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Should the value 216 be rejected from the set of results 192,216,202,195, and 204?

Short Answer

Expert verified

The value 216 should not be rejected but has to be retained in the given results.

Step by step solution

01

Grubbs Test for an Outlier

A datum that significantly differs from other observations is known as an outlier. The consideration or rejection of such a datum from the entire observation is found through the Grubbs test.

The Grubbs statistic G is mathematically presented as:

Gcalculated=∣questionablevalue-x∣s

Here,

xis the mean of entire data set.

s is the standard deviation of entire data set.

If Gcalculated>Gtable, then the questionable point should be discarded.

IfGcalculated>Gtable, then the questionable point should be retained.

02

Determine whether the value 216 can be rejected

Given data:

The given sets of results are 192, 216, 202, 195, and 204.

The questionable value is 216:

The mean of the given set of results is calculated as follows:

x=∑xiin=192+216+202+195+2045=10095=201.8

The Standard deviation is calculated as follows:

s=∑xi-x2in-1=201.8-1922+...........201.8-20425-1=9.34

The G value is calculated by using the Grubbs test as shown below:

Gcalculated=questionablevalue-xs=216-201.89.34=1.52

For five observations, the Gtablevalue is 1.672.

Compare the result and see that Gcalculated(1.52)<Gtable(1.672).

Hence, the questionable value should be retained.

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