \beta)\) signifies the beta function. This beta function acts as a normalization constant, ensuring that the total area under the PDF curve equals 1.
The PDF of a beta distribution can take different shapes based on the chosen \(\alpha\) and \(\beta\) values. For instance, choosing \(\alpha=2.5\) and \(\beta=1\) results in a bell-shaped curve skewed towards 1. This flexibility makes the beta distribution incredibly versatile in modeling phenomena that naturally occur within a bounded range.
Cumulative Distribution Function
The Cumulative Distribution Function (CDF) is key to understanding the probability of a random variable in a beta distribution being less than or equal to a specific value. It is essentially a probability accumulation function.
To calculate the CDF in the context of a beta distribution, we rely on the incomplete beta function, denoted as \(I_x(\alpha, \beta)\). For example, to determine the probability that a random variable \(X\) is less than 0.25, we evaluate \(I_{0.25}(2.5, 1)\), which gives us \(P(X < 0.25) \approx 0.15625\).
The CDF grows from 0 to 1 as \(x\) progresses from 0 to 1, providing a complete picture of how probabilities accumulate over the specified range.
Shape Parameters
Shape parameters \(\alpha\) and \(\beta\) are the defining features of a beta distribution. These parameters manipulate the form of the distribution to fit specific needs or data characteristics. Here's what they do:
  • \(\alpha\): Often referred to as the "first shape parameter," it primarily influences the distribution's skewness towards 1.
  • \(\beta\): Known as the "second shape parameter," it mainly dictates the skewness towards 0.
By adjusting \(\alpha\) and \(\beta\), you can create different kinds of skewed or symmetric distributions. In our exercise, the combination \(\alpha=2.5\) and \(\beta=1\) results in a left-skewed distribution, indicating a tendency for events to pack more closely towards the low end of the range.
This customization offers incredible flexibility, allowing the beta distribution to be used widely in fields like finance and academia for modeling probabilities over a fixed interval.
Mean and Variance
The mean and variance of a beta distribution provide essential insights into its central tendency and variability.
Let's explore each:
  • Mean: The average value of a beta-distributed variable is given by \(\frac{\alpha}{\alpha + \beta}\). For our parameters \(\alpha=2.5\) and \(\beta=1\), the mean is \(0.7143\). This suggests that the distribution is slightly skewed to the right of the middle point (0.5).
  • Variance: The variance, expressing the spread of the distribution, is calculated using \(\frac{\alpha\beta}{(\alpha + \beta)^2(\alpha + \beta + 1)}\). Here, the variance is \(0.051\), indicating a relatively tight spread around the mean.
The mean and variance give a comprehensive understanding of the distribution's behavior, highlighting its typical value and the extent to which values deviate from it. This allows analysts and researchers to comprehend how concentrated or dispersed a distribution is, aiding in better decision-making and interpretations.

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