/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 2 Suppose that \(f(x)=3\left(8 x-x... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose that \(f(x)=3\left(8 x-x^{2}\right) / 256\) for \(06)\) (c) Determine \(x\) such that \(P(X

Short Answer

Expert verified
P(X<2) by integration, P(X<9)=1, P(26) by integration, x for P(X<x)=0.95 by solving integral equation.

Step by step solution

01

Understanding the Problem

The exercise requires calculating the probabilities related to the random variable \(X\) which is defined over the interval \(0 < x < 8\). The function \(f(x) = \frac{3(8x-x^2)}{256}\) represents its probability density function.
02

Calculate P(X

To find \(P(X<2)\), calculate the integral of \(f(x)\) from 0 to 2:\[P(X<2) = \int_0^2 \frac{3(8x-x^2)}{256} \, dx\]Compute the integral to obtain the probability.
03

Calculate P(X

Since \(X\) is defined only for \(0 < x < 8\), any value greater than 8 is out of bounds and does not contribute to the probability. Thus, \(P(X<9) = P(X<8) = 1\), as it covers the whole range of the random variable.
04

Calculate P(2

Evaluate the integral of \(f(x)\) from 2 to 4:\[P(2<X<4) = \int_2^4 \frac{3(8x-x^2)}{256} \, dx\]Calculate this integral to find the desired probability.
05

Calculate P(X>6)

To determine \(P(X>6)\), find the integral of \(f(x)\) from 6 to 8:\[P(X>6) = \int_6^8 \frac{3(8x-x^2)}{256} \, dx\]Solve this integral to find the probability of \(X\) being greater than 6.
06

Find x for P(X

To find \(x\) such that \(P(X<x)=0.95\), solve the equation:\[\int_0^x \frac{3(8x-x^2)}{256} \, dx = 0.95\]Solve this integral equation for \(x\) to find the required quantile.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Calculating Probabilities from Integrals
In probability, calculating the probability of a continuous random variable involves finding the area under the curve of its probability density function (PDF). This is done using integrals. The integral gives us the probability that the random variable falls within a certain range.

Let's consider the exercise provided, where the probability density function is defined as:
  • \(f(x) = \frac{3(8x-x^2)}{256}\) for \(0 < x < 8\)
To calculate probabilities:
  • For any interval \(a\) to \(b\), compute \(P(a < X < b) = \int_a^b f(x) \, dx\).
  • For values less than 2, as in part (a), \(P(X < 2) = \int_0^2 \tfrac{3(8x-x^2)}{256} \, dx\).
  • We solve these integrals using techniques from calculus, typically integration by substitution or by parts, depending on the PDF form.
The result of such integrals is a probability value between 0 and 1.

Understanding this concept helps with interpreting probabilities for given intervals, which is the core of analyzing continuous random variables.
Continuous Random Variables
Continuous random variables are variables that can take any value within a given range or interval. Unlike discrete variables, which jump from one value to another, continuous random variables smoothly transition through intervals.

In the exercise, \(X\) is a continuous random variable defined over \(0 < x < 8\). This means that \(X\) can take any value within this interval. The nature of continuous random variables allows for an infinite number of possible values in any range.

Key points about continuous random variables include:
  • They are described by a probability density function (PDF), which indicates how probability is distributed over the values.
  • The total area under the PDF curve across its complete interval is equal to 1, indicating 100% probability distributed across all possible outcomes.
  • Probabilities are calculated using integrals, as they involve the area under the function's curve within specified limits.
This understanding is foundational for manipulating and calculating probabilities for such variables, essential for applied statistics and real-world data analysis.
Quantile Calculation
Quantile calculation for a continuous random variable involves finding a value below which a given proportion of the data falls. This is commonly used to find thresholds or cutoff points in datasets.

To find a quantile, solve the following equation for \(x\):
  • \(\int_0^x f(t) \, dt = p\), where \(f(t)\) is the PDF and \(p\) is the desired cumulative probability.
For instance, part (e) of the exercise asked to determine \(x\) such that \(P(X < x) = 0.95\). This quantile, denoted as the 95th percentile, represents the value below which 95% of observations fall.

To solve this:
  • Set up the integral \(\int_0^x \frac{3(8t-t^2)}{256} \, dt = 0.95\).
  • Use numerical methods or standard integration techniques to solve for \(x\).
Understanding quantiles is crucial in fields like finance, meteorology, and quality control, where they are used to assess risk, distribution, and performance thresholds.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The percentage of people exposed to a bacteria who become ill is \(20 \%\). Assume that people are independent. Assume that 1000 people are exposed to the bacteria. Approximate each of the following: (a) The probability that more than 225 become ill (b) The probability that between 175 and 225 become ill (c) The value such that the probability that the number of people who become ill exceeds the value is 0.01

The sick-leave time of employees in a firm in a month is normally distributed with a mean of 100 hours and a standard deviation of 20 hours. (a) What is the probability that the sick-leave time for next month will be between 50 and 80 hours? (b) How much time should be budgeted for sick leave if the budgeted amount should be exceeded with a probability of only \(10 \% ?\)

The thickness of a laminated covering for a wood surface is normally distributed with a mean of 5 millimeters and a standard deviation of 0.2 millimeter. (a) What is the probability that a covering thickness is greater than 5.5 millimeters? (b) If the specifications require the thickness to be between 4.5 and 5.5 millimeters, what proportion of coverings do not meet specifications?

Without an automated irrigation system, the height of plants two weeks after germination is normally distributed with a mean of 2.5 centimeters and a standard deviation of 0.5 centimeter. (a) What is the probability that a plant's height is greater than 2.25 centimeters? (b) What is the probability that a plant's height is between 2.0 and 3.0 centimeters? (c) What height is exceeded by \(90 \%\) of the plants?

The probability density function of the time it takes a hematology cell counter to complete a test on a blood sample is \(f(x)=0.04\) for \(50

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.