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Given the following equilibria, calculate the concentration of

each zinc species in a solution saturated withZn(OH)2(s)and containing[OH-]

at a fixed concentration of3.21027M.

Zn(OH)2(s)Ksp=310-16Zn(OH)+1=1104Zn(OH)2(aq)2=21010Zn(OH)3-3=81013Zn(OH)42-3=31015

Short Answer

Expert verified

Zn2+=2.9310-3MZnOH+=910-6MZnOH2aq=610-6MZnOH3-=610-6MZnOH32-=910-14M

Step by step solution

01

Definition of solubility product.

For a sparingly soluble salt, the solubility product is the mathematical product of the concentration of its dissolved constituent ions raised up to the power of their stoichiometric coefficient.

MyXz(s)yMz+(aq)+zXy-(aq)Ksp=Mz+yXy-z

02

Definition of cumulative constants.

The cumulative constant for the reaction

M+nXMXn

Is defined as:

n=MXnMXn

03

Concentration of each Zn species in Zn(OH)2(s) .

Fixed concentration ofOH- in the solution=3.210-7M

Solubility product for Zn(OH)2(s)310-16

ZnOH2Zn+2+2OH-Ksp=Zn+2OH-2Zn+2=KspOH-=310-163.210-72=2.9310-3M

04

Concentration of each Zn species in  Zn(OH)+

Zn+2OH-1ZnOH+ZnOH+=1Zn2+OH-ZnOH+=11042.9310-33.210-7ZnOH+=910-6

05

Concentration of each Zn species in Zn(OH)2(aq)

Zn+2+2OH-2ZnOH2ZnOH2aq=2Zn2+OH-2ZnOH2=11042.9310-33.210-72ZnOH2=610-6

06

Concentration of each Zn species in Zn(OH)3-

Zn+2+3OH-3ZnOH3-ZnOH3-=3Zn2+OH-3ZnOH3-=11042.9310-33.210-73ZnOH3-=810-9

07

Concentration of each Zn species in Zn(OH)4-

Zn+2+4OH-4ZnOH4-2ZnOH4-2=4Zn2+OH-4ZnOH42=11042.9310-33.210-74ZnOH4-2=91014

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