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A measurement with a signal-to-noise ratio of 100 / 1 can be thought of as a signal, S, with 1 % uncertainty, e. That is, the measurement isS±e=100±1.

(a) Use the rules for propagation of uncertainty to show that, if you add two such signals, the result is total signal=200±√2 , giving a signal-to-noise ratio of200/√2=141/1 .

(b) Show that if you add four such measurements, the signal-tonoise ratio increases to 200 / 1.

(c) Show that averaging n measurements increases the signal-to-noise ratio by a factor ofn compared with the value for one measurement.

Short Answer

Expert verified

(a) The principles for uncertainty propagation are followed, and the result is a total signal 2

(b) Four measurements had a signal-to-noise ratio of 400: 2=200: 1.

(c)n times higher than the initial signal/noise ratio.

Step by step solution

01

Definition of signal to noise

  • The signal-to-noise ratio (SNR) is calculated by dividing the mean value of a signal (S) by the background standard deviation (N).
  • When S/N falls below 2 or 3, the signal becomes impossible to see.
02

Determine the signal to noise ratio

(a)

When it combine two of these signals, it get:

100±1+100±1-200±√2

where the uncertainty is determined:

e=e12+e22e=12+12=2

The signal-to-noise ratio is calculated as follows:

2002=1411

03

Determine the singal to noise ratio increase by 200/1

(b)

When four of these measurements are added together, it get:

100±1+100±1+100±1+100±1-400±2

where there is uncertainty:

e=e12+e22+e32+e42e=12+12+12+12=2

The signal-to-noise ratio is calculated as follows:

4002=2001

04

Determine the signal-to-noise ratio by a factor of n compared with the value for one measurement.

(c)

The signal to noise ratio of the initial measurement is:

1001

As a result, the average signal is as follows:

role="math" localid="1663653596294" n×100n×100

The average amount of noise is:

nn=1n

The average signal to average noise ratio is:

100n=100×n

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