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Dilution by mass is more accurate than dilution by volume. A stocksolution contains 1.044 g Fe/kg solution in 0.48 M HCl. How many μ²µ¹ó±ð/gsolution are in a solution made by mixing 2.145 g stock solution with 243.27 g 0.1 M HCl?

Short Answer

Expert verified

The amount ofμ²µ¹ó±ð/gis9.125μ²µ¹ó±ð/g

Step by step solution

01

Calculate the Mass:

AmountFe(μ²µ/g)=MassofFeMassofsolution.......(1)

Equation for mass of solution,

Mass of solution = Mass of stock solution + Mass of HCL

Given,

Mass of stock solution =2.145 g

Mass of HCL=243.27 g

Mass of solution =2.145gn+243.27g

Massofsolution=245.415g

Mass of Fe in stock solution = (Mass of Fe per kg solution)(Mass of stock solution)

Mass of Fe in stock solution = 1.044g1kg1kg103g

Mass of Fe in stock solution =0.00223938g

Substitute in equation (1),

02

STEP:2 :  Calculate  the amount of iron (Fe)

AmountofFe(μ²µ/g)=MassofFeMassofsolution

role="math" localid="1663669292492" AmountofFe(μ²µ/g)=0.00223938245.415g1061gAmountofFe(μ²µ/g)≈9.125μ²µ/g

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