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Chapter 0: Q17P (page 1)

How many milliliters of 2.15% alcoholic dimethylglyoxime should be used to provide a 50.0% excess for Reaction 27-7 with 0.998 4 g of steel containing 2.07 wt% Ni? Assume that the density of the dimethylglyoxime solution is 0.790 g/mL.

Short Answer

Expert verified

The value of volume of DGM of 2.15% is V=7.22 mL

Step by step solution

01

Find mass of solution for 0.1277g:

Calculate m(Ni) and n,

$m (Ni) = wt % 脳 0.9984 g m (Ni) = 0.0207 脳 0.9984 g)$

$m (Ni) = 0.02067 g n (Ni) = m / M = 3.521 脳 10^{4} mol$

From this we can find m(DGM),

$m (DGM) = n 脳 M m (DGM) = 2 (3.521 脳 10^{- 4} mol) 脳 116.12 g / mol m (DGM) = 0.08177 g$

Calculate the 50% excess masss,

$excess = 1.5 脳 0.08177 g excess = 0.1227 g$

From this we can calculate the mass of solution,

$m (solution) = \frac{excess}{0.0215 g} m (solution) = 0.1227 g / 0.0215 g$

The mass of solution is $m (s o l u t i o n) = 5.705 g$

02

Calculate the volume of DGM of 2.15%:

$V = m / 蚁 V = 5.705 g / 0.790 g / m L$

The value of volume of DGM of 2.15% is $V = 7.22 mL$

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