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Chapter 18: Q1TY (page 460)

What is the wavelength, wavenumber, and name of radiation with an energy of 100 kJ/mol?

Short Answer

Expert verified

The wavelength is $1.20 渭尘$

The wavenumber is $0.83 {渭尘}^{- 1}$

The name of radiation is Infrared radiation.

Step by step solution

01

Expression:

The expression for energy is $E = \frac{hc}{位}$

Rewrite the expression for $位$ :

$位 = \frac{hc}{E}$

The expression for wavenumber isrole="math" localid="1663647990022" $\overset{炉}{谓} = \frac{1}{位}$

02

Calculate wavelength:

Consider

$h = 6.626 脳 10^{- 34} J 鈰� s c = 2.998 脳 10^{8} m / s E = 100 kJ / mol$

Substitute in equation for wavelength,

$位 = \frac{hc}{E}$

$\frac{位 = (6.626 脳 10^{- 34} J 鈰� s) (2.998 脳 10^{8} m / s) (6.626 脳 10^{23} molecules / mol)}{100 kJ / mol \frac{(10^{3} J)}{1 kJ}}$

$鈮� (1.20 脳 10^{- 6} m) (\frac{10^{6} 渭尘}{1 m}) = 1.20 渭尘$

The wavelength is $1.20 渭尘$

03

Calculate wavenumber:

$\overset{炉}{谓} = \frac{1}{位}$

Substitute $位 = 1.20 渭尘$ ,

$\overset{炉}{谓} = \frac{1}{1.20 渭尘} 鈮� 0.83 {渭尘}^{- 1}$

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Most popular questions from this chapter

Vapor at a pressure of $30.3 渭迟$ bar from the solid compound pyrazine had a transmittance of 24.4% at a wavelength of 266nm in

a 3.00 - cm cell at 298K

Pyrazine

(a) Convert transmittance to absorbance.

(b) Convert pressure to concentration (mol/L) with the ideal gas law (Problem 1-18).

(c) Find the molar absorptivity of gaseous pyrazine at 266nm.

Gold nanoparticles (Figure 17-31) can be titrated with the oxidizing agent TCNQ in the presence of excess of ${Br}_{2}^{-}$ to oxidize $Au (0) " to {AuBr}_{2}^{-}$ in deaerated toluene. Gold atoms in the interior of the particle are Au(0) . Gold atoms bound to $C_{12} H_{25} S$ - (dodecanethiol) ligands on the surface of the particle are Au(I) and are not titrated.

The table gives the absorbance at $856 0.700 mL of $1.00 脳 10^{- 4} MTCNQ + 0.05 M (C_{8} H_{1} 7)_{4} N^{+} {Br}^{-}$ in toluene is titrated with gold nanoparticles (1.43 g/Lin toluene) from a microsyringe with a Teflon-coated needle. Absorbance in the table has already been corrected for dilution.

(a) Make a graph of absorbance versus volume of titrant and estimate the equivalence point. Calculate the Au(0) in 1.00 g of nanoparticles.

(b) From other analyses of similarly prepared nanoparticles, it is estimated that 25 % of the mass of the particle is dodecanethiol ligand. Calculate mmol of localid="1667559229564" $C_{12} H_{25} S$ in 1.00 g of nanoparticles.

(c) The Au(I) content of 1.00 g of nanoparticles should be 1.00 mass of Au(0) - mass of $C_{12} H_{25} S$ . Calculate the micromoles of Au(I) in 1.00 g of nanoparticles and the mole ratio Au(I) :. In principle, this ratio should be 1: 1. The difference is most likely because $C_{12} H_{25} S$ was not measured for this specific nanoparticle preparation.

In formaldehyde, the transition $n 鈫� 蟺 * (T_{1})$ occurs at 397 nm,and the $n 鈫� 蟺 * (S_{1})$ transition comes at 355 nm. What is the difference in energy (kJ/mol) between the $S_{1}$ and $T_{1}$ states? This difference is due to the different electron spins in the two states.

Describe a different set of dilutions to produce 3 mg Fe/mL from 1 000 mg

Fe/mL

Dilution by mass is more accurate than dilution by volume. A stocksolution contains 1.044 g Fe/kg solution in 0.48 M HCl. How many $渭驳贵别 / g$ solution are in a solution made by mixing 2.145 g stock solution with 243.27 g 0.1 M HCl?

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