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A reliable assay shows that the ATP (adenosine triphosphate) content of a certain cell type is. You developed a new assay, which gave the values117,119,111, 115, 120μmol/100mL(average = 116.4) for replicate analyses. Do your results agree with the known value at the 95%confidence level?

Short Answer

Expert verified

The 95% confidence interval does not include the accepted value of111μmol/100mL

Step by step solution

01

Definition of standard deviation and mean.

  • Arithmetic mean: By dividing the amount of measured values by the number of measurements , the arithmetic mean x¯is determined.

Mean:

  • Standard deviation: The standard deviation is a measurement of how tightly the data cluster around the mean.

The standard deviation (s) is given by the formula:

s=∑ixi-x¯2n-1

Standard deviation of the mean of sets of n values is:

σn=θn

02

Explanation.

The mean:

x¯=∑ixin=117+119+111+115+1205=116.4=116roundedoff

Standard deviation:

s=∑xi-x¯2n-1=116-1172+.....+116-12025-1=3.58=4roundedoff

95% Confidence interval:

The 95% confidence interval for four degrees of freedom is calculated as follows,

Confidence interval=x¯±tsn

=116.4±2.7763.585=116.4±4.4=116±4roundedoff=112.0

or 120.8 (digits in subscript denotes insignificant figures)

The 95% confidence interval does not include the accepted value of111μmol/100mL Hence, the difference is significant.

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Most popular questions from this chapter

What is the relation between the standard deviation and the precision of a procedure? What is the relation between standard deviation and accuracy?

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