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In formaldehyde, the transition n→π*(T1)occurs at 397 nm,and the n→π*(S1)transition comes at 355 nm. What is the difference in energy (kJ/mol) between the S1andT1states? This difference is due to the different electron spins in the two states.

Short Answer

Expert verified

The difference is due to the different electron spins in the two states is 36kJ/mol

Step by step solution

01

Define Luminescence:

Luminescenceis the sudden release of light by a substance not produced by heat; Or "cold light". It is therefore a form of cold-body radiation. It can be caused by chemical reactions, electrical energy, subatomic motions or pressure on the crystal.

02

Find n→π*(T1) energy:

E=h.v=h.cλE=6.626.10-34Js..3.108m/s2397.109mE=5.1019JConverttokJ/molE=5.10-19.10-3kJ/molE=301kJ/mol

03

 Find n→πa˙(S1) energy:

E=h.v=h.cλE=6.626.1034Js.3.108m/s2355.10-9mE=5.6.10-19JConverttokJ/molE=5.6.10-19.10-3kJ.6.022.1023mol-1E=337kJ/mol

04

Find difference between electron spins:

(337 - 301)kJ/mol = 36kJ/mol

The difference is due to the different electron spins in the two states is 36kJ/mol

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Most popular questions from this chapter

Semi-xylenol orange is a yellow compound at pH 5.9but turns red when it reacts with Pb2+. A 2.025 - mLsample of semixylenol orange at pH 5.9was titrated with7.515×10-4MPb(NO3)2with the following results:

Total role="math" localid="1663647483742" μ³¢Pb2+added

Absorbance at 490nmwavelength

Total μ³¢Pb2+added

Absorbance at490nmwavelength

0.0

6.0

12.0

18.0

24.0

30.0

36.0

0.227

0.256

0.286

0.316

0.345

0.370

0.399

42.0

48.0

54.0

60.0

70.0

80.0


0.425

0.445

0.448

0.449

0.450

0.447


Make a graph of absorbance versus microliters of Pb2+added. Be sure to correct the absorbances for dilution. Corrected absorbance is what would be observed if the volume were not changed from its initial value of 2.025Ml. Assuming that the reaction of semi orange with Pb2+has a 1 : 1stoichiometry, find the molarity of semi-xylenol orange in the original solution.

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