/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q8P Deuterated triglycine sulfate (a... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Deuterated triglycine sulfate (abbreviated DTGS) is a common ferroelectric infrared detector material. Explain how it works.

Short Answer

Expert verified

Deuterated triglycine sulfate (DTGS) has a permanent electric polarization as a result of alignment of the molecules in the crystal. One part of the crystal is positively charged, while the opposite side is negative. The polarization is temperature dependent, so when the crystal absorbs infrared radiation, its temperature and polarization (voltage difference) change. The change in voltage is the detector pyroelectric signal.

Step by step solution

01

Step: 1 Definition of the deuterated triglycine sulfate (DTGS):

A deuterated triglycine sulfate (DTGS) mid-infrared spectrometer showing large and automatic signals of electrical polarization when the infrared beam incident affects its separation.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Describe the role of each component of the spectrophotometer.

The true absorbance of a sample is 1.000, but the mono chromator passes 1.0% stray light. Add the light coming through the sample to the stray light to find the apparent transmittance of the sample. Convert this answer back into absorbance and find the relative error in the calculated concentration of the sample.

Here is an extremely sensitive method for measuring nitrite () down to in natural waters. The water sample is treated with sulfanilamide and N-(1-naphthylethylenediamine) in acid solution to produce a colored product with a molar absorptivity of 4.5×104M-1cm-1at 540 nm. The colored solution is pumped into a 4.5-meter-long, coiled Teflon tube whose fluorocarbon wall has a refractive index of 1.29. The aqueous solution inside the tube has a refractive index near 1.33. The colored solution is pumped through the coiled tube. An optical fiber delivers white light into one end of the tube, and an optical fiber at the other end leads to a polychromator and detector.

(a) Explain the purpose of the coiled Teflon tube and explain how it functions.

(b) What is the critical angle of incidence for total internal reflection at the Teflon/water interface?

(c) What is the predicted absorbance of a1.0nM solution of colored reagent?

The prism shown here is used to totally reflect light at a90°angle. No surface of this prism is silvered. Use Snell's law to explain why total reflection occurs. What is the minimum refractive index of the prism for total reflection?

(a) In the cavity ring-down measurement at the opening of this chapter, absorbance is given by A=Lcln10(1Ï„-1Ï„0)whereis the length of the triangular path in the cavity, Cis the speed of light, Tis the ring-down lifetime with sample in the cavity, and T0is the ring-down lifetime with no sample in the cavity. Ring-down lifetime is obtained by fitting the observed ring-down signal intensityto an exponential decay of the form l=l0e-²âÏ„, whereis the initial intensity and t is time. A measurement ofis made at a wavelength absorbed by the molecule. The ring-down lifetime for 21.0-cm-1 along empty cavity is 18.52μ²õand18.52μ²õfor a cavity containing.role="math" localid="1664865078479" CO2 Find the absorbance ofCO2at this wavelength.

(b) The ring-down spectrum below arises from CH413and CH412from 1.9ppm(vol/yol)of methane in outdoor air at 0.13. The spectrum arises from individual rotational transitions of the ground vibrational state to a second excited C-H)vibrational state of the molecule. (i) Explain what quantity is plotted on the ordinate ( Y-axis). (ii) The peak forCH412is at6046.9546cm-1. What is the wavelength of this peak in? What is the name of the spectral region where this peak is found?

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.