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The migration time for Cl-in a capillary zone electrophoresis experiment is 17.12 min and the migration time for l-is 17.78 min. From mobilities in Table 15-1, predict the migration time of Br(The observed value is 19.6 min.)

Short Answer

Expert verified

Expressions for Cl-and l-isμapp=LtE

The migration time is calculated as x=20.5min

Step by step solution

01

Step 1:Expressions forCl-andl-using the following equations

We need to write the expressions for Cl-and l-using the following equations

t=Lμnet=LμappEμapp=LtE

Where t is migration time,L is length,E is electric field and is speed.

forCl-μapp=L17.2El-μapp=L17.78E

02

Step 2:Difference in mobilities

Next we write the difference in mobilities

∆μappl-Cl=L17.2E-L17.78EfromTable15-lwecanseethatl-Cl=0.05×10-8m2/Vs

03

Step 3:Difference in mobilities for  and 

ThenwewillwritethedifferenceinmobilitiesforBr-andCl-:

∆μappBr-Cl=L17.2E-LxE

fromTable15-lwecanseethatBr-Cl=0.22×10-8m2/Vs

04

Step 4:Calculate the migration time

Using step 2 and step 3 calculating the migration time

∆μappBr-Cl∆μl-Cl=0.220.054.4=L17.2E-LxEL17.2E-L17.78Ex=20.5min

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Most popular questions from this chapter

26-D. Consider a capillary electrophoresis experiment conducted near pH9, at which the electroosmotic flow is stronger than the electrophoretic flow.

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