91影视

Consider the binary tree T=(V,E) with the root node. A binary tree must have at most two children for every parent node.

Consider the binary tree T=(V,E)with the designated root node. Array x{.} with a value for each each node in V is given.

Create new array z{.} for each $u鈭�V$,

z{u}= the maximum of the x -values associated with u鈥檚 descendants.

Considering the given information, a linear-time algorithm is as follows.

Input: BinaryTree T=(V,E)

Output: z{.} for each $u鈭�V$

Initialize z{i} to 0,

Begin procedure DFS()

While traversal

if node pops out of the stack

update the z value of the node u at the top of the stack

z{u}=max(z{u},x{v}

return z{u}

The above algorithm initializes the z array, and performs the depth first search. During traversal , if the node pops out of the stack , update the z value of the node u. This algorithm runs in linear time.

Therefore, a linear-time algorithm that calculates the entire z-array has been provided.