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A total of 46 percent of the voters in a certain city classify themselves as Independents, whereas 30 percent classify themselves as Liberals and 24 percent say that they are Conservatives. In a recent local election, 35 percent of the Independents, 62 percent of the Liberals, and 58 percent of the Conservatives voted. A voter is chosen at random. Given that this person voted in the local election, what is the probability that he or she is

(a) an Independent?

(b) a Liberal?

(c) a Conservative?

(d) What percent of voters participated in the local election?

Short Answer

Expert verified

a. 0.3311

b. 0.3825

c. 0.2863

d.24.32%

Step by step solution

01

Given information

The total voters identify as independent is46%and independents voted in the election35%.

The voters identify as liberals30%and liberals voted in the election 62%.

The voters identify as conservatives24%and conservatives voted in the election58%.

A voter is chosen at random

02

Formula used

Probability of an event=Number of favorable outcomesNumber of total outcomes

03

Calculation of solution (Part a)

Assume, the total number of people be x.

Number of people who identify as independent =0.46x

Total number of voters=(0.46×0.35x)+(0.3×0.62x)+(0.24×0.58x)=0.4862x

Number of independent voters =0.35×0.46x=0.161x

Probability that a voter selected at random is an independent voter=0.161x0.4862x=8052431=0.3311

04

Calculation of solution (Part b)

Number of people who identify as liberal=0.30x

Number of liberal voters=0.62×0.30x=0.186x

Probability that a voter selected at random is a liberal voter=0.186x0.4862x=9302431=0.3825

05

Calculation of solution (Part c)

Number of people who identify as conservative=0.24x

Number of conservative voters=0.58×0.24x=0.1392x

Probability that a voter selected at random is a conservative voter=0.1392x0.4862x=6962431=0.2863

06

Calculation of solution (Part d)

Total number of voters who participated in the election=0.2432x

Percentage of voters who participated in the election=0.2432xx×100=24.32%

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