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A solution contains 0.010MBa2+and 0.010MAg2. Can 99.90% of either ion be precipitated by chromate CrO42-without precipitating the other metal ion?

Short Answer

Expert verified

Neither Ba2+norAg+can be precipitated without precipitating other metal ion.

Step by step solution

01

Chromate Precipitate.

BaCrO4s⇌Ba2++CrO42-Ksp=2.1×10-10Ag2CrO4(s)⇌2Ag++CrO42-Ksp=1.2×10-12

Since, the stoichiometry of the two salts are not same, lower Kspvalue does not indicate faster precipitation.

Suppose 99.99% of BaCrO4is precipitated, then the final concentration of Ba+2ions will be 0.1100×0.01=1.0×10-5M

Therefore, concentration of chromate ion present in solution :

Ksp=Ba2+CrO42-2.1×10-10=1.0×10-5×CrO42-CrO42-=2.1×10-101.0×10-5=2.1×10-5

02

Reaction Quotient for Ag2CrO4 .

Q=Ag+CrO42-=0.01022.1×10-5=2.1×10-9

Since, Q>Kspfor Ag2CrO4,Ag+should precipitate.

Therefore, it is not possible to separate both the salts by precipitation.

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