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Chapter 6: Q63P (page 283)

Draw curved arrows to show the flow of electrons responsible for the conversion of the following reactants into products.

Short Answer

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a) Here oxygen lone pair shifts to the carbon oxygen bond and form double bond then cleavage of OCH3and C bond takes place. CH3O- ion will release.

b) In this nucleophilic (nucleus loving) attack takes place. Nitrogen lone pair attacks on hydrogen and attract hydrogen towards itself and form NH3 and carboanion will form.

c) In this nucleophilic (nucleus loving) attack takes place. Oxygen lone pair attacks on carbon and form bond with it and Br-releases.

Step by step solution

01

Step 1: How the reaction proceed

a) Here oxygen lone pair shifts to the carbon oxygen bond and form double bond then cleavage of OCH3and C bond takes place. CH3O- ion will release.

b) In this nucleophilic (nucleus loving) attack takes place. Nitrogen lone pair attacks on hydrogen and attract hydrogen towards itself and form NH3 and carboanion will form.

c) In this nucleophilic (nucleus loving) attack takes place. Oxygen lone pair attacks on carbon and form bond with it and Br-releases.

02

Final answer

So the reaction proceed like this-

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Most popular questions from this chapter

What stereoisomers are obtained from the following reactions?

a. trans-2-butene + HBr

b. (Z)-3-methyl-2-pentene + HBr

c. (E)-3-methyl-2-pentene + HBr

d. cis-3-hexene + HBr

e. cis-2-pentene + Br2

f. 1-hexene + Br2

a. What is the major product obtained from the reaction of propene and Br2plus excess Cl-?

b. Indicate the relative amounts of the stereoisomers that are obtained.

When 3-methyl-1-butene reacts with HBr, two alkyl halides are formed: 2-bromo-3-methylbutane and 2-bromo-2-methylbutane. Propose a mechanism that explains the formation of these two products.

What reagents are needed to carry out the following syntheses?

Why are Na+ and K+ unable to form covalent bonds?
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