Q8P-d Consider the titration of 25.0 m... [FREE SOLUTION]

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Chapter 12: Q8P-d (page 283)

Consider the titration of 25.0 mL of 0.020 0 M MnSO₄ with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn²⁺ at the following volumes of added EDTA and sketch the titration curve:
(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL
(h) 55.0 mL (i) 60.0 mL

Short Answer

Expert verified

(d) For 49 mL the value ofpMn²⁺is 3.87.

Step by step solution

Introduction

Equations and data obtained in order to proceed for calculation are as follows

$\begin{matrix} T i t r a t i o n 鈥夆赌� Re a c t i o n : 鈥� M n^{2 +} + E D T A 鈬� M n Y^{2 鈭�} \\ K_{f} = 10^{13.89} \\ A t 鈥夆赌夆€� p H 鈥夆赌夆€� 8 鈥夆赌� 伪_{Y^{4 鈭�}} = 4.2 脳 10^{鈭� 3} 鈥� (T a b l e 鈥� 12 鈭� 1) \end{matrix}$

Determine equilibrium constant

$\begin{matrix} K_{f}^{'} = 伪_{Y^{4 鈭�}} 脳 K_{f} \\ = 4.2 脳 10^{鈭� 3} 脳 10^{13.89} \\ = 3.3 脳 10^{11} \end{matrix}$

Equivalence point=50 mL

Determine the value of pMn2+

The concentration of the remaining productcan be calculated using the following equation

=Fraction remaining 脳 Initial concentration 脳 Dilution factor

If 49 mL solution is added then the reaction will be 49/50 completed as the equivalence point is at 50 mL. Then the metal (Mn) concentration will be

$\begin{matrix} [M n^{2 +}] = (\frac{50 鈭� 49}{50}) (0.02 鈥� M) (\frac{25}{25 + 49}) \\ = 1.35 脳 10^{鈭� 4} 鈥� M \end{matrix}$

Therefore, the value of pMn²⁺

^{$\begin{matrix} p M n^{2 +} = 鈭� \log (M n^{2 +}) \\ = 鈭� \log (1.35 脳 10^{鈭� 4}) \\ = 3.87 \end{matrix}$}

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Short Answer

Step by step solution

Introduction

Determine equilibrium constant

Determine the value of pMn2+

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91影视

Consider the titration of 25.0 mL of 0.020 0 M MnSO4 with 0.010 0 M EDTA in a solution buffered to pH 8.00. Calculate pMn2+ at the following volumes of added EDTA and sketch the titration curve:(a) 0 mL (b) 20.0 mL (c) 40.0 mL (d) 49.0 mL (e) 49.9 mL (f) 50.0 mL (g) 50.1 mL(h) 55.0 mL (i) 60.0 mL

Short Answer

Step by step solution

Introduction

Determine equilibrium constant

Determine the value of pMn2+

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Chemistry Textbooks

Chemistry Branches

Making Measurements

Ionic and Molecular Compounds

Physical Chemistry

Inorganic Chemistry

Chemical Reactions

Study anywhere. Anytime. Across all devices.