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Consider a reflection grating operating with an incident angle of 408 in Figure 20-7. (a) How many lines per centimeter should be etched in the grating if the first-order diffraction angle for 600 nm (visible) light is to be 2308? (b) Answer the same question for 1 000 cm21 (infrared) light.

Short Answer

Expert verified

(a)d=2.38.103lines/cmb)d=142.86lines/cm

Step by step solution

01

Step: 1 Define the reflection grating:

The light grating has ridges or rulings in its place while the transmission grating has transfer or empty holes in its place.

02

Step: 2 Grating equation:

(a)

n.λ=dsinθ+sinϕ

D is:

d=n.λsinθ+sinϕd=1.600.10-9msin40°+sin-30°d=4.2.10-6m

Or

d=14.2.10-4cmd=2.38.103lines/cm

03

Step: 3 The wavelength:

(b)

λ=11000cm-1λ=1.10-3cm

D is:

d=n.λsinθ+sinϕd=1.1.10-3cmsin40°+sin-30°d=7.10-3m

Or

d=17.10-3cmd=142.86lines/cm

The solution is (a)d=2.38.103lines/cmb)d=142.86lines/cm

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