/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q1TY For the reaction Li++H2O⇌Li(OH... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

For the reaction Li++H2O⇌Li(OH)(aq)+H+,KLi=2.3×10-14. Combine this reaction with the reaction to find the equilibrium constant for the reaction Li++OH-⇌Li(OH)(aq).

Short Answer

Expert verified

The equilibrium constant (K) for the reaction of Li++OH-⇌Li(OH)aq was calculated as 2.3.

Step by step solution

01

Define the formula for Kb.

The value of can be calculated as:

Kb=BH+OHB

Where Kbis called a base dissociation constant.

The value of Kwis calculated by the formula:

KW=Ka×Kb

02

Find the equilibrium constant.

Given:

KLi=2.3×10-14MKw=[H+][OH-]Kw=1.0×10-14

Now the equilibrium constant for the given reaction:

H+OH-H2OK=1/Kw=1/1.0×10-14Li++H2OLiOHaq+H+KLi=2.3×10-14Li++OH-LiOHaqK=1/Kw.KLi

K=11.0×10-14×2.3×10-14=2.3

Thus, the equilibrium constant (K) for the reaction of Li++OH-⇌Li(OH)aqwas calculated to be 2.3.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

BaCl2?H2O(s)loses water when it is heated in an oven:

BaCl2⋅H2O(s)⇌BaCl2(s)+H2O(g)

Δ±á°=63.11kJ/molat25°C

Δ³§Â°=+148J/(Kâ‹…mol)at25°C

a) Write the equilibrium constant for this reaction. Calculate the vapour pressure of gaseous H2O(PH2O) above BaCl2â‹…H2Oat 298K.

(b) If ∆H°and ∆S°are not temperature dependent (a poor assumption), estimate the temperature at which PH2O above BaCl2⋅H2O(s)will be 1 bar.

From the equations

HOCl"⇌H++OCl-K=3.0×10-8HOCl+OBr-⇌HOBr+OCl-K=15

find the value of K for the reactionHOBr⇌H++OBr-.

Given the following equilibria, calculate the concentration of

each zinc species in a solution saturated withZn(OH)2(s)and containing[OH-]

at a fixed concentration of3.2×1027M.

Zn(OH)2(s)Ksp=3×10-16Zn(OH)+β1=1×104Zn(OH)2(aq)β2=2×1010Zn(OH)3-β3=8×1013Zn(OH)42-β3=3×1015

For H2(g)+Br2(g)⇌2HBr(g),K=7.2×10-4at 1362Kand ∆H°is positive. A vessel is charged with 48.0PaHBr,1370PaH2, and3310PaBr2at1362K.

(a) Will the reaction proceed to the left or the right to reach equilibrium?

(b) Calculate the pressure (Pa) of each species at equilibrium.

(c) If the mixture at equilibrium is compressed to half of its original volume, will the reaction proceed to the left or the right to re-establish equilibrium?

(d) If the mixture at equilibrium is heated from 1362 to 1407K , will HBr be formed or consumed in order to re-establish equilibrium?

(a) A favorable entropy change occurs when ∆Sis positive. Does the order of the system increase or decrease when ∆Sis positive?

(b) A favorable enthalpy change occurs when ∆His negative. Does the system absorb heat or give off heat when ∆His negative?

(c) Write the relation between ∆G,∆Hand ∆S . Use the results of parts (a) and (b) to state whether ∆Gmust be positive or negative for a spontaneous change.

See all solutions

Recommended explanations on Chemistry Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.