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Find [Pb2+],PbI2(aq),and [PbI3-]in a saturated solution of PbI2(s)with [I-]=0.10M.

Short Answer

Expert verified

Theconcentrationof[Pb2+]is7.9×10-7MTheconcentrationof[PbI2aq]is1.1×10-5MTheconcentrationof[PbI3]is6.6×10-6M

Step by step solution

01

Define the solubility product

It is defined as the product of the dissolved ion concentration raised to the power of the stoichiometric coefficient.

MyXzs⇌KspMz+(aq)+zXy-(aq)Ksp=[Mz+]y[Xy-]z

The solubility product is very helpful in predicting whether a salt precipitates in a solution.

02

Find the concentration.

For the reaction:

PbI2(s)⇇Pb+2+2I-Ksp=7.9×10-9

Ksp=[Pb+2][I-]2

Pb2+=Ksp/I-2=7.9×10-9/0.102=7.9×10-7M

03

Find the concentration.

Pb2++2I-⇇β2PbI2β2=1.4×103[PbI2aq]=β2[Pb2+][I-]2

=1.1×10-5M

04

Find the concentration.

Pb2++3I-⇇β3PbI3-β3=8.3×103

Concentration of Pbl3-

Pbl3-=β3Pb2+l-3=6.6×10-6M

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