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Suppose that \(X\) has a lognormal distribution with parameters \(\theta=2\) and \(\omega^{2}=4\). Determine the following: (a) \(P(X<500)\) (b) The conditional probability that \(X<1500\) given that $$X>1000$$ (c) What does the difference between the probabilities in parts (a) and (b) imply about lifetimes of lognormal random variables?

Short Answer

Expert verified
(a) 0.9824, (b) 0.9904. Long lifetimes are probable following initial survival.

Step by step solution

01

Understanding the Lognormal Distribution

A lognormal distribution is associated with a normal distribution for the natural logarithm of the variable. If \(X\) is lognormally distributed with parameters \(\theta\) and \(\omega^2\), then \(\ln(X)\) is normally distributed with mean \(\theta\) and variance \(\omega^2\). For this problem, this means \(\ln(X)\sim N(2, 4)\).
02

Convert to Standard Normal

To solve for probabilities under a lognormal distribution, convert \(X\) into its standard normal form. This involves using the transformation \(Z = \frac{\ln(X) - \theta}{\omega}\). Here, \(Z = \frac{\ln(X) - 2}{2}\) since \(\omega = 2\).
03

Solve for P(X

Convert the condition \(X < 500\) to its logarithmic form: \(\ln(X) < \ln(500)\). Substitute into the Z equation: \(Z < \frac{\ln(500) - 2}{2}\). Calculate \(Z\) and then use standard normal distribution tables or a calculator to find the probability. \(\ln(500) \approx 6.2146\), so \(Z < \frac{6.2146 - 2}{2} = 2.1073\), and \(P(Z < 2.1073) \approx 0.9824\).
04

Solve for Condtional Probability (b)

First, find \(P(X < 1500)\) in the original lognormal context: Convert \(X < 1500\) into \(\ln(X) < \ln(1500)\). Use standard normal conversion: \(Z < \frac{\ln(1500) - 2}{2}\). \(\ln(1500) \approx 7.3132\) so \(Z < \frac{7.3132 - 2}{2} = 2.6566\), which gives \(P(Z < 2.6566) \approx 0.9958\). Then, calculate \(P(X > 1000)\): \(\ln(X) > \ln(1000)\). \(\ln(1000) \approx 6.9078\) and \(Z > \frac{6.9078 - 2}{2} = 2.4539\), giving \(P(Z > 2.4539) = 1 - P(Z < 2.4539) = 1 - 0.9928 = 0.0072\).Finally, the conditional probability is the quotient of these two: \(P(X < 1500 | X > 1000) = \frac{P(X < 1500)}{P(X > 1000)} = \frac{0.9958}{0.0072} \approx 0.9904\).
05

Interpret the Difference in Probabilities

The probability \(P(X<500)\) is quite high, implying that for lognormal distributed variables, smaller values are more likely. The conditional probability \(P(X < 1500 | X > 1000)\) is also very high, showing that even for higher ranges, increments in the observed range continue to maintain high probabilities. This means lognormal distributions tail off gradually, meaning as values increase, the distribution suggests a relatively slow decay in probability, indicating heavy tails.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probabilities in a lognormal distribution can be a bit tricky, primarily because we deal with the natural logarithm of the random variable. When dealing with a problem like determining \( P(X < 500) \), we start by converting the random variable \( X \) into its log form. Given \( X \sim \text{Lognormal}(\theta, \omega^2) \), \( \ln(X) \sim N(\theta, \omega^2) \), which is a normal distribution.

Here's a quick guide to calculate probabilities under a lognormal distribution:
  • Convert the variable condition, such as \( X < 500 \), into logarithmic terms, \( \ln(X) < \ln(500) \).
  • Use the transformation \( Z = \frac{\ln(X) - \theta}{\omega} \) to convert to a standard normal variable.
  • Plug into \( Z = \frac{\ln(500) - 2}{2} \) to get the \( Z \)-score.
  • Use standard normal distribution tables or a calculator to determine \( P(Z < \text{calculated } Z) \).
This process allows us to bridge our understanding from normal distributions to lognormal distributions easily.
Standard Normal Distribution
A key feature of solving probability problems involving the lognormal distribution is converting them into the standard normal form. The standard normal distribution, represented as \( N(0,1) \), has a mean of 0 and a variance of 1. This simplifies calculations through its tabulated probability values.

When working with the lognormal distribution, the transformation formula \( Z = \frac{\ln(X) - \theta}{\omega} \) is used to convert \( X \) into its standard normal form \( Z \). This ensures that irrespective of the original mean and variance, we can use the standardized tables to find probabilities easily.

For example:
  • To find \( P(X < 1500) \), calculate \( Z = \frac{\ln(1500) - 2}{2} \).
  • Check standard normal distribution tables for \( P(Z < 2.6566) \).
By converting into the standard normal form, any complex distribution can be tackled with ease, making it an invaluable tool in statistics.
Conditional Probability
Conditional probability helps you determine the likelihood of an event happening, given that another event has already occurred. In the context of lognormal distributions, it involves understanding how probabilities shift when confined to a certain domain.

For instance, to calculate the conditional probability \( P(X < 1500 | X > 1000) \), you need two probabilities from the lognormal distribution:
  • The probability that \( X < 1500 \): This is found using \( P(Z < 2.6566) \) which yields approximately 0.9958.
  • The probability that \( X > 1000 \): This involves calculating \( 1 - P(Z < 2.4539) \) to get approximately 0.0072.
The conditional probability is then found using \( \frac{P(X < 1500)}{P(X > 1000)} \), highlighting how outcomes are reevaluated when new information (i.e., \( X > 1000 \)) is introduced.

By understanding conditional probabilities, we gain insights into the persistence and behavior of data, even as certain conditions change. It's a powerful tool for predictions and making decisions when faced with uncertainty.

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