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Suppose that the electroosmotic mobility of a solution is +1.61×10-7m2/(V×s)) How many plates are required to separate sulfate from bromide with a resolution of 2.0? Use Table 15-1 for mobilities and Equation 26-14 for resolution.

Short Answer

Expert verified

Plates that are required to separate sulfate from bromide with a resolution of 2.0 isN=2×510plates

Step by step solution

01

Plates that are required to separate sulfate from bromide with a resolution of 2.0

From Table 15-1 we will use the following:

μepSO42-=-8.27×10-8m/Vsμapp=μeo=μepμapp=16.1×10-8+-8.27×10-8aμapp=7.83×10-8m2/VsμepBr-=-8.13×10-8m2/Vsμapp=μeo=μepμapp=16.1×10-8+-8.13×10-8μapp=7.97×10-8m2/Vs

02

Step 2:Calculate the average

Nextwewillcalculatetheaverageμand∆μep

μav=7.83×10-8+7.97×10-82μav=7.90×10-8m2/Vs∆μep=8.27×10-8-8.13×10-8∆μep=0.14×10-8m2/Vs

03

Step 3:Equation 26-14 for resolution

Then we will use the Equation 26-14 for resolution:

N=4×Resolutionμav∆μep2N=4×2.07.900.142N=2×105plates

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